similar to: "sequence of factor settings"?

Hello together, i have a data.frame, which i want to filter with numbers in a vector. I have a vector (Top10) with these numbers: [1] 205 302 156 378 235 328 183 375 296 374 and i have a data.frame with a Column (CU_NO) with all my Customer numbers. How can i filter this data.frame, with the Numbers in my vector. this one doens't work:

At 2013-08-12 01:18:30,"Tobias Grosser" <tobias at grosser.es> wrote: >On 08/10/2013 06:59 PM, Star Tan wrote: >> Hi all, >> >> I have evaluated Polly's performance on LLVM test-suite with latest LLVM (r188054) and Polly (r187981).  Results can be viewed on: http://188.40.87.11:8000. > >Hi Star Tan, > >thanks for the update. >

Hi all,I'm trying to build a SpatialLines object from a list that contains 124 river segments. Each segment in the list contains the x,y coordinates. I'm using the following code to create the SpatialLines object, but it just retrieves one segment. Any suggestions? test.func = function(x){ ??? for (i in 1:length(x)) {??????? tt[[i]] <- x[i]; tt[[i]]? = Line(tt[[i]]); tt[[i]]? =

Hi Ashraf, It is not obvious to me what your structures are but one problem in your function is the assignment tt1 <- SpatialLines(list(tt[[i]])). This will set tt1 to just have one item. Consider the following test.func <- function(x) { tt1 <- list() for ( i in ... ) { ... tt1[[i]] <- SpatialLines(tt[[i]]) } return(tt1) } HTH, Eric On Mon, Sep 25,

Hi Eric, Thanks for the help.But this will not solve the problem as it will generate a list and what I need is an object of class sp using SpatialLine function from sp package.So, I need to convert each matrix to coordinates and then to a line and then to a spatial line as figured in the code. My data structure is a list of 141 matrices.Each matrix represents coordinates of the river lines

I am the proud owner of a new laptop since my old one died the other day. Currently I have a dual-boot Windows 7 Home and Ubuntu 12.04 . I'll leave the Windows problems for another post. I know practically nothing about Linux so I am probably doing something stupid but ... at the moment I cannot seem read or write files in Ubuntu. I am not having any problem saving other documents to the

The following creates a time series tt1 whose values rise from 1 to 20 and another time series tt2 each of whose values are 10 larger than the corresponding value in tt1. When we attempt to bind them together as columns, the entry after Dec 1960 is erroneously listed as NA 1960 instead of Jan 1961. If n is changed to either 19 or is changed to 21 in the example below, the example suddenly

Dear All I am trying to graph a proportion and CI95% by a factor with ooplot (any other better solution ?) It works well until I try to add the confidence interval. this is the error message and and a description of the data: > dat1 PointEst TT1 1 3.6 TT2 2 5.0 TT3 3 5.8 TT4 4 11.5 TT5 5 7.5 TT5 6 8.7 TT7 7 17.4 > dat2

Dear All, I have the following data coming out from s <- with(final, summarize(norm, llist(gtt,fdiab), function(norm) { n <- sum(!is.na(norm)) s <- sum(norm, na.rm=T) binconf(s, n) }, type='matrix') ) ie gtt fdiab norm.norm norm.norm2 norm.norm3 18

At 2013-08-09 10:20:46,"Tobias Grosser" <tobias at grosser.es> wrote:>On 08/08/2013 06:27 PM, Star Tan wrote: >> At 2013-08-08 22:28:33,"Tobias Grosser" <tobias at grosser.es> wrote: >>> On 08/08/2013 01:29 AM, Star Tan wrote: >>>> Hi all, >>>> >>>>

On 08/08/2013 07:45 PM, Star Tan wrote: > At 2013-08-09 10:20:46,"Tobias Grosser" <tobias at grosser.es> wrote:>On 08/08/2013 06:27 PM, Star Tan wrote: >>> At 2013-08-08 22:28:33,"Tobias Grosser" <tobias at grosser.es> wrote: >>>> On 08/08/2013 01:29 AM, Star Tan wrote: >>>>> Hi all, >>>>>

Prof Nash, Prof Galanos Is it possible to use a generic code stub in front of packages that use optimx to improve optimx use or curtail it according to the requirements? Best Regards Amit +91 7899381263 ________________________________________________________________________ Please request Skype as available 5th Year FPM (Ph.D.) in Finance and Accounting Area Indian Institute

How can I extract only the time component from an POSIXlt object? For example if I try the following it still returns both the date and time... >as.POSIXlt(tr.date[1]) [1] "2010-10-18 21:46:53" >as.POSIXlt(tr.date[1],"%H:%M:%S") [1] "2010-10-18 21:46:53" round and trunc don't help... is there an "as.Time" equivalent to as.Date ? Thanks,

Hi, I was trying to get hyperlinks using xtable, but couldn't get the hyperlinks to function properly. For example, if I use ## Try to link NY times website to every figure in column 4 mat <- matrix(1:43,6,5) mat[,5] <- "http://nytimes.com" for(i in 1:nrow(mat)){ strr <- paste('<a href="', mat[i,5],'">', mat[i,4], '</a>',

On 08/08/2013 06:27 PM, Star Tan wrote: > At 2013-08-08 22:28:33,"Tobias Grosser" <tobias at grosser.es> wrote: >> On 08/08/2013 01:29 AM, Star Tan wrote: >>> Hi all, >>> >>> >>> I have summarized the top 10 compiler passes for Polly when compiling LLVM test-ssuite. Results can be viewed on: >>>

Dear R users I am trying to exporting plots from R to an external folder, or to the working directory, but the resolution of plots (pdf file) largely reduced. Any way I can get same quality as my original plots?? e.g. I tested the plotting part using one example and obtained pretty good (/readable) quality for each plot in the (4*4) multiple graph. But when I did the loop and tried to export

Here's one way. Suppose your "time series" is in a vector called "x". top10 <- sort(x, decreasing=TRUE)[1:10] mean.index <- mean(which(x %in% top10)) HTH, Andy > -----Original Message----- > From: James Brown [mailto:jdb33 at hermes.cam.ac.uk] > Sent: Tuesday, September 23, 2003 7:51 AM > To: r-help at stat.math.ethz.ch > Subject: [R] Rank and

At 2013-08-08 22:28:33,"Tobias Grosser" <tobias at grosser.es> wrote: >On 08/08/2013 01:29 AM, Star Tan wrote: >> Hi all, >> >> >> I have summarized the top 10 compiler passes for Polly when compiling LLVM test-ssuite. Results can be viewed on: >>    

Hello, I have a list (mode and class are list) in R that is many elements long and of the form: >length(list) [1] 5778 >list[1:4] $ID1 [1] "num1" $ID2 [1] "num2" "num3" $ID3 [1] "num4" $ID4 [1] NA I'd like to convert the $ID2 value to be in one element rather than in two.?? It shows up as c(\"num2\", \"num3\") if I try to use

I'm implementing a custom bootstrap resampling procedure in R. This procedure resamples clusters of data points obtained by different subjects in an experiment. Since the bootstrap samples need to have the same size as the original dataset, `target.set.size`, I select speakers compute their data point contributions to make sure I have a set of the right size. set.seed(1)