Displaying 20 results from an estimated 500 matches similar to: "Mixed Effect Model - Jackknife error estimate"
2011 Jan 31
4
Select rows with distinct values in a column and other conditions
My data frame looks like:
SightingID PA1 PA2 PlotID InOverlap Area1 2001 1 -99 392 Y 0.22 2002 1 -99 388 Y 0.253 2008 1 NA 104 N 0.344 2010 1 NA 71 N 0.185 2012 1 NA 61 N 0.166 2013 1 NA 61 N 0.227 2014 1 NA 62
2009 Apr 14
2
subset dataframe by rows using character vector?
Dear List,
I'm stuck on what seems like a simple indexing problem, I'd be very grateful to anyone willing to help me out.
I queried a dataframe which returns a character vector called "plot". I have another dataframe from which I want to subset or select only those rows that match "plot". I've tried subset, and also the "which" command.
plot
2009 Jul 29
4
- counting factor occurrences within a group: tapply()
Dear List,
I'm an [R] novice starting analysis of an ecological dataset containing the
basal areas of different tree species in a number of research plots.
Example data follow:
> Trees<-data.frame(SppID=as.factor(c(rep('QUEELL',2), rep('QUEALB',3),
'CORAME', 'ACENEG', 'TILAME')), BA=c(907.9, 1104.4, 113.0, 143.1, 452.3,
638.7, 791.7, 804.3),
2008 Dec 18
1
using jackknife in linear models
Hi R-experts,
I want to use the jackknife function from the bootstrap package onto a
linear model.
I can't figure out how to do that. The manual says the following:
# To jackknife functions of more complex data structures,
# write theta so that its argument x
# is the set of observation numbers
# and simply pass as data to jackknife the vector 1,2,..n.
# For example, to jackknife
#
2010 Nov 25
2
delete-d jackknife
Hi dear all,
Can aynone help me about delete-d jackknife
usually normal jackknife code for my data is:
n <- nrow(data)
y <- data$y
z <- data$z
theta.hat <- mean(y) / mean(z)
print (theta.hat)
theta.jack <- numeric(n)
for (i in 1:n)
theta.jack[i] <- mean(y[-i]) / mean(z[-i])
bias <- (n - 1) * (mean(theta.jack) - theta.hat)
print(bias)
but how i can apply delete-d jackknife
2006 Aug 25
1
Plot y ~ x under condition of variable a and b [Broadcast ]
It's the "|source" in your formula that tells lattice to separate them.
If you drop that, you'll get all points without S and P distinguished at
all. If you add a groups argument, you should get them presented with
different colors/symbols/etc. depending on your trellis settings (warning:
untested code):
par.plot(lnvol~lnden, groups =
2007 Mar 27
1
Jackknife estimates of predict.lda success rate
Dear all
I have used the lda and predict functions to classify a set of objects
of unknown origin. I would like to use a jackknife reclassification to
assess the degree to which the outcomes deviate from that expected by
chance. However, I can't find any function that allows me to do this.
Any suggestions of how to generate the jackknife reclassification to
assess classification accuracy?
2010 Nov 14
2
jackknife-after-bootstrap
Hi dear all,
Can someone help me about detection of outliers using jackknife after
bootstrap algorithm?
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2005 Nov 08
1
Poisson/negbin followed by jackknife
Folks,
Thanks for the help with the hier.part analysis. All the problems
stemmed from an import problem which was solved with file.chose().
Now that I have the variables that I'd like to use I need to run some
GLM models. I think I have that part under control but I'd like to use
a jackknife approach to model validation (I was using a hold out sample
but this seems to have fallen out
2004 Mar 02
0
Jackknife after bootstrap influence values in boot package?
Is there a routine in the boot package to get the jackknife-after-
bootstrap influence values? That is, the influence values of
a jackknife of the bootstrap estimates?
I can see how one would go about it from the jack.after.boot code, but that
routine only makes pretty pictures.
It wouldn't be hard to write, but I find it hard to believe this
isn't part of the package already.
