Displaying 20 results from an estimated 5000 matches similar to: "questions on ARMA and KPSS"
2005 Mar 08
2
The null hypothesis in kpss test (kpss.test())
is that 'x' is level or trend stationary. I did this
> s<-rnorm(1000)
> kpss.test(s)
KPSS Test for Level Stationarity
data: s
KPSS Level = 0.0429, Truncation lag parameter = 7,
p-value = 0.1
Warning message:
p-value greater than printed p-value in:
kpss.test(s)
My question is whether p=0.1 is a good number to
reject
N0? On the other hand, I have a
2005 Mar 09
1
about kpss.test()
Hi All,
First of all, could you tell me what the "KPSS Level"
in the output of the test means?
I have a series, x, of periodic data and tried
kpss.test() on it to verify its stationarity. The
tests
gave me the p-value above 0.1. Since the null
hypothesis N0 is that the series _is_ stationary, this
means that I cannot reject N0. But the series does
look
periodic!
So does all this
2006 Jul 06
2
KPSS test
Hi,
Am I interpreting the results properly? Are my conclusions correct?
> KPSS.test(df)
---- ----
KPSS test
---- ----
Null hypotheses: Level stationarity and stationarity around a linear trend.
Alternative hypothesis: Unit root.
----
Statistic for the null hypothesis of
level stationarity: 1.089
Critical values:
0.10 0.05 0.025 0.01
0.347 0.463
2005 May 02
1
Trying to understand kpss.test() in tseries package
I'm trying to understand how to use kpss.test() properly. If I have a
level stationary series like rnorm() in the help page, shouldn't I get a
small p-value with the null hypothesis set to "Trend"? The (condensed)
output from kpss.test() for the two possible null hypotheses is given
below. I don't see any significant difference between these results.
> x <-
2009 Mar 06
0
modifying a built in function from the stats package (fixing arima) (CONCLUSIONS)
Thanks a lot to everybody that helped me out with this.
Conclusions:
(1)
In order to edit arima in R:
>fix(arima)
or alternatively:
>arima<-edit(arima)
(2)
This is not contained in the "Introduction to R" manual.
(3)
A "productive" fix of arima is attached (arma coefficients printed out and
error catched so that it doesn't halt parent loops to search for
2007 Dec 08
2
time series tests
Hi all,
Can anyone clear my doubts about what conclusions to take with the following what puts of some time series tests:
> adf.test(melbmax)
Augmented Dickey-Fuller Test
data: melbmax
Dickey-Fuller = -5.4075, Lag order = 15, p-value = 0.01
alternative hypothesis: stationary
Warning message:
p-value smaller than printed p-value in: adf.test(melbmax)
2007 Oct 22
1
Newbie help: Data in an arma fit
I'd like to fit an ARMA(1,1) model to some data (Federal Reserve Bank
interest rates) that looks like:
...
30JUN2006, 5.05
03JUL2006, 5.25
04JUL2006, N <---- here!
05JUL2006, 5.25
...
One problem is that holidays have that "N" for their data. As a test, I
tried fitting ARMA(1,1) with and without the holidays deleted. In other
words, I fit the above data
2007 Nov 02
0
Significance-Problems by using arma/xreg.
Hello.
I've got a problem with arma/xreg.
I would like to get a better model-fit by implenting
some external explanatory variable, so I thought I can
implement it by expand the arima-function with an
xreg-argument:
I have two stationary data vectors y and x of length
201:
y <-
2011 Jun 04
0
[R-SIG-Finance] Measure quality of fit for MA(q), ARMA(p, q) and GARCH(p, q)
Thank you so much all for your invaluable inputs.
On Sat, Jun 4, 2011 at 3:36 AM, Patrick Burns <patrick at burns-stat.com> wrote:
> A common thing to do is the Ljung-Box
> test on the residuals. ?For garch it
> would be the residuals squared.
>
> Actually for garch it should be the
> rank of the squared residuals -- see
>
2009 Oct 13
0
How to specify an ARMA(1, [1,4]) model? Solved
On Tue, Oct 13, 2009 at 5:06 PM, Rolf Turner <r.turner@auckland.ac.nz>wrote:
>
> Not clear to me what the OP really wants. Perhaps the seasonal
> model is what's required; perhaps an arima(1,0,4) model with
> theta_2 and theta_3 constrained to be 0. The latter can be
> achieved with
>
> arima(x,order=c(1,0,4),fixed=c(NA,NA,0,0,NA,NA))
>
> Or perhaps
2004 Jul 04
1
Re: Seasonal ARMA model
> It might clarify your thinking to note that a seasonal ARIMA model
> is just an ``ordinary'' ARIMA model with some coefficients
> constrained to be 0 in an efficient way. E.g. a seasonal AR(1) s =
> 4 model is the same as an ordinary (nonseasonal) AR(4) model with
> coefficients theta_1, theta_2, and theta_3 constrained to be 0. You
> can get the same answer as from
2009 Oct 13
1
How to specify an ARMA(1, [1,4]) model?
