Displaying 20 results from an estimated 800 matches similar to: "(no subject)"
2004 Nov 23
6
Weibull survival regression
Dear R users,
Please can you help me with a relatively straightforward problem that I
am struggling with? I am simply trying to plot a baseline survivor and
hazard function for a simple data set of lung cancer survival where
`futime' is follow up time in months and status is 1=dead and 0=alive.
Using the survival package:
lung.wbs <- survreg( Surv(futime, status)~ 1, data=lung,
2009 Nov 10
0
NEW release of FRAILTYPACK
Dear All,
We are happy to announce, after a long gestation, the release of the new
version of FRAILTYPACK (version 2.2-9.5) which is now available from
CRAN. The package fit general frailty models using penalized likelihood
estimation, for clustered or recurrent events.
For instance :
-- ADDITIVE FRAILTY MODELS for proportional hazards models with two
correlated random effects (intercept
2009 Nov 10
0
NEW release of FRAILTYPACK
Dear All,
We are happy to announce, after a long gestation, the release of the new
version of FRAILTYPACK (version 2.2-9.5) which is now available from
CRAN. The package fit general frailty models using penalized likelihood
estimation, for clustered or recurrent events.
For instance :
-- ADDITIVE FRAILTY MODELS for proportional hazards models with two
correlated random effects (intercept
2004 Jan 14
1
estimation of lambda and gamma with std errors for a weibull model
Dear R experts,
How should lambda and gamma (with std.errors) be calculated for a weibull model with age as an independent predictor? I have assumed that this can be done with survreg with e. g. (summary(survreg(Surv(time, status) ~ age, dist = 'weibull')) ) and predict.survreg with e.g. (predict(model, se.fit = T, newdata = data.frame(age = seq(50, 80, 5)) but unfortunately I'm
2006 Jul 07
6
parametric proportional hazard regression
Dear all,
I am trying to find a suitable R-function for
parametric proportional hazard regressions. The
package survival contains the coxph() function which
performs a Cox regression which leaves the base hazard
unspecified, i.e. it is a semi-parametric method. The
package Design contains the function pphsm() which is
good for parametric proportional hazard regressions
when the underlying base
2011 Apr 02
4
help
Dear R Help group
I need to run a command line script from within R session. I am not clear
how i can acheive this. I tried shell and system function, but i am missing
something critical.can someone provide help?
My intention is to create a pdf file of a plot in R and then attach
existing files from my system as attachment into the newly created pdf file.
Any help would be greatly appreciated..
2005 Jun 09
2
Weibull survival modeling with covariate
I was wondering if someone familiar
with survival analysis can help me with
the following.
I would like to fit a Weibull curve,
that may be dependent on a covariate,
my dataframe "labdata" that has the
fields "cov", "time", and "censor". Do
I do the following?
wieb<-survreg(Surv(labdata$time,
labadata$censor)~labdata$cov,
2008 Jan 23
2
Parametric survival models with left truncated, right censored data
Dear All,
I would like to fit some parametric survival models using left
truncated, right censored data in R. However I am having problems
finding a function to fit parametric survival models which can handle
left truncated data.
I have tested both the survreg function in package survival:
fit1 <- survreg(Surv(start, stop, status) ~ X + Y + Z, data=data1)
and the psm function in package
2005 Aug 27
1
survival parametric question
Hi to all,
I am working on design package using survival function.
First using PSM and adopting a weibull specification for the baseline hazard , I have got the following results(since weibull has both PH and AFT propreties ,in addition I have used the PPHSm command):
Value Std. Error z p
(Intercept) 1.768 1.0007 1.77 7.73e-02
SIZE -0.707 0.0895 -7.90 2.80e-15
2005 Jun 24
1
interpreting Weibull survival regression
Hi,
I was wondering if someone can help me
interpret the results of running
weibreg.
I run the following and get the
following R output.