Thanks
2012 Mar 04
0
Jackknife for a 2-sample dispersion test
Hi All,
I'm not able to figure out how to perform a Jackknife test for a 2-sample
dispersion test in R. Is there a built-in function to perform this or do we
have to take a step by step approach to calculate the test statistic?
Any help would be awesome.
Thanks!
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2007 Dec 31
0
Optimize jackknife code
Hi,
I have the following jackknife code which is much slower than my colleagues C code. Yet I like R very much and wonder how R experts would optimize this.
I think that the for (i in 1:N_B) part is bad because Rprof() said sum() is called very often but I have no idea how to optimize it.
#O <- read.table("foo.dat")$V1
O <- runif(100000);
k=100 # size of block to delete
2012 Nov 14
2
Jackknife in Logistic Regression
Dear R friends
I´m interested into apply a Jackknife analysis to in order to quantify the
uncertainty of my coefficients estimated by the logistic regression. I´m
using a glm(family=’binomial’) because my independent variable is in 0 - 1
format.
My dataset has 76000 obs, and I´m using 7 independent variables plus an
offset. The idea involves to split the data in let’s say 5 random subsets
and
2003 Apr 16
2
Jackknife and rpart
Hi,
First, thanks to those who helped me see my gross misunderstanding of
randomForest. I worked through a baging tutorial and now understand the
"many tree" approach. However, it is not what I want to do! My bagged
errors are accpetable but I need to use the actual tree and need a single
tree application.
I am using rpart for a classification tree but am interested in a more
unbaised
2008 Jul 19
1
wroung groupedData despite reading Bates and Pinheiro 3 times
Hi everyone. I am trying to add a formula to my data using the groupedData
function.
My experiment consists of randomized block design using fruits, vegetation
and time as factors. The idea is to see if fruits, vegetation and time
explain the abundance of mice. I am using tree density as a covariate.
So I tried to fit the following structure to my data.
>
2006 Apr 11
4
Bootstrap and Jackknife Bias using Survey Package
Dear R users,
I?m student of Master in Statistic and Data analysis, in New University of Lisbon. And now i?m writting my dissertation in variance estimation.So i?m using Survey Package to compute the principal estimators and theirs variances.
My data is from Incoming and Expendire Survey. This is stratified Multi-stage Survey care out by National Statistic Institute of Mozambique. My domain of
2006 Oct 24
1
Variance Component/ICC Confidence Intervals via Bootstrap or Jackknife
I'm using the lme function in nmle to estimate the variance components
of a fully nested two-level model:
Y_ijk = mu + a_i + b_j(i) + e_k(j(i))
lme computes estimates of the variances for a, b, and e, call them v_a,
v_b, and v_e, and I can use the intervals function to get confidence
intervals. My understanding is that these intervals are probably not
that robust plus I need intervals on the
2009 Apr 22
1
Gee with nested desgin
Dear all,
Is it possible to incorporate a nested design in GEE? I have
measurements on trees that where measured in two years. The trees are
nested in plots. Each plot contains 24 trees. The number of plots is 72.
Hence we would expect 2 * 24 * 72 = 3456 data points. A few are missing,
so we end up wih 3431 data points.
This is what I have tried until now.
#assuming independence between trees
2009 Jul 10
1
Degree of freedom in the linear mixed effect model using lme function in R
Hello,
I would appreciate if somebody could help me clear my mind about the below issues.
I have a factorial experiment to study the effects of Grazing and Fire on Forest biomass production. The experimental unit (to which the treatment combinations are applied) are PLOTs. The measures were made repeatedly for 13 years.
I am planning to use the linear mixed effect model function lme in R for this.
2011 Apr 19
1
How to Extract Information from SIMEX Output
Below is a SIMEX object that was generated with the "simex" function from the
"simex" package applied to a logistic regression fit. From this mountain of
information I would like to extract all of the values summarized in this
line:
.. ..$ variance.jackknife: num [1:5, 1:4] 1.684 1.144 0.85 0.624 0.519 ...
Can someone suggest how to go about doing this? I can extract the