Hi,
I'm trying to model an ARMA(1,[1,4]),
i.e. I want only lags 1 and 4 of the Moving Average part.
It's the '[1,4]' part that is giving me a problem.
I've tried different arma's and arima's in different packages, namely:
packages tseries, fArma, FinTS, timeSeries, TSA, Zelig, ds1, forecast
For example, with package FinTS:
> ( ARIMA(y, order=c(1,0,c(1,4))) )
2004 Feb 12
0
How to predict ARMA models?
Hi all,
I am fitting an ARMA(1,(1,4)) model.
y(t) = a*y(t-1) + e(t) + b1*e(t-1) + b4*e(t-4)
> arma1.14 <- arma(series, lag=list(ar=1, ma=c(1,4)),
+ include.intercept = F, qr.tol = 1e-07)
works fine:
Coefficient(s):
ar1 ma1 ma4
0.872 -0.445 0.331
I want to forecast 50 periods.
I could not find a 'predict' function for ARMA models.
I
2004 Oct 13
4
incomplete function output
Dear R users,
I have a function (below) which encompasses several tests.
However, when I run it, only the output of the last test is
displayed. How can I ensure that the function root(var)
will run and display the output from all tests, and not
just the last one?
Thank you,
b.
root <- function(var)
{
#---Phillips-Perron
PP.test(var, lshort = TRUE)
PP.test(var, lshort = FALSE)
2008 Jan 10
1
question regarding kpss tests from urca, uroot and tseries packages
Hi R users!
I've come across using kpss tests for time series analysis and i have a question that troubles me since i don't have much experience with time series and the mathematical part underlining it.
x<-c(253, 252, 275, 275, 272, 254, 272, 252, 249, 300, 244,
258, 255, 285, 301, 278, 279, 304, 275, 276, 313, 292, 302,
322, 281, 298, 305, 295, 286, 327, 286, 270, 289, 293, 287,
2007 Nov 26
3
Time Series Issues, Stationarity ..
Hello,
I am very new to R and Time Series. I need some help including R codes
about the following issues. I' ll really appreciate any number of
answers...
# I have a time series data composed of 24 values:
myinput = c(n1,n2...,n24);
# In order to make a forecasting a, I use the following codes
result1 = arima(ts(myinput),order = c(p,d,q),seasonal = list(order=c(P,D,Q)))
result2 =
2008 Dec 08
0
ARMA models
Dear ALL:
Could you please eamil me how to simulate Mixed Seasonal ARMA (p,q)x(P,Q)12 models [say ARMA(0,1)x(1,0)12 ]from R.
With many thanks.
Abou
==========================
AbouEl-Makarim Aboueissa, Ph.D.
Assistant Professor of Statistics
Department of Mathematics & Statistics
University of Southern Maine
96 Falmouth Street
P.O. Box 9300
Portland, ME 04104-9300
Tel: (207)
2008 May 31
0
KPSS test - Lag selection
Hello everyone!
Quite a similar question has been posed here some time ago, but there was no
explicit solution offered. So I hope that it is OK to pose it again.
I want to perform a KPSS test using the packages "urca" or "tseries". But I
neither want to use the predefined lag structures, "short" and "long", nor
specify the number of lags arbitrarily by
2007 Mar 07
1
good procedure to estimate ARMA(p, q)?
Hi all,
I have some residuals from regression, and i suspect they have correlations
in them...
I am willing to cast the correlation into a ARMA(p, q) framework,
what's the best way to identify the most suitable p, and q, and fit ARMA(p,
q) model and then correct for the correlations in regression?
I know there are functions in R, I have used them before, but I just want to
see if I can do
2009 Jul 15
2
storing lm() results and other objects in a list
to clean up some code I would like to make a list of arbitrary length
to store?various objects for use in a loop
sample code:
############ BEGIN SAMPLE ##############
# You can see the need for a loop already
linearModel1=lm(modelSource ~ .,mcReg)
linearModel2=step(linearModel1)
linearModel3=lm(modelSource ~ .-1,mcReg)
linearModel4=step(linearModel3)
#custom
linearModel5=lm(modelSource ~ .