similar to: Installation of XML library can't find libxml2.dll

Hi, As the server www.omegahat.org seems to be down since quite a while, could someone send me the RSXML library for Windows2000 ? Many thanks, Marc Mamin

I am getting what appears to be an Unbuntu level error in trying to install the XML package. Both commands: install.packages("XML:) install.packages("XML", dependencies = TRUE) give an error . The full installation script is below but the problem to my very inexperenced eye seems to be here: checking for pkg-config... /usr/bin/pkg-config checking for xml2-config... no Cannot

Hi When I use plot(hclust(dist..)...)...) etc to create a dendrogram of a hierarchial cluster analysis, I end up with a vertical tree. What do I need to do to get a horizontal tree? Also, my users are used to seeing trees who's leaves all "end" at the same place (eg. Like in minitab). Is this possible in R? Thanks Mick Michael Watson Head of Informatics Institute for Animal

Hi, Does anyone have a binary of XML package for 1.7.0 on Windows? I have searched it at the RSXML pages (http://www.omegahat.org/RSXML/ ) but it seems it is no longer support. Any pointers for the compiled version will be appreciated. Regards, mushtaq [[alternate HTML version deleted]]

Hi When I give the command: > heatmap.2(as.matrix(d),Rowv=as.dendrogram(hc.gene),Colv=FALSE,scale="row ",trace="none",col=greenred.colors(79)) The resulting heatmap has re-ordered my columns! This is time-course data, and I don't want my columns re-ordered! Note from the help: Rowv: determines if and how the _row_ dendrogram should be reordered.

Hi Sorry to ask such a basic question. I have a list, each element of which is a vector of two values. What I actually want is a matrix with two columns, and one row per element of the list. Obviously I have tried as.matrix(), and as.vector() but I didn't expect the latter to work. I feel so lame asking this. Any suggestions? Mick

Hi Forgive my ignorance. I am selecting a column of a data.frame using the column name, and I want to know what the resulting column "is". My data frame is called "submin" and the column name is held in a variable called "display.gname" Eg: > is.data.frame(submin) [1] TRUE > is.data.frame(submin[,display.gname]) [1] FALSE >

Hi I have a complicated plot which has a potentially large legend. What I want to do is actually create the legend in a new window. Has anyone done this before? I'd like to be able to create a window with just the legend in it, and have it so the window is just the right size etc. I'm sure someone must have done this already? If not, any tips would be welcome. Thanks Mick

Hi I did a google search on this and came up with nothing. OK, in the latest release of R for windows, I want to change the gui to SDI mode. Edit -> GUI preferences Choose SDI Apply I get the message about properties not being able to be changed on a running console, and that I need to save. So I click Save, and am met with a "Save As" dialogue box with the default file called

Hi Thanks once again for your help, I do appreciate it..... however.... Here is what I get with your test.... (under tcsh - i normally use bash, but I will keep everything the same) users/mwatson> env http_proxy=http://wwwcache.bbsrc.ac.uk:8080/ R >options(internet.info=0) >update.packages() trying URL `http://cran.r-project.org/src/contrib/PACKAGES' unable to connect to

Hello all, I have loading problem with XML_1.9 under 64 bit R2.3.1, which I got from http://R.research.att.com/. XML_1.9 works fine under 32 bit R2.5.0. I thought that could be installation problem, and I tried install.packages or biocLite, every time the package installed fine, except some warning messages below: ld64 warning: in /usr/lib/libxml2.dylib, file does not contain requested

Hi We have touched on this before, but I don't think I quite got it right. So I have a list, each element of which is a a vector of 2 numbers: > l2 $cat000_a01 [1] 0.3429944 4.5138244 $cat000_a02 [1] 0.1929336 4.3064944 $cat000_a03 [1] -0.2607796 4.1551591 What I actually want to convert this into is a matrix with the names (cat000_a01 etc) as row names, the first element of each of

R Users: After installing Bioconductor, RSXML and all the relevant Win32 DLLs (libxml2, zlib, iconv), I receive the following error message when using pm.getabst() Error in xmlRoot(absts) : no applicable method for "xmlRoot" I receive this when using the example from help(pm.getabst). Downloading the target XML file, parsing it with xmlTreeParse and applying xmlRoot returns no

Hi I have data from 12 subjects. The measurement is log(expression) of a particular gene and can be assumed to be normally distributed. The 12 subjects are divided into the following groups: Infected, Vaccinated, Lesions - 3 measurements Infected, Vaccintaed, No Lesions - 2 measurements Infected, Not Vaccinated, Lesions - 4 measurements Uninfected, Not Vaccinated, No Lesions - 3 measurements

Hi I've been reading the help for by and aggregate but can't get my head round how to do this. I have a data frame - the first three columns are replicate measurements, then the next 3 are replicates etc up to 36 (so 12 variables with 3 replicate measurements each). I want to compute the mean for each of the 12 variables, so that, for each row, I have 12 means. A grouping variable

I think that title makes sense... I hope it does... I have a data frame, one of the columns of which is a factor. I want the rows of data that correspond to the level in that factor which occurs the most times. I can get a list by doing: by(data,data$pattern,subset) And go through each element of the list counting the rows, to find the maximum.... BUT I can't help thinking there's

Quite a simple one really! When I run boxplot(), the labels on the X axis are horizontal, and I want them vertical. So I did: par(las=3) boxplot(...) And my labels just aren't there anymore.... Any help???

Hi This is a difference between the way matrices and data frames work I guess. I want to replace the NA values in a data frame by 0, and the code works as long as the data frame in question actually includes an NA value. If it doesn't, there is an error: df <- data.frame(c1=c(1,1,1),c2=c(2,2,NA)) df[is.na(df)] <- 0 df df <- data.frame(c1=c(1,1,1),c2=c(2,2,2)) df[is.na(df)] <-

Dear R expert: I have the problems with calling R from Java on Windows XP_SP2/Eclipse3.1/JDK1.5 problems: Loading RInterpreter library Exception in thread "main" java.lang.UnsatisfiedLinkError: no RInterpreter in java.library.path at java.lang.ClassLoader.loadLibrary(ClassLoader.java:1682) at java.lang.Runtime.loadLibrary0(Runtime.java:822) at

Hi I can't get R to connect to the internet. I am running R 1.7.1 on Windows XP and whenever I try to download packages etc from within R using the internet, it fails. OK so I am behind a firewall and use a proxy server.... SO, if I go to my MS-DOS prompt and type: RGui.exe --internet2 everything works.... BUT i can't set up a shortcut for this as Windows (I hate Windows) complains