similar to: a R function for sort a data frame.

Displaying 20 results from an estimated 1000 matches similar to: "a R function for sort a data frame."

2007 Aug 02
2
Re : beamer error with R
Un texte encapsul? et encod? dans un jeu de caract?res inconnu a ?t? nettoy?... Nom : non disponible Url : https://stat.ethz.ch/pipermail/r-help/attachments/20070802/04c0f92e/attachment.pl
2005 Mar 19
4
How I calculate nCr with R ? (Como calculo nCr con R? )
En espa?ol (In Spanish) Necesito calcular la en numeros de combinaciones de n cosas tomando k al tiempo. Como hago eso en R ??? Yo escrib? mi propia funci?n pero pienso que de esa forma no es f?cil para mis estudiantes . He estado buscando en la ayuda y no he encontrado informaci?n sobre una funci?n que calcule eso directamente. Podr?an ayudarme In English (en Ingl?s ) I need calculate
2005 May 19
3
Drawing a circle
Hi. I need to draw a circle whit center (a,b) and radio r. So I use the R code below a<-1.975 # valore x del centro b<-1.215 # valores y del centro r<-1.46 # radio x1<-seq(a-r,a+r,by=0.01); #los valores de x yp<-sqrt(r^2-(x1-a)^2)+b; # los valores y a partir de la ra??z positiva yn<-(-1)*sqrt(r^2-(x1-a)^2)+b; # los valores y a partir de la ra??z negativa x<-c(x1,x1);
2005 Jul 01
1
Setting lattice boxplot's lines to black
Hi R users. I'm using the lattice library and I need a print version for my graphics. How Set I my boxplot's lines to black ???? tpl<-trellis.par.get("plot.line") tpl$col<-"black" trellis.par.set("plot.line", tpl) Don't work. Boxplot's lines aren't black. Thanks a lot. This is my script. library(lattice) # I set background's
2006 Dec 05
1
publicar tutorial en CRAN
Hola, a todos los usuarios de R. Me gustar?a saber que pasos hay que seguir para que un manual o tutorial acerca de R escrito por un usuario quede disponible en CRAN. Escrib? un tutorial de Sweave en espa?ol y quiero colocarlo a disposici?n de los usuarios de R pero no se cuales son los pasos a seguir, a quien hay que dirigirlo y que requisitos se requieren para eso.
2002 Oct 24
3
model.matrix (via predict) (PR#2206)
Full_Name: Glenn Stone Version: 1.5.1 and 1.6.0 OS: win2000 Submission from: (NULL) (168.140.227.9) The following code produces incorrect fitted values in version 1.5.1 and an error in 1.6.0 Error in "contrasts<-"(*tmp*, value = "contr.treatment") : contrasts apply only to factors In addition: Warning message: variable ihalf is not a factor in:
2009 Jul 12
1
Booting problem with memdisk + Thinkpad + USB
Hi, I encountered a booting problem with memdisk 2.83, USB and IBM Thinkpad T61, apparently the same issue as described here: http://syslinux.zytor.com/archives/2008-April/009850.html The boot process always stops after "Loading boot sector... booting...". With debug tracers enabled, the last few output lines are: Loading boot sector... FR<p>Dbooting...
