similar to: how to test the existence of a name in a dataframe

Displaying 20 results from an estimated 6000 matches similar to: "how to test the existence of a name in a dataframe"

2013 May 29
0
"Unable to optimize" error returned in factanal using R-3.0.1, Windows 64 bit, and OpenBLAS
Hello, I have been trying for weeks to compile a 64-bit Rblas. I started with ATLAS where I have had success in the past, but 64 bit was not behaving, and as each compilation takes between 9 and 12 hours, "test, check, and revise" was not going to be really viable. I therefore switched to OpenBLas (OPBL). I was successful in compiling R-3.0.1 and an OPBL-based BLAS for Windows 64bit
2007 Apr 20
2
sorting data in R
hello, I'd like know how to sort a data frame in R for example how I should do to sort by Catholic with swiss data frame like below thanks Fertility Agriculture Examination Education Catholic Infant.Mortality Courtelary 80.2 17.0 15 12 9.96 22.2 Delemont 83.1 45.1 6 9 84.84 22.2
2007 May 09
1
step() in sink() and Sweave()
Dear developers, I just noticed that step() function currently prints the current model using message(), but the resulting model using print(). The relevant commands within the step() body are: if (trace) message("Start: AIC=", format(round(bAIC, 2)), "\n", cut.string(deparse(as.vector(formula(fit)))), "\n") (with example() output:) Start: AIC=190.69
2002 Feb 12
1
Best Subsets regression
Hi, I have found a minor problem with leaps(). In 1.3.1 under Windows 2000 I seem to only be able to obtain values for one statistic at a time. That is choosing method=c("Cp","adjr2","r2") just gives Cp values. To mimic the output of Minitab's MTB > BReg 'Fertility' 'Agriculture'-'Infant.Mortality' ; SUBC> NVars 1 5; SUBC>
2010 Nov 16
1
how to do linear regression when dimension is high
Hi I am a newbie in R. I have data with dim of 20. How to use lm if i want to do regression with the whole design matrix? My y is the first column. the left are xs. Thanks a lot. -- View this message in context: http://r.789695.n4.nabble.com/how-to-do-linear-regression-when-dimension-is-high-tp3045167p3045167.html Sent from the R help mailing list archive at Nabble.com.
2012 Jan 21
1
Function for multiple t tests
Hi, I want to run t.test() for several variables among two groups, and I would like to skip the tedious process of collecting information to assemble a table, but I am not sure if the function I want already exists. Any suggestion would be appreciated. I have a working example, as required by the posting guide: my_swiss = swiss[-1,] my_swiss$facto = rep(1:2,nrow(my_swiss)/2)
2004 Oct 04
11
inverse function of order()
I have: d <- sample(10:100, 9) o <- order(d) r <- d[o] How I can get d (in the original order), knowing only r and o? Thanks - Wolfram
2002 May 03
2
sub() of matrix returns a vector and not a matrix
Is there a simple possibility to become directly a matrix from a call of sub() on a matrix? --------- START OF LOGFILE ---------------- # R 1.4.1 > a <- matrix( letters[1:6], 2, 3 ) # a is a matrix > print( a ) [,1] [,2] [,3] [1,] "a" "c" "e" [2,] "b" "d" "f" > b <- sub( '(.)', '-\\1-', a )
2006 Nov 29
4
Why the factor levels returned by cut() are not ordered?
