similar to: Memory problem with jpeg() and wide jpegs

Hi I have seen a few posts to this list regarding problems accessing the x11() device over cgi - namely, when trying to create a graphic using the jpeg() function, everything is fine from the command line but it won't work over cgi, producing the error: "Unable to open connection to X11 display" Has anyone actually solved this particular problem satisfactorily? Please reply

Hi I have recently installed and implemented Xvfb (X virtual frame buffer) so that I can create jpegs using R over CGI (SUSE Linux 8.1 and Apache 1.3). I have noticed that in order to do this, a file (Rplots.ps) is created in my cgi-bin directory everytime a cgi script is run. This could cause problems though as I have a multi-user system where it is possible that two different users will run

I met a trouble in setting jpeg a large size. for example, when i use jpeg(height=65526), a problem "Error in devga(paste("jpeg:", quality, ":", filename, sep = ""), width, : unable to start device devga In addition: Warning message: Unable to allocate bitmap" occurs. if a smaller size is set, no errors occur. I'm using R 1.8.0 on win2k. Thank

Dear R list, I do encounter the following problem by generating either a png-file (example below) or a jpeg-file: By employing 'box(which="outer")' a box is drawn, except for the right line. If I generate the plot without the 'box(which="outer")', a line at the bottom in the graphics file still appears. However, both plots are displayed correctly in the R

Hi I am having some problems getting my heatmap to be the right size! Let me explain. I am experienced at getting an hclust or a dendrogram object to be the right size. For example, I have a dataset which has 4000 rows, which I clustered using hclust and I wanted to plot it as a horizontal dendrogram. So I used jpeg(), set the image height to be 4000 and plotted the dendrogram and got the

Hi Windows XP, R 2.0.1. I am drawing a very large barplot using jpeg() - setting the width to 10,000 as there are over 5000 bars. This all works fine and I get exactly what I want - except there is a huge bit of white space between the Y-axis and the first bar - so much in fact that I have to scroll two screens from the Y-axis before I see the first bar. After that the bars are evenly spaced

Hi When I use plot(hclust(dist..)...)...) etc to create a dendrogram of a hierarchial cluster analysis, I end up with a vertical tree. What do I need to do to get a horizontal tree? Also, my users are used to seeing trees who's leaves all "end" at the same place (eg. Like in minitab). Is this possible in R? Thanks Mick Michael Watson Head of Informatics Institute for Animal

Hi Sorry to ask such a basic question. I have a list, each element of which is a vector of two values. What I actually want is a matrix with two columns, and one row per element of the list. Obviously I have tried as.matrix(), and as.vector() but I didn't expect the latter to work. I feel so lame asking this. Any suggestions? Mick

Hi Thanks once again for your help, I do appreciate it..... however.... Here is what I get with your test.... (under tcsh - i normally use bash, but I will keep everything the same) users/mwatson> env http_proxy=http://wwwcache.bbsrc.ac.uk:8080/ R >options(internet.info=0) >update.packages() trying URL `http://cran.r-project.org/src/contrib/PACKAGES' unable to connect to

Hi When I give the command: > heatmap.2(as.matrix(d),Rowv=as.dendrogram(hc.gene),Colv=FALSE,scale="row ",trace="none",col=greenred.colors(79)) The resulting heatmap has re-ordered my columns! This is time-course data, and I don't want my columns re-ordered! Note from the help: Rowv: determines if and how the _row_ dendrogram should be reordered.

Hi Forgive my ignorance. I am selecting a column of a data.frame using the column name, and I want to know what the resulting column "is". My data frame is called "submin" and the column name is held in a variable called "display.gname" Eg: > is.data.frame(submin) [1] TRUE > is.data.frame(submin[,display.gname]) [1] FALSE >

Hi I did a google search on this and came up with nothing. OK, in the latest release of R for windows, I want to change the gui to SDI mode. Edit -> GUI preferences Choose SDI Apply I get the message about properties not being able to be changed on a running console, and that I need to save. So I click Save, and am met with a "Save As" dialogue box with the default file called

Hi I have a complicated plot which has a potentially large legend. What I want to do is actually create the legend in a new window. Has anyone done this before? I'd like to be able to create a window with just the legend in it, and have it so the window is just the right size etc. I'm sure someone must have done this already? If not, any tips would be welcome. Thanks Mick

Quite a simple one really! When I run boxplot(), the labels on the X axis are horizontal, and I want them vertical. So I did: par(las=3) boxplot(...) And my labels just aren't there anymore.... Any help???

Sorry to ask a (probably) dumb question, but I am trying to install XML package on Windows XP, R 2.0.1, and I get the error: "This application has failed to start because libxml2.dll was not found. Re-installing the application may fix this problem" > library(XML) Error in dyn.load(x, as.logical(local), as.logical(now)) : unable to load shared library

Hi We have touched on this before, but I don't think I quite got it right. So I have a list, each element of which is a a vector of 2 numbers: > l2 $cat000_a01 [1] 0.3429944 4.5138244 $cat000_a02 [1] 0.1929336 4.3064944 $cat000_a03 [1] -0.2607796 4.1551591 What I actually want to convert this into is a matrix with the names (cat000_a01 etc) as row names, the first element of each of

Hi I have data from 12 subjects. The measurement is log(expression) of a particular gene and can be assumed to be normally distributed. The 12 subjects are divided into the following groups: Infected, Vaccinated, Lesions - 3 measurements Infected, Vaccintaed, No Lesions - 2 measurements Infected, Not Vaccinated, Lesions - 4 measurements Uninfected, Not Vaccinated, No Lesions - 3 measurements

Hi I've been reading the help for by and aggregate but can't get my head round how to do this. I have a data frame - the first three columns are replicate measurements, then the next 3 are replicates etc up to 36 (so 12 variables with 3 replicate measurements each). I want to compute the mean for each of the 12 variables, so that, for each row, I have 12 means. A grouping variable

Hi I can't get R to connect to the internet. I am running R 1.7.1 on Windows XP and whenever I try to download packages etc from within R using the internet, it fails. OK so I am behind a firewall and use a proxy server.... SO, if I go to my MS-DOS prompt and type: RGui.exe --internet2 everything works.... BUT i can't set up a shortcut for this as Windows (I hate Windows) complains

Hi This is a difference between the way matrices and data frames work I guess. I want to replace the NA values in a data frame by 0, and the code works as long as the data frame in question actually includes an NA value. If it doesn't, there is an error: df <- data.frame(c1=c(1,1,1),c2=c(2,2,NA)) df[is.na(df)] <- 0 df df <- data.frame(c1=c(1,1,1),c2=c(2,2,2)) df[is.na(df)] <-