2007 May 18
4
Simple programming question
Hi R-users, I have a simple question for R heavy users. If I have a data frame like this dfr <- data.frame(id=1:16, categ=rep(LETTERS[1:4], 4), var3=c(8,7,6,6,5,4,5,4,3,4,3,2,3,2,1,1)) dfr <- dfr[order(dfr$categ),] and I want to score values or points in variable named "var3" following this kind of logic: 1. the highest value of var3 within category (variable named
2010 Oct 04
2
i have aproblem --thank you
dear professor: thank you for your help,witn your help i develop the nomogram successfully. after that i want to do the internal validation to the model.i ues the bootpred to do it,and then i encounter problem again,just like that.(´íÎóÓÚerror to :complete.cases(x, y, wt) : ²»ÊÇËùÓеIJÎÊý¶¼Ò»Ñù³¤(the length of the augment was different)) i hope you tell me where is the mistake,and maybe i have
1997 Apr 08
1
R-alpha: User friendly functions
A loose idea for *post*-0.50 development I've been giving a some (but not all that many) thoughts to whether some of the conceptual difficulties facing newcomers could be avoided by having simplified functions for common operations. We already have parts of this, e.g. in Kurts ctest routines. Specifically, I was thinking about data frames: How about
2011 Jun 29
2
Indexing to Insert values from a dataframe into a matrix
Hello, I think this is a simple problem but I am not coming up with a simple solution. I think it just an indexing problem. I can easily replace values in a matrix from a dataframe when the dataframe has row and column numbers. In the example below I use row and column names and I can not get it to work #make a matrix where rows and columns are the lat and long for a bounding box of Australia
2007 May 20
2
Number of NA's in every second column
Hi R-users, How do I calculate a number of NA's in a row of every second column in my data frame? As a starting point: dfr <- data.frame(sapply(x, function(x) sample(0:x, 6, replace = TRUE))) dfr[dfr==0] <- NA So, I would like to count the number of NA in row one, two, three etc. of columns X1, X3, X5 etc. Thanks in advance Lauri [[alternative HTML version deleted]]
2004 Jul 16
3
sas to r
I would be incredibly grateful to anyone who'll help me translate some SAS code into R code. Say for example that I have a dataset named "dat1" that includes five variables: wshed, site, species, bda, and sla. I can calculate with the following SAS code the mean, CV, se, and number of observations of "bda" and "sla" for each combination of
2010 Oct 04
1
I have aproblem about nomogram--thank you for your help
dear professor: I have a problem about the nomogram.I have got the result through analysing the dataset "exp2.sav" through multinominal logistic regression by SPSS 17.0. and I want to deveop the nomogram through R-Projject,just like this : > n<-100 > set.seed(10) > T.Grade<-factor(0:3,labels=c("G0", "G1", "G2","G3")) >
2008 Mar 06
2
How to hold a value(Mean sq) with a string
Hi all: Can someone advice me on how to hold the residuals Mean sq value on a string so it can be used in other calculations. I was trying something like this: Msquare<-dfr$Mean sq but fails..Thanks dfr <- read.table(textConnection("percentQ Efficiency 1.565 0.0125 1.94 0.0213 0.876 0.003736 1.027 0.006 1.536 0.0148 1.536 0.0162 2.607 0.02 1.456 0.0157 2.16 0.0103
2006 Apr 20
1
Randomly selecting one row for each factor level [Broadca st]
The following should work: > dfr.samp <- dfr[tapply(1:nrow(dfr), dfr$x, sample, 1),] > dfr.samp x y z 10 a 10 J 2 b 2 B 9 c 9 I Andy From: Kelly Hildner > > I don't use R much, and I have been unable to figure out how > to get the > subset of my data frame that I would like. > > For example, if this were my data frame: > > > dfr <-
2005 Apr 06
3
looking for a plot function
Dear useRs, I have a data frame and I want to plot all rows. Each row is represented as a line that links the values in each column. The plot looks like this: dfr <- data.frame(A=sample(1:50,10),B=sample(1:50,10), C=sample(1:50,10),D=sample(1:50,10)) xa <- 10*1:4 plot(c(10,40),c(0,50)) for (i in 1:nrow(dfr)) { lines(xa,dfr[i,],pch=20,type="o") } Things get more complicated
2011 Mar 28
2
GSoC 2011 Weighting Schemes
Hi, guys I am Wenjin from Graduate School of Chinese Academy of Science, pursing a master degree and my current research interests including using Data mining and Information retrieve technology to analysis software engineering (SE) data and support SE. I have great interested in "Weight Schemes" project. and in the last few days I have learnt some detail about DFR model family by
2001 Oct 31
2
removing duplicated rows from a data.frame
Dear all, Sorry for the simplicity of the question, but how does one go about removing duplicated rows in a data.frame? I'm looking for a quick and simple solution, as my data.frames are relatively large (50000 by 50). I've racked my brain and searched the help files and found nothing useful or quick, only duplicated() and unique() which work only work on lists. Thanks Gary.
2010 Feb 27
1
Newbie help with ANOVA and lm.
Would someone be so kind as to explain in English what the ANOVA code (anova.lm) is doing? I am having a hard time reconciling what the text books have as a brute force regression and the formula algorithm in 'R'. Specifically I see: p <- object$rank if (p > 0L) { p1 <- 1L:p comp <- object$effects[p1] asgn <-