What is the reason, that the levels of the factor returned by cut() are not marked as ordered levels? > is.ordered( cut( breaks=3, sample(10 ) ) ) FALSE > help(factor) ... If 'ordered' is 'TRUE', the factor levels are assumed to be ordered. ... Wolfram
2005 Apr 11
6
How to change letters after space into capital letters
What is the easiest way to change within vector of strings each letter after a space into a capital letter? E.g.: c( "this is an element of the vector of strings", "second element" ) becomes: c( "This Is An Element Of The Vector Of Strings", "Second Element" ) My reason to try to do this is to get more readable abbreviations. (A suggestion would be to
2001 Apr 21
0
Re: PR#886: Error (?) in documentation of 'swiss'
>From k.j.mcconway@open.ac.uk Wed Mar 28 16:46:49 2001 Hardly crucial, but I've come upon a potential error in the documentation of the 'swiss' datafram in the R base package. The description accurately matches what is said in the Mosteller and Tukey source quoted, but according to the data archived at Princeton (links from http://opr.princeton.edu/archive/eufert/switz.html), the
2003 Jan 24
4
new function: showcolors {base}
I propose to add a function that allows to display colors selected by a text pattern or by color vectors in a plot. Wolfram Fischer #--- showcolors.R showcolors <- function( col = "red" , index = NULL , pie = TRUE , lwd = 6 , cex = 1.0 , main = NULL , sub = NULL , ... ){ n.colors <- length( col ) if( n.colors > 1 ){ main <- deparse( substitute( col ) )
2001 Apr 21
1
Re: PR#886: Error (?) in documentation of 'swiss'
No, you're quite right, I was wrong. I must have been very confused when I put up the first 'bug' report, #886. I noticed my error a couple of days after and put up a comment to that effect on R-bugs, but it seems to have vanished (or alternatively I did that wrong as well). I agree with you on the criterion for the choice of districts as well. There remains a minuscule discrepancy
2003 Aug 29
2
length() and nchar()
I would propose to add " See also: `nchar' for counting the number of character in character vectors. " to the helpfile of length(), because it is rather difficult to find nchar() if one has only search terms as "length", "len", "strlen" in mind. Sincerly Wolfram Fischer
2005 Apr 15
4
function corresponding to map of perl
Is there a function in R that corresponds to the function ``map'' of perl? It could be called like: vector.a <- map( vector.b, FUN, args.for.FUN ) It should execute for each element ele.b of vector.b: FUN( vector.b, args.for.FUN) It should return a vector (or data.frame) of the results of the calls of FUN. It nearly works using: apply( data.frame( vector.b ), 1, FUN,
2017 Jul 06
2
attributes on symbols
The multcomp package has code in multcomp:::expression2coef that attaches the 'coef' attribute to symbols. Since there is only one symbol object in a session with a given name, this means that this attaching has a global effect. Should this be quietly allowed or should there be a warning or an error? E.g., str(quote(Education)) # symbol Education lmod <- stats::lm(Fertility ~ .,
2007 Feb 15
2
Problems with 'delay'/'delayedAssign' when installing data package
I downloaded: http://www.bioconductor.org/data/metaData/hgu95av2_1.7.0.tar.gz described as: Package: hgu95av2 Title: A data package containing annotation data for hgu95av2 Version: 1.7.0 Created: Wed Jan 12 16:57:23 2005 Author: Lin,Chenwei Description: Annotation data file for hgu95av2 assembled using data from public data repositories Maintainer:
2006 Dec 08
1
lattice: defining an own function using args for "formula" and "groups"
x.fun <- function( formula, data ) dotplot( formula, data ) x.grp <- function( formula, groups, data ) dotplot( formula, groups, data ) data( barley ) > x.fun( variety ~ yield | site, data=barley ) # no problem > dotplot( variety ~ yield | site, groups=year, data=barley ) # no problem > x.grp( variety ~ yield | site, groups=year, data=barley ) object "year" not found
2008 Sep 17
2
Command Prompt Question
Could someone please tell me how to stop the package/function name from being included before the command prompt? This started happening today after I made some changes to my Rprofile.site file and I don't know why. For example: if I enter example(AIC), instead of just getting the regular '>' before each output line, I get 'AIC>' instead. I only want the '>'
2002 May 21
1
plotting functions with line width (lwd) as vectors
If I want to plot different widths of line segments or arrows I have to program loops to plot each line apartly. Is that right? n <- 6 x <- 1:n y <- rnorm(1:n) q <- ( x %% 3 + 1 ) * 2 plot( x, y, cex=q ) for( i in 1:(n-1) ) lines( x[i:(i+1)], y[i:(i+1)], lwd=q[i], col=q[i] ) Would it not be possible to make plotting functions accept vectors of line widths (as they