similar to: How to avoid rounding of matrix elements?

hi all, I am trying to use named list to hash a bunch of vector by name, for instance: test = list() test$name = c(1,2,3) the problem is that when i try to get the values back by using the name, the matching isn't done in an exact way, so test$na is not NULL. is there a way around this? Why by default all.equal.list doesnt require an exact match? How can I do hashing in R? thanks. ulas.

Hi, First let me say I am a big fan of R and appreciate all your time and effort. The update() function does not seem to work in a for loop. Consider the following: mdat <- matrix(c(1,2,3, 11,23,13, 12,4,8), nrow = 3, ncol=3, byrow=TRUE) reg <- lm(mdat[7:9]~1) for(i in 1:2) { reg <- update(reg,.~.+mdat[((i-1)*3 + 1):(i*3)]) #update reg twice } reg # reg should have two independent

Dear R-help team, I am getting addicted to using R but keep on getting many challenges on the way especially on data management (data cleaning). I have been wanting to drop all the rows if there values are `NA' or have specific values like 1 or 2 or 3. mdat <- matrix(1:21, nrow = 7, ncol=3, byrow=TRUE, dimnames = list(c("row1",

Hi all, So let's say I have a matrix, mdat and I only know the index number. How do I retrieve the column and row names? For example, > mdat <- matrix(c(1,2,3, 11,12,13), nrow = 2, ncol=3, byrow=TRUE, dimnames = list(c("row1", "row2"), c("C.1", "C.2", "C.3"))) > mdat[4] [1] 12 >

Dear R help, Apologies for the less than informative subject line. I will do my best to describe my problem. Consider the following matrix: mdat <- matrix(c(1,0,1,1,1,0), nrow = 2, ncol=3, byrow=TRUE, dimnames = list(c("T1", "T2"), c("sp.1", "sp.2", "sp.3"))) mdat In my actual data I have time

dear all, i am anewcomer. i have a set of paired data, the values are great different from each other. i want to show them in histogram. first, how to draw each bar for corresponding paired data side by side; second, how to set the scale of y axis? one is up to 100-fold to the other. ifdoubleslash is used to omit some coordinates, the histogram will looks better. is there anyone that can help

Hello there, I have a question regarding bar plots. I am trying to plot the data from the following matrix as a barplot - # input data mdat <- matrix(c(0.1,0.9,0.9,0.1,0.5,0.5,0.45,1-0.45,0.6,0.4,0.8,0.2), nrow = 6, ncol=2, byrow=TRUE, + dimnames = list(c("Mon", "Mon", "Tues", "Tues", "Thurs", "Friday"), +

Hi, I was trying to make another legend for the rug plot. Sample code: library(ggplo2) ids <- paste('id_',1:3,sep='') before <- sample(9) after <- sample(1:10,9) dat <- as.matrix(cbind(before,after)) rownames(dat) <- rep(ids,3) position <- c(rep(10,3),rep(13,3),rep(19,3)) mdat <- cbind(melt(dat),position) ggplot(mdat, aes(position, value)) +

Hi everyone. Long time listener, first-time caller here. I have a data set that's been melted with the excellent reshape package, but I can't seem to cast it the way I need to. Here's the melted data's structure: > str(mdat) 'data.frame': 6978 obs. of 4 variables: $ VehType : Factor w/ 2 levels "Car","Truck": 1 1 2 1 1 2 1 1 1 1 ... $ Year :

Hi, Can you please help me with this please? What I am trying to do is call a vector from R function and used in the new function So I create 4 functions with these arguments M11 <- function(TrainData,TestData,mdat,nsam) { ls <- list() I have few statments one of them is vectx <- c(,1,2,3,4,5,6,6) vectz <- c(12,34,5,6,78,9,90) and then................ ls(vectx=vtecx,vectz=vectz)

Alright, so I am trying to write my own function to calculate column sums in a matrix. I want the result as a single list with the values. So far I have: csum<-function(m) { a = data.frame(m) s = lapply(a,sum) return(s) } What is the easiest way to have it return in a format such as [1] 6 15 24 ? Thanks. -- View this message in context:

Hi I got a barplot that has values between 0-150 and the y-axis shows the steps 0 50 100 and 150 but I would like to change it to 0 10 20 30... ...130 140 150 Dont really know the word in english so sry about it beeing abit confusing :) Thx for your help Joel -- View this message in context: http://r.789695.n4.nabble.com/change-y-axis-distance-tp2548363p2548363.html Sent from the R help

Hi all, I try to represent a multiple curve graphic where the x-axis is the temperature and the different y-axes are the different X (X22,X43,X44...) some X corresponds to the same molecule (22 and 44 are for CO2 for instance) so I use the same colour for them. I wanna mix the linetype with the colour to be able to visually see the difference between X43 and X45 The best I have done up to now

Hello R users (and Hadley) I have another question about ggplot2 :-) (version 0.8) `dat` <- structure(list(D = c("a", "b", "c", "d"), G = c(1.51520888871520, 1.88812208268440, -6.60521862, 0.55968739), E = c(1.38888592256404, 1.39366168665589, 1.22509259382058, 1.36617701059296), I = c(6.92634958902857, 6.94416045215158, 13.2179488828556,

Hello list, ## I have been doing the following process to convert data from one form to another for a while but it occurs to me that there is probably an easier way to do this. I am often given data that have column names which are actually data and I much prefer dealing with data that are sorted by factors. So to convert the columns I have previously made use of make.groups() in the lattice

Hello, It looks to me as if the ! logical operator cannot be called when subsetting a data.frame. In the example below, the value column has two factor levels (but my typical datasets have more), and what I am trying to do is to exclude all lines for which the "value" is different from "A". I have got a syntax error message everytime I try to use the subset() function.

Hi R-experts, I try to find a way to transfer a matrix to a data.frame that is used as input of aov. can you give me advice for that? >mdat <- matrix(c(1,2,3, 11,12,13), nrow = 2, ncol=3, byrow=TRUE, dimnames = list(c("row1", "row2"), c("Col1", "Col2", "Col3"))) >mdat      Col1 Col2 Col3 row1    1    2    3 row2   11   12   13 ===>

Hi, I have been recently experimenting with the lattice package, which I must admit is just great! However, I'm sort of stuck in modifying certain parameters; Would appreciate some pointers on a couple of things: 1) Is it possible to change the font of the labels (say to computer modern) -- either in the Windows output or thru' Sweave (generating EPS/PDF)? 2) As you will notice, there

HOla a todos soy novato en R. Lo que pasa es que tengo un conjunto de datos en una matriz y me gustaría saber , si es que el R tiene un comando en especial (para no tener que hacer el programa) para que dichos datos queden en una sola fila o columna. gracias. -- [[alternative HTML version deleted]]

Hello, Newbie question: how do you capture groups in a regexp in R? Let's say I have txt="blah blah start=20080101 end=20090224". I'd like to get the two dates start and end. In Perl, one would say: my ($start,$end) = ($txt =~ /start=(\d{8}).*end=(\d{8})/); I've tried: txt <- "blah blah start=20080101 end=20090224" m <-