similar to: Wilcoxon paired signed rank test and continuity correction

Displaying 20 results from an estimated 3000 matches similar to: "Wilcoxon paired signed rank test and continuity correction"

2005 Jan 25
2
Rd problems when converting DVI version
Hi Running R v2.0 on SuSe linux 8.2. I'm trying to build a package (which built perfectly on Windows...) on Linux, and I ran: R CMD check mypackage I got: * checking mypackage-maual.tex ... ERROR LaTeX errors when creating DVI version This typically indicates Rd problems OK, there are no problems with my Rd - I got 3 warnings but they were all expected, and the whole package builds find
2004 Nov 16
3
Simple plot() question
Hi First a simple question to do with plot(). How do I change the x-axis labels on a plot? For example, I am plotting each row of a matrix, and I want each row to be a line on my graph. Simple really. Eg: plot(sg[1,], type="l") When I do this, the x-axis is labelled 1:38, as I have 38 columns in my matrix. When I do: plot(sg[1,order(sg[1,])], type="l") Ideally I would
2005 Jan 05
0
AW: Replacing all NA values in a matrix
Replacing the NA?s with eg. 1 : > a 1 2 3 4 1 20 50 10 80 2 NA 19 NA 49 3 NA 32 NA 61 4 45 101 44 190 a[try(is.na(a)) == TRUE] <- 1 > a 1 2 3 4 1 20 50 10 80 2 1 19 1 49 3 1 32 1 61 4 45 101 44 190 I this can help you, Matthias > -----Urspr?ngliche Nachricht----- > Von: r-help-bounces at stat.math.ethz.ch > [mailto:r-help-bounces at
2004 Dec 10
4
cbind() and factors.
Hi I'm seeing some "odd" behaviour with cbind(). My code is: > cat <- read.table("cogs_category.txt", sep="\t", header=TRUE, quote=NULL, colClasses="character") > colnames(cat) [1] "Code" "Description" > is.factor(cat$Code) [1] FALSE > is.factor(cat$Description) [1] FALSE > is.factor(rainbow(nrow(cat))) [1]
2005 Jan 05
8
Replacing all NA values in a matrix
OK, dumb question, and it is probably in the docs somewhere, but after 12 months working with R and quite a while looking at the docs, I still don't know (or have forgotten) how to replace all NA values in a matrix at once with some other value. I can do it column by column using is.na(), but I can't figure out how to do it for the whole matrix. My apologies, I am ashamed ;-) Michael
2003 Jul 07
1
Xvfb and R
Hi I have recently installed and implemented Xvfb (X virtual frame buffer) so that I can create jpegs using R over CGI (SUSE Linux 8.1 and Apache 1.3). I have noticed that in order to do this, a file (Rplots.ps) is created in my cgi-bin directory everytime a cgi script is run. This could cause problems though as I have a multi-user system where it is possible that two different users will run
2003 Jul 03
1
General X11 Problems
Hi You may remember a while ago I was having problems with creating jpegs using R over CGI. I solved this on my LAPTOP (*grins*) by - executing "xhost +localhost" from the command line - putting "SetEnv DISPLAY=:0.0" in my httpd.conf (apache) And all worked well. Now I'm trying to move the whole system onto my shiny new server - and encountering yet more problems
2004 May 19
7
Help with hclust() and plot()
Hi When I use plot(hclust(dist..)...)...) etc to create a dendrogram of a hierarchial cluster analysis, I end up with a vertical tree. What do I need to do to get a horizontal tree? Also, my users are used to seeing trees who's leaves all "end" at the same place (eg. Like in minitab). Is this possible in R? Thanks Mick Michael Watson Head of Informatics Institute for Animal
2003 Jun 13
4
Using jpeg() function over cgi
Hi I have seen a few posts to this list regarding problems accessing the x11() device over cgi - namely, when trying to create a graphic using the jpeg() function, everything is fine from the command line but it won't work over cgi, producing the error: "Unable to open connection to X11 display" Has anyone actually solved this particular problem satisfactorily? Please reply
2008 Aug 05
1
Greek characters in plots
Hi I am running an R script that creates 100s of graphs, and I need to use the greek CAPITAL letter delta in the mtext() function. I got as far as expression(delta) but this gives me the lowercase version. Can anyone help? I'm using R 2.7 on Windows XP Mick Head of Informatics Institute for Animal Health Compton Berks RG20 7NN 01635 578411
2008 Aug 07
1
