similar to: Place more than one key with xyplot

I'm trying to insert rows of a data.frame into a database table, or update where the key fields of a record already exist in the table. I've come up with a possible solution below, but would like to hear if anyone has a better solution. # The problem demonstrated: # Create a data.frame with test values library(RODBC) tbl <- data.frame( key1 = rep(1:3, each = 2), key2 =

key1.=c(1, 2, 3) key2.=c(2) if (identical(key1.,key2.) == "TRUE") { cat("No Errors found") } if (length(setdiff(key1., key2.)) !=0) {

Hi, Thanks for a great environmentfor statistical computing :-) I have some input data in a file ("input_kvpairs.csv") of the form key1=23, key2=67, key3="hello there" key1=7, key2=22, key3="how are you" key1=2, key2=77, key3="nice day, thanks" Now in my head I wish it was of the form ("input.csv") #key1, key2, key3 23, 67, "hello

On 30/05/15 08.34, Nico Kadel-Garcia wrote: > On Sat, May 30, 2015 at 8:00 AM, Kasper Dupont > <kasperd at kdxdx.23.may.2015.kasperd.net> wrote: > > As far as I can tell when the ssh command uses an agent to > > authenticate to a server and then forwards an agent to that > > server, it will always use the same agent for both purposes. > > > > Has there

Dear R-experts, recently, I started to discover the world of R. I came across a problem, that I was unable to solve by myself (including searches in R-help, etc.) I have a flat table similar to key1 key2 value1 abcd_1 BP 10 abcd_1 BSMP 1A abcd_1 PD 25 abcd_2 BP 20 abcd_3 BP 80 abcd_4 IA 30 abcd_4 PD 70 abcd_4 PS N I wish to transform this table to obtain the following result: key2 key1 BP

Dear R-Help I have some trouble to set the legend in a xyplot into two rows. The code below gives me the legend in the layout I am looking for, I just rather have it in two rows. library(lattice) schluessel <- list( points=list( col="red", pch=19, cex=0.5 ), text=list(lab="John"), lines=list(col="blue"),

Using MultiValueSorter, I can sort by key1, key2, relevance; or relevance, key1, key2. But AFAIK, I can't sort by key1, relevance, key2. Unless I spool out the entire result set or write some C++. I wonder if we need a new 'sort by' function that accepts any combination of keys and relevance in any order? The function would make it's own optimisations (ie is relevance first or

Has anyone used this to get data out of PHP sessions? I can get data out using the php_unserialize function however I am getting a array of strings that looks like this: ["key1: data1","key2: data2"] I would rather get RoR session style of associative arrays ["key1"=>"data", "key2"=>"data2"] Am I just being dense and there is an

Hi everyone, I have the following code that works in data frames taht I would like tow ork in data.tables . However, I'm not really sure how to go about it. I basically have the following names = c("data1", "data2") frame = data.frame(list(key1=as.integer(c(1,2,3,4,5,6)), key2=as.integer(c(1,2,3,2,5,6)),data1 = c(3,3,2,3,5,2), data2= c(3,3,2,3,5,2))) for(i in

Hi, To a large extend, Asterisk's /etc/asterisk/*.conf configuration files conform to a format such as: [section1] key1=value1 key2=value2 [section2] key1=value1 key2=value2 ... To increase coherence when running custom-made application in Perl, Java, PHP, ...) and Asterisk on the same platform, I'm wondering if could extend a bit Asterisk's config files instead of duplicating data

Hi, Asterisk database is made of <family><key> records such as: fam key1 val1 fam key2 val2 ... fam key100 val100 I'm looking for the smartest way to iterate among different keys associated to a given family. One way to do this is to parse "database show fam" response. Is there something smarter ? Something like ${DBKEYS(fam)} which would evaluate to "key1

Its not clear from the documentation whether one should do \keyword[key1, key2} or \keyword{key1} \keyword{key2} in .Rd files. I believe the latter is correct. (At least 'R CMD check' complains when given the first version.) It would help to make this explicit in the R extension writing docs. Tim -- Timothy H. Keitt Department of Ecology and Evolution State University of New

Buenas, una vez más. Utilizo: data <- subset(data,data$Key %in% data2$Key) para quedarme con los casos de data que están también en data2, de acuerdo a la variable Key. ¿Cómo sería si quiero que sean los que coinciden en Key1 y Key2? Pense hacer un collapse con Key1 y key2, tanto en data como data2, y usarlo como uso key en el ejemplo de arriba, pero debe haber una forma más

Dear R help group I've been working on this plot for a while now and now getting around to the minor adjusments. I would like to be able to put a border and background fill around the legend in this plot. I understand the legend 'bty' should do this have this capablity but not sure how the syntax works in this case ###### initalise library("lattice")

Greetings Supreme Council of R Masters, Like toddler, I have gotten my head stuck in the banisters of R ... again. Let it be know I am still a neophyte in the R-community forum world, so please don't flame me too bad. I have two sets of data, each with a set of timestamps. I would like to somehow merge the datasets based on the timestamps and an individual identifier. That is there are

On Thursday 03 December 2015 11:52:14 Richard W.M. Jones wrote: > On Wed, Dec 02, 2015 at 02:10:52PM +0100, Pino Toscano wrote: > > Hi, > > > > one of the bugs we have (#1092583) is about the lack of query string > > for http/https URLs: there were patches about that (not merged yet), > > whose solution was to add a new optional argument "querystring".

On Tuesday, 12 November 2019 19:35:12 CET Richard W.M. Jones wrote: > This allows multiple --key parameters on the command line to match a > single device. This could either be specified as: > > tool --key /dev/sda1:key:trykey1 --key /dev/sda1:key:trykey2 > > which would try "trykey1" and "trykey2" against /dev/sda1. This seems OK for me, so you can

I await Luke''s node settings implementation with interest. At the moment however, I have this sort of ugliness: $site = $hostname ? { fred => "opsera", barney => "bedrock", default => "unknown site", ... } So I''ve knocked up this little function to use CSV files instead. Now I can just do: $site =

(I do not know how to make Outlook send plain text, so I avoid apostrophes.) For what it is worth, I agree with Mark Webster. The discussion by Ivan Krylov is interesting, but if duplicated really treated a row name as part of the row then any(duplicated(data.frame(?))) would always be FALSE. My expectation is that if key1 is a subset of key2 then all(duplicated(df[key1]) >=

This fixes Github issue #2 reported by "kupiakos". <https://github.com/libguestfs/hivex/issues/2> --- generator/generator.ml | 2 +- python/t/210-setvalue.py | 26 +++++++++++++++++--------- 2 files changed, 18 insertions(+), 10 deletions(-) diff --git a/generator/generator.ml b/generator/generator.ml index 908c5f3..02aaf12 100755 --- a/generator/generator.ml +++