similar to: help with eval

Dear mailing list, I have found some strange behaviour which I think relates to parent frames and eval. Can anyone explain what's going on here? First example: > test.parent.funcs_ function() { outer.var_ 5 subfunc1_ function() substitute( outer.var, envir=parent.frame()) print( subfunc1()) subfunc2b_ function() eval( quote( outer.var), envir=parent.frame()) print(

Sorry to intervene. Argument passed to 'eval' is evaluated first. So, eval(x <- 2) is effectively like { x <- 2; eval(2) } , which is effectively { x <- 2; 2 } . The result is visible. eval(expression(x <- 2)) or eval(quote(x <- 2)) or evalq(x <- 2) gives the same effect as x <- 2 . The result is invisible. In function 'eval2', res <-

On Jul 15, 2015, at 12:51 PM, William Dunlap wrote: > I think rapply() was changed to act like lapply() in this respect. > When I looked at the source of the difference, it was that typeof() returned 'language' in 3.2.1, while it returned 'list' in the earlier version of R. The first check in rapply's code in both version was: if (typeof(object) != "list")

David, If you are referring to the solution that would be: rapply(list(test), eval, envir = fenv) I thought I explained in the question that the above code does not work. It does not throw an error, but the behavior is no different (at least in the output or result). Using the above code still results in the x object not being stored in fenv on 3.1.2. Dayne On Wed, Jul 15, 2015 at 4:40 PM,

I ran into an interesting issue with `evalq` (and also `eval(quote(...))`): ???? f <- function() { ?????? list( ???????? sys.parent(1), ???????? evalq(sys.parent(1)), ???????? evalq((function() sys.parent(2))()),? # add an anon fun layer ???????? evalq((function() sys.parent(1))()) ?????? ) ???? } ???? res <- f() ???? str(res) ???? ## List of 4 ???? ##? $ : int 0???????? # sys.parent(1)

In 3.1.2 eval does not store the result of the bquote-generated call in the given environment. Interestingly, in 3.2.1 eval does store the result of the bquote-generated call in the given environment. In other words if I run the given example with eval rather than evalq, on 3.1.2 "x" is never stored in "fenv," but it is when I run the same code on 3.2.1. However, the given

Hello, I upgraded from 3.1.2 to 3.2.1 and am receiving errors on code that worked as I intended previously. Briefly, I am using bquote to generate expressions to modify data.table objects within a function, so I need the changes to actually be stored in the given environment. Previously, I used code like the following: test <- list(bquote(x <- 10)) fenv <- environment() rapply(test,

Hi R-listers, I am trying to better undertand what we would call "functional paradigm" use of S/R to better map my programming activities in other languages. This little function is aimed to create an object (at the end end, it would have it's own class): -- myObject =function(){ list( a=1, foo=function(b) { cat("b:",b)

Hi, I've just created: newEnvEval <- function(..., hash=FALSE, parent=parent.frame(), size=29L) { envir <- new.env(hash=hash, parent=parent, size=size); evalq(..., envir=envir); envir; } # newEnvEval() so that I can create an environment and assign objects to it in one go, e.g. env <- newEnvEval({ a <- 1; b <- 2; }); print(env$a); Does this already exists somewhere?

Some formula methods for S3 generic functions use the idiom returnValue$call <- sys.call(sys.parent()) to show how to recreate the returned object or to use as a label on a plot. It is often followed by returnValue$call[[1]] <- quote(myName) E.g., I see it in packages "latticeExtra" and "leaps", and I suspect it used in "lattice" as well. This idiom

The help page of eval says: The 'evalq' form is equivalent to 'eval(quote(expr), ...)'. But the following is not equivalent. Can anyone give me some explaination? Thanks very much. > f1 <- function(x,digits=5) lapply(x, f2) > f2 <- function(x) eval(quote(print(x+1,digits=digits)),list(x=x),parent.frame(2)) > f1(list(x1=1)) [1] 2 $x1 [1] 2 > > f1 <-

On Mon, Jan 26, 2015 at 12:24 PM, Hadley Wickham <h.wickham at gmail.com> wrote: > If it was any other environment than the global, you could use substitute: > > e <- new.env() > delayedAssign("foo", stop("Hey!"), assign.env = e) > substitute(foo, e) > > delayedAssign("foo", stop("Hey!")) > substitute(foo) Hmm... interesting

Is this a bug, or have I misunderstood the proper use of lm? Thanks, Whit code: x <- rnorm(50) y <- matrix(as.logical(round(runif(100),0)),ncol=2) NROW(x)==NROW(y) lm(x~y) > x <- rnorm(50) > y <- matrix(as.logical(round(runif(100),0)),ncol=2) > NROW(x)==NROW(y) [1] TRUE > lm(x~y) Error in "[[<-.data.frame"(`*tmp*`, nn, value = c(2, 1, 2, 1, 1, 1, 2, :

/*author:csf178-Re5JQEeQqe8AvxtiuMwx3w@public.gmane.org*/ function Class(Initalizer,SuperClasses) { if(!SuperClasses)SuperClasses=[]; var ret=function(){ for(var i=0;i<SuperClasses.length;i++) { SuperClasses[i].call(this); } var $private={}; var $public=this; var $static=ret; with($static){ with($private){ with($public){

I must admit I'm a little ashamed to have been using R for so long, and still lack a sound understanding of deferred calls, eval, deparse, substitute, and friends. I'm attempting to make a deferred call to a function which has default arguments in the following way: call.foo <- function(f) { x <- f() } x <- 1:10 f <- function(x=x) { x^2 } call.foo(f) However, I'm

If I want to use with inside a loop, it seems that next gets confused. To reproduce: for(lst in list(list(a = 1), list(a = 2), list(a = 3))) { with(lst, if(a == 2) next else print(a)) } I expect 1 and 3 to be printed, but I see [1] 1 Error in eval(expr, envir, enclos) : no loop for break/next, jumping to top level Is this a) by design, or b) a bug, or c) a thing that is rare enough that I

for the moment, I'm using: .onAttach <- function(libname, pkgname) { .bbg.db.conn <<- dbConnect(dbDriver("PostgreSQL"), user="blah","blah") } .onUnload <- function(libpath) { dbDisconnect(.bbg.db.conn) } which results in a hidden global variable in the global environment. I would prefer to make the assignment only in the package namespace.

Given > D = data.frame(o=gl(2,1,4)) this works as I expected: > evalq(o, D) [1] 1 2 1 2 Levels: 1 2 but neither of these does: > f <- function(x, dat) evalq(x, dat) > f(o, D) Error in eval(expr, envir, enclos) : object "o" not found > g <- function(x, dat) eval(x, dat) > g(o, D) Error in eval(x, dat) : object "o" not found What am I doing wrong?

I maintain the package affylmGUI. It works when installed on many previous versions of R. I have today tested exactly the same code under R-2.15.3, R-3.0.2, R-3.1.0, R-3.1.1, R-3.1.2 and R-devel. I have also tested the versions of affylmGUI downloaded by biocLite for each version of R and the same result applies. I have no errors under 2.15.3, 3.0.2, 3.1.0 and 3.1.1. The following error

I've noticed the following oddity where capture.output() prevents eval() from evaluating an expression in the specified environment. I'm not sure if it is an undocumented feature or a bug. It caused me many hours of troubleshooting. By posting it here, it might save someone else from doing the same exercise. Start by defining foo() which evaluates an expression locally in a given