similar to: Cluster analysis using EM algorithm

Hi list, not really a problem to solve but a strange unwanted behavior (at least I do not like it): I'm loading library(multiv) to use sammon. Later I load library(MASS) which tells me that sammon is masked now, because there is also a MASS version of sammon. Since I believe that the MASS version is at least as good as the multiv version, I would also use the MASS version, but help(sammon)

Hi, I have run rpart to construct a regression tree. Is there any simple method to draw a nice picture of it, as it is usually done in books and paper to visualize the tree? Thank you, Christian *********************************************************************** Christian Hennig Fachbereich Mathematik-SPST/ZMS, Universitaet Hamburg hennig at math.uni-hamburg.de,

Hi, I want to do something like this: par(mfrow=c(7,7)) for (i in 1:49) hist(RATDACOM[SUBJNO==i],breaks=0.5+(0:6), main="",xlab="",ylab="",xaxt="n",yaxt="n") (Don't think about what RATDACOM and SUBJNO are.) I get an error Error in plot.new() : Figure margins too large. 36 histograms with mfrow=c(6,6) work. But the 36 histograms

Hi, exist a special cluster-analysis algorithms which can work with NA's. a further "problem" is that i want cluster variables not cases to identify special variable-set's. Is it a common way turn the data.frame and use kmeans,because this works with NA's, or have anybody another method for finding "variable-sets" , with exception of factor analysis. thanks for

Dear all, I'm fitting a set of length-of-stay data by a model of mixture of exponentials. I've been following the example on page 436 in MASS (5th Ed.). However, I have a couple of questions while following this example. What if we don't know how many components there are in the model in advance. Is there any established method to determine the number of components from a set of

Hello list, I want to apply svm from library e1071, and I want to supply class weights. I do not really understand the help entry (and there is no example) class.weights: a named vector of weights for the different classes, used for asymetric class sizes. Not all factor levels have to be supplied (default weight: 1). All components have to be named. I have two

Hi, I want R to be installed on a UNIX network (Solaris). I am not the system administrator and so I cannot do it myself. The system administrator wants to know which packages I want, and it may be a lot. Is there an easy way to download and install all packages at once? Is it a good idea? (There is a good chance that I do not need the some few packages that do not install well during such a

Hi, is there any method for goodness of fit testing of an (as general as possible) univariate distribution with parameters estimated, for normal, exponential, gamma distributions, say (e.g. the corrected p-values for the Kolmogorov-Smirnov or Chi-squared with corresponding ML estimation method)? It seems that neither ks.test nor chisq.test handle estimated parameters. I am aware of function

Hi, I would like to use the format function to get numbers all with three digits to the right of the decimal point, even in cases where there is no significant digit left. For example, I would like to get c(0.3456789,0.0000053) as "0.346" "0.000". It seems that it is not possible to force format to print a "0.000", i.e. without any significant decimal places. Is it

Hi, here are three results of random forest (version 4.0-1). The results seem to be more or less the same which is strange because I changed the classwt. I hoped that for example classwt=c(0.45,0.1,0.45) would result in fewer cases classified as class 2. Did I understand something wrong? Christian x1rf <- randomForest(x=as.data.frame(mfilters[cvtrain,]),

Dear group, I would like to document more than one function on one help page using the Rd language. I tried something like \value{ \code{foo1} returns a list with components \item{arg1}{Argument 1} \item{arg2}{Argument 2} \code{foo2} returns a list with components \item{arg3}{Argument 3} \item{arg4}{Argument 4} } Unfortunately this makes the text "\code{foo2} returns a list

Hi, the following strange error appears when I use qda: > qda1 <- qda(as.data.frame(mfilters[cvtrain,]),as.factor(traingroups)) Error: function is not a closure That's also strange: > qda1 <- qda(mfilters[cvtrain,],as.factor(traingroups)) Error in qda.default(mfilters[cvtrain, ], as.factor(traingroups)) : length of dimnames must match that of dims Some backgroud: >

Dear group, I want to use the mclust package on large data, and therefore I want to use a subset in the initial clustering phase. From help(mclust): k: If `k' is specified, the hierarchical clustering phase will use a sample of size `k' of the data in the initial hierarchical clustering phase. The default is to use the entire data set. m2 is a

Hello, I would like to calculate a cluster analysis and I use the function 'hclust'. I have seen the GRAPHICAL results of this function with 'plot'. I would like to analyse this cluster but I don't know how to see the NUMERICAL results of each step of this cluster like: - R Squared - Pseudo F - Pseudo t**2 Thank you for any help, Pierre-Olivier Chasset ===== Pierre-Olivier

Dear R-users, I have a two - dimensional data set which needs to be clustered into groups: I'm searching for groups of points which show a positive correlation (in a twodimensional plot of the data set), but I do not have any knowledge about how many groups there might be. Do you know of a clustering algorithm in R (or in general) which can use a-priori information about the cluster's

Hi, Does anybody know some package or function that computes canonical variates? Luis & Janete -------------------------------------------- sapo.pt/kitadsl -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the

Dear list, (also sent to Roger Bivand, but perhaps somebody of you can help me also) I am trying to use package spdep for fitting an SAR model with errorsarlm. However, I am not sure how to make a valid nb object out of my neighborhood. As far as I have seen, there is no documentation for nb.object. I have done the following: class(pschmid$nb) <- "nb" # pschmid is a prab object as

<FONT face="Default Sans Serif, Verdana, Arial, Helvetica, sans-serif" size=2><div>I was wondering if anyone knew there are functions to do mixture modeling in R.</div><DIV>&nbsp;</DIV><DIV>Many thanks in advance,</DIV><DIV>Peter

Hey, Dose R include some package for Gaussian Mixture Model data generation and parameters estimation? Now I want to assign lots of multivariate data into a GMM model. So just wondering if given sample data, can we use some functions to estimate the compoents' density function. Thanks for your support. Fred -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-

Hi, I would like to know if someone knows an extended implementation of k-means in R to find appropriate number of clusters for a given k-dimensional data. Also, I am working on clustering for forecasting, if someone is interested or has knowledge on implementational details please mail me, I would appreciate it. Regards Skanda Kallur "Cogito, ergo sum" (I think, therefore I