Mtext doesn't display characters in italic when I use a greek symbol
Following on from my previous mail! plot(1:10,1:10) mtext("title", side=3, adj=0, font=3, cex=1.5) This works as expected and puts the font in italics. tag <- "A)" suffix <- "genea::" plot(1:10,1:10) mtext(bquote(.(tag) ~ Delta * .(suffix)), side=3, adj=0, font=3, cex=1.5) Here, the font isn't in italics, it's normal. I presume this is some
2010 Jun 23
3
Wilcoxon signed rank test and its requirements
Hi all, I have a distribution, and take a sample of it. Then I compare that sample with the mean of the population like here in "Wilcoxon signed rank test with continuity correction": > wilcox.test(Sample,mu=mean(All), alt="two.sided") Wilcoxon signed rank test with continuity correction data: AlphaNoteOnsetDists V = 63855, p-value = 0.0002093 alternative hypothesis:
2006 Aug 25
1
exact Wilcoxon signed rank test with ties and the "no longer under development" exactRanksumTests package
Dear List, after updating the exactRanksumTests package I receive a warning that the package is not developed any further and that one should consider the coin package. I don't find the signed rank test in the coin package, only the Wilcoxon Mann Whitney U-Test. I only found a signed rank test in the stats package (wilcox.test) which is able to calculate the exact pvalues but unfortunately
2007 Jun 28
1
Wilcoxon Rank Sum Test.
Dear, I'm using R software to evaluate Wilcoxon Rank Sum Test and I' getting one Warning message as this: > C1dea_com [1] 1.000 0.345 0.200 0.208 0.508 0.480 0.545 0.563 0.451 0.683 0.380 0.913 1.000 0.506 > C1dea_sem [1] 1.000 0.665 0.284 0.394 0.509 0.721 0.545 0.898 0.744 0.683 0.382 0.913 1.000 0.970 > wilcox.test(C1dea_sem,C1dea_com, paired = TRUE, alternative =
2017 Aug 22
1
Wilcoxon signed-rank test
Hi, I am using wilcox.test function to test the difference between the means of two samples. The data points are paired, so I am using a paired test. There is one strange case. Sample A has a higher mean than a sample B. However, wilcox.test function says that sample B has a significantly higher "mean rank" than sample A. How is it possible? Here is the code (data file is attached):
2006 Sep 11
2
Wilcoxon Rank-Sum Test with Bonferroni's correction
Dear all, I am trying to run Wilcoxon Rank-Sum Test with Bonferroni's correction. I have two lists: l0, l1: mapply(function(x,y)wilcox.test(x,y)$p.value, l0, l1) How do I run Bonferroni's correction on mapply? Any help is much apperciated. Thanks, -Raj
2010 Nov 24
2
Wilcoxon Rank Sum in R with a multiple testing correction
Hi there, I'm a total newbie to R. I'd like to use a Wilcoxon Rank Sum test to compare two populations of values. Further, I'd like to do this simultaneously for 114 sets of values. The two populations are C and N. The different sets of values have arbitrary names (I'll call them a, b, c etc). The set-up is as follows: a b c d .... C 2 C 3 C 5 C 9 C 4
2003 Dec 01
2
wilcoxon-pratt signed rank test in R - drug-effiacy
Hi. I'm going to introduce the R-package for a group of medical doctors later this week and is a little confused about there use of a test named "willcoxon-pratt" for testing if the clinical and biochemical markers has decreased significantly after the use of some drugs for a group of patients. Looking into the R-functions I would in R recommand using a matched-pairs Wilcoxon
2011 Apr 12
2
The three routines in R that calculate the wilcoxon signed-rank test give different p-values.......which is correct?
I have a question concerning the Wilcoxon signed-rank test, and specifically, which R subroutine I should use for my particular dataset. There are three different commands in R (that I'm aware of) that calculate the Wilcoxon signed-rank test; wilcox.test, wilcox.exact, and wilcoxsign_test. When I run the three commands on the same dataset, I get different p-values. I'm hoping that
2010 Apr 05
3
A questionb about the Wilcoxon signed rank test
Hi guys,   I have two data sets of prices: endprice0, endprice1   I use the Wilcox test:   wilcox.test(endprice0, endprice1, paired = TRUE, alternative = "two.sided",  conf.int = T, conf.level = 0.9)   The result is with V = 1819, p-value = 0.8812.   Then I calculated the z-value of the test: z-value = -2.661263. The corresponding p-value is: p-value = 0.003892, which is different from