> weibreg(Surv(time, censor)~covar)
fit$fail = 0
Call:
weibreg(formula = Surv(time,
censor)~covar)
Covariate Mean Coef
Rel.Risk L-R p Wald p
covar 319.880 -0.002 0.998
0.000
log(scale) 0.000 8.239
2008 Oct 06
10
DO NOT REPLY [Bug 5811] New: rsync error: error allocating core memory buffers (code 22) at io.c(635)
https://bugzilla.samba.org/show_bug.cgi?id=5811
Summary: rsync error: error allocating core memory buffers (code
22) at io.c(635)
Product: rsync
Version: 3.0.4
Platform: x64
OS/Version: Linux
Status: NEW
Severity: blocker
Priority: P3
Component: core
AssignedTo: wayned@samba.org
2010 Dec 10
1
survreg vs. aftreg (eha) - the relationship between fitted coefficients?
Dear R-users,
I need to use the aftreg function in package 'eha' to estimate failure times for left truncated survival data. Apparently, survreg still cannot fit such models. Both functions should be fitting the accelerated failure time (Weibull) model. However, as G?ran Brostr?m points out in the help file for aftreg, the parameterisation is different giving rise to different
2013 Apr 19
2
NAMESPACE and imports
I am cleaning up the rms package to not export functions not to be called
directly by users. rms uses generic functions defined in other packages.
For example there is a latex method in the Hmisc package, and rms has a
latex method for objects of class "anova.rms" so there are anova.rms and
latex.anova.rms functions in rms. I use:
2012 Jul 23
2
Samba 4 on Production
We're involved in a project that the requirements could be satisfied
with both samba3 and 4. Anyway I am testing what can be done with
Samba4 and after following the tutorial published in the official
wiki, I was able to create my test domain, and join WinXP and Win7
machines to it without a problem.
I still need to test the GPO functionality, and some other stuff, but
before continuing with
2009 Jan 26
1
Error in Surv(time, status) : Time variable is not numeric
Dear,
I want to analyze two-level survival data using a shared frailty model, for
which I want to use the R package 'Frailtypack", proposed by Rondeau et al.
The dataset was built using SAS software. I also tried to change the format
using SPSS and Excell.
My (reduced) dataset has following column names:
ID entry time status family var1
I used following command:
>
2004 Dec 22
0
weighted kernel density estimation
Dear wizaRds,
I use the MASS::kde2d function to estimate density of the two first
principal components. I do that to have a graphic visualisation of a
"group structure" in my dataset. So far, no problem.
But i would like to estimate that density using weights according to the
COS?? values that tells me if my observation is well represented on the
factorial plan 1-2. I would like to
2013 Mar 02
0
frailtypack: new options !
A new version of the package FRAILTYPACK is now available on CRAN.
-- possibility to fit now a Shared and a Joint Frailty model with a log-normal distribution for the random effects.
-- possibility to deal with interval-censored data (for a shared frailty model)
-- possibility to fit a joint frailty model for clustered data
For more details see the corresponding NEWS files in the pkgs.
We are
2013 Mar 02
0
frailtypack: new options !
A new version of the package FRAILTYPACK is now available on CRAN.
-- possibility to fit now a Shared and a Joint Frailty model with a log-normal distribution for the random effects.
-- possibility to deal with interval-censored data (for a shared frailty model)
-- possibility to fit a joint frailty model for clustered data
For more details see the corresponding NEWS files in the pkgs.
We are
2009 Mar 08
2
survreg help in R
Hey all,
I am trying to use the survreg function in R to estimate the mean and
standard deviation to come up with the MLE of alpha and lambda for the
weibull distribution. I am doing the following:
times<-c(10,13,18,19,23,30,36,38,54,56,59,75,93,97,104,107,107,107)
censor<-c(1,0,0,1,0,1,1,0,0,0,1,1,1,1,0,1,0,0)
survreg(Surv(times,censor),dist='weibull')
and I get the following
2009 Nov 13
2
survreg function in survival package
Hi,
Is it normal to get intercept in the list of covariates in the output of survreg function with standard error, z, p.value etc? Does it mean that intercept was fitted with the covariates? Does Value column represent coefficients or some thing else?
Regards,
-------------------------------------------------
tmp = survreg(Surv(futime, fustat) ~ ecog.ps + rx, ovarian,