similar to: Help in persp (VERY URGENT ASSISTANCE)

Hi All i would like to get some help on how to use the persp() for 3d surface plotting with the data from txt file. it has format like x1 y1 z1 x2 y2 z2 x3 y3 z3 ............ and so on...sometimes the txt file data may be very large also.. how could i load this txt file and view its 3d view. thanks in advance --------------------------------- [[alternative HTML version

Dear people, I've been trying to find a way to do the following. I have a data set in text file with 3 columns and 2400 rows. i tried to read the table as fisrt<-("ex.txt",header=FALSE) I would like to read the third column values (which has 2400 value) and split them into matrix of size (600,4): as first 600 column values in first column in matrix and next 600 next

Dear All, I am very new to R projects.i would like to get some help regarding the graph construction using persp. May be i am wrong in some steps.I have given the commands which i tried for drawing 3d surface using persp.I would like to label the axes using the scales. z <- array(topnew2$V2, dim=c(600,2)) x <- 10 * (1:nrow(z)) y <- (1:ncol(z)) persp(x, y, z, theta = 30, phi =

Hi, I need clarifications on how to sell linux tools. (Though i' not sure how people ready to buy it :) ) I have written few tools and planning to write more(by giving up current non-linux & boring job). I want to know,which license will allow me to sell tools/softwares? (I hope to sell the products through online) Cheers, Lakshmipathi.G www.giis.co.in

Hi - I am a beginner to the R language. I have written the following matrix: Z.mat=matrix(c(2,2,2,1,1,1,3,2,1,6,5,4,9,1,1,2,3,2), nrow=6) I would like to add a 4th column consisting of: 6, 9, 8, 15, 16, 17 I would also like to name each column a, b, c, d as well. Thanks! [[alternative HTML version deleted]]

I don't speak on behalf of any developers, but most times it is very difficult to change the license of an open source project, as the consent of all contributors would be needed which is nearly impossible. There are ways, but I don't think it is very likely. Further information about linking gpl is widely available on the net. Afaik it is always allowed to link to any library as long as

Hi Greetings.&nbsp;I have windows server2012R2&nbsp; and installed&nbsp;Hypervisor &nbsp;I have installed Ubuntu 16.04 server edition in Virtual machine(hyper-v 2012r2) &nbsp;Postfix and dovecot are running &nbsp;dovecot version :2.2.22 (fe789dz) &nbsp;Able to send mail is ok. mail received in /var/mail/%u &nbsp;could not receive mail from client Thunderbird.

Always I have the following lines in my mail.log (at startup and service restart) dovecot: master: Warning: Killed with signal 15 (by pid=3156 uid=0 code=kill) dovecot: log: Warning: Killed with signal 15 (by pid=1 uid=0 code=kill) dovecot: master: Dovecot v2.2.22 (fe789d2) starting up for imap, pop3 (core dumps disabled) dovecot -n output is below: # 2.2.22 (fe789d2): /etc/dovecot/dovecot.conf

hi all, The reason why writting this mail--i don't know how to name a tool written by myself :-) Following is the functionality of a file system tool : When you install the tool it acts as a protection for your files.Tool copies the address of files. If you accidently deleted a file -if its contents are not modified-then the tool retrives the contents of file. How should i call this tool./

Hello, We are using frailty models to estimate risk of one year death. Is there a way to generate survival curves adjusted for covariates and also include frailty term? Any help will be much appreciated! Thanks! LV [[alternative HTML version deleted]]

Hi All, I installed OpenSUSE 11.0, updated samba server to 3.2.4 version. Added two users in linux and samba with user names "test1" and "Test2". (Please note the capital letter in Test2). Created two shares in /srv/samba/shares "test1" and "Test2". The permissions of the shares are as below. drwx------ 2 test1 users 4096 2009-12-11 12:42 test1 drwx------

hi This is Tarun from Indusa Global , Jamaica pl. reply regards -------------- next part -------------- A non-text attachment was scrubbed... Name: tarun.vcf Type: text/x-vcard Size: 180 bytes Desc: Card for tarun kumar Url : http://lists.samba.org/archive/samba/attachments/19990727/506b9d4c/tarun.vcf

AFAIK, R only has "pnorm" which computes the probability of getting a value smaller or equal to "x" from a normal distribution N[mean,stdev]. For example: R> pnorm(0, 4, 10) [1] 0.3446 means there is 34.46% chance of getting a value equal to or smaller than 0 from a N(4, 10) distribution. What I intend to get is: given the observed value "x", mean, and stdev

Hi Guy's I was wondering if someone could point me in the right direction. dbinom(10,1,0.25) I am using dbinom(10,1,0.25) to calculate the probabilty of 10 judges choosing a certain brand x times. I was wondering how I would go about simulating 1000 trials of each x value ? regards Brendan -- View this message in context:

Hi All, In package e1071 for SVM based classification, one can get a probability measure for each prediction. I like to know what is method that is used for calculating this probability. Is it calculated using logistic link function? Thanks for your help. Regards, Raj

Hi all, I am a freshman of R,but I am interested in it! Those days,I am learning pages on NIST,with url http://www.itl.nist.gov/div898/handbook/eda/section3/probplot.htm, I am meeting a problem about probability plot and I don't know how to plot a data set with R. Could somebody tell me the answer,and a example is the best! I will look forward to your answer. Thank you very much.

Estimate region of highest probabilty density Dear R-community I have data consisting of x and y. To each pair (x,y) a z value (weight) is assigned. With kde2d I can estimate the densities on a regular grid and based on this make a contour plot (not considering the z-values). According to an earlier post in the list I adjusted the kde2d to kde2d.weighted (see code below) to estimate the

Dear R users, i try to calculate the probabilty to survive a given time by using the estimated survival curve by kaplan meier. What is the right way to do that? as far as is see i cannot use the predict-methods from the survival package? library(survival) set.seed(1) time <- cumsum(rexp(1000)/10) status <- rbinom(1000, 1, 0.5) ## kaplan meier estimates fit <- survfit(Surv(time,

Dear list, I would like to plot the empirical cumulative distribution of the time needed by a treatment to attain a certain goal. A number of experiments is run with a strict time limit. In some experiments the goal is attained before the time limit, in other experiments time expires before the goal is attained. The situation is very similar to survivial analysis with censored data. I tryed

It is a trivial matter to adjust the linewidth of the axes and plot line in a 2D plot: x <- 1:10; y <- 1:10; par(lwd=2); # axis (and others) linewidth plot(x,y,"l",lwd=6); # plot linewidth Is there anything comparable to this for persp or wireframe? I've tried a number of ways, and the framebox/axes seem to be linked to the linewidth used in generating the