similar to: Changing the Y graph scale Maximum value.

Displaying 20 results from an estimated 3000 matches similar to: "Changing the Y graph scale Maximum value."

2009 Aug 07
3
How do I plot a line followed by two forecast points?
Good day all, I'm trying to plot a continuous line plot, which is followed by two forecast points eg. one forecast point is 12 months out, and another 24 months out from the last date of the line plot. In my attempts so far, the second plot (the forecast points) is scaled against a new axis scale, thus the two plots are not directly comparable (I need the forecast points to be scaled
2004 May 06
1
plot(hist.default(1:10,plot=F)) error.
Hi! How to find out which plot function is used when i call plot(hist.default(1:10,plot=F)) and all works fine ? The reason why I would like to know it is that after loading some self written R functions > plot(hist.default(1:10,plot=F)) Error in xy.coords(x, y, xlabel, ylabel, log) : x and y lengths differ > traceback() 5: stop("x and y lengths differ") 4: xy.coords(x, y,
2017 Sep 19
3
Graph f(x) = 1/x
Dear All: good morning I am trying to graph the function y=f(x)=1/x over the interval (-5,5). But I am getting an error message. Please see below. I am getting the error message: *Error in xy.coords(x, y, xlabel, ylabel, log) : * * 'x' and 'y' lengths differ* x x <- seq(-5, 5, 0.01) y < 1/x plot(x,y, type='l', xlim=c(-5, 5), ylim=c(-5, 5), xlab = "x",
2004 Nov 23
6
Weibull survival regression
Dear R users, Please can you help me with a relatively straightforward problem that I am struggling with? I am simply trying to plot a baseline survivor and hazard function for a simple data set of lung cancer survival where `futime' is follow up time in months and status is 1=dead and 0=alive. Using the survival package: lung.wbs <- survreg( Surv(futime, status)~ 1, data=lung,
2004 Jul 13
2
help with as.function
HI, sorry but i don't understand how to make a function with as.function() formula<-"2+3*x" formu<-as.symbol(formula) > formu 2+3*x formul<-as.function(alist(x=,formu)) curve(formul,1,5,col="blue") Error in xy.coords(x, y, xlabel, ylabel, log) : x and y lengths differ > typeof(formul) [1] "closure" and not plot the curve function, Why?
2010 Jan 09
2
Plotting numeric values against non numeric items
Hi i want do a line graph. My y axis contains numeric values. My x axis contains non numeric statements. This is what i want the graph to look like. When i try to plot this graph on R it comes up with the following error message: "Error in plot.window(...) : need finite 'xlim' values In addition: Warning messages: 1: In xy.coords(x, y, xlabel, ylabel, log) : NAs introduced by
2010 Sep 22
2
How to fix error: 'x' and 'y' lengths differ
Hi, im a student so still very new to R. Hope someone could help me out here =) They are 3 slug control products, bustaslug, product X and Y. Im ask to explore the data by plot() and tapply(). But when i try to plot or use the tapply command, it tells me that the x and y lengths differ. so im thinking its because the data is unbalanced? Is there a simple command that i could use to fix this?
2009 Jun 11
2
Tables without names
A table without names displays like a vector: > unname(table(2:3)) [1] 1 1 1 and preserves the table class (as with unname in general): > dput(unname(table(2:3))) structure(c(1L, 1L), .Dim = 2L, class = "table") Does that make sense? R is not consistent in its treatment of such unname'd tables: In plot, they are considered erroneous input: >
2008 Sep 04
1
Building a time series.
I have a need to build a time series and there are a couple of aspects about the time series object that are confusing me. First it seems that ts.union is not doing what I would expect. For example: x0 <- rep(0,10) x1 <- rep(1,10) xt0 <- ts(x0, frequency=10) xt1 <- ts(x1, frequency=10) st2 <- ts.union(xt0, xt1) > xt2 Time Series: Start = c(1, 1) End = c(1, 10) Frequency = 10
2010 Jun 07
1
Patch for legend.position={left,top,bottom} in ggplot2
Hi Hadley and everyone, here's a patch for ggplot2 that fixes the behavior of opts(legend.position={left,top,bottom}). If you try the following code in an unmodified ggplot2 options(warn = -1) suppressPackageStartupMessages(library("ggplot2")) data <- data.frame( x = c(1, 2, 3, 4, 5, 6), y = c(2, 3, 4, 3, 4, 5), colour = c(TRUE, TRUE, TRUE, FALSE, FALSE, FALSE))
2008 Oct 20
2
error message when plotting survival curves
I am trying to plot survival curves using the following code as an example: >rs1799964.coxph<-(coxph(Surv(sassurvmonths,status)~age+stage+rs1799964_TNFA,method="efron")) >plot(rs1799964.coxph,lyt=c(1,3),xlab="Survival in Months",ylab="Proportion Surviving") I am gettingthe following error message: >Error in xy.coords(x, y, xlabel, ylabel, log) :
2008 Mar 23
2
(no subject)
Is there any way to use more than one color or shape in the same plot. I would like to make the points different colors for various levels of a variable. I have tried a simple 'if' statement in the plot command, but I get an error message. Here is what I have tried and the error message I get: > plot(test, if(test[,1]<8) col="steelblue2" else col="wheat2")Error
2010 Mar 31
3
creating a variable using concatenation
A general problem i run into, i know there must be a simple solution. I like to create a variable by appending a 1 for example, (i need to loop later on from 1 to X, thus the reason for this). So i assign the variable vplot with this value, however it has quotes and when i use it in a barplot, it throws an error. but the tcenter$X1 does exist, its an element of a data frame. So if i type
2005 Oct 03
1
Error in xy.coords(x, y, xlabel, ylabel, log) : x and y lengths differ
I am currently trying to use R to construct a regression model to explain output based on temperature. I have combined my output and temp data into a notepad file. there is no problem with loading the data into R. > data.df output temp 1 850 17 2 849 17 3 905 17 4 925 17 5 1043 19 6 1104 20 7 1097 18 8 979 19 9 926 18 10 1133 18 ~~ ~~ 240 1124
2004 Apr 07
3
More user-friendly error message needed.
When I tried the following commands, I got a strange message. > x<-data.frame(y=c(1:10)) > plot(x$z) Error in xy.coords(x, y, xlabel, ylabel, log) : x and y lengths differ "The data frame, x, does not have a field named z." may be better user-friendly message for this kind of common error. Daehyok Shin
2004 Apr 07
3
More user-friendly error message needed.
When I tried the following commands, I got a strange message. > x<-data.frame(y=c(1:10)) > plot(x$z) Error in xy.coords(x, y, xlabel, ylabel, log) : x and y lengths differ "The data frame, x, does not have a field named z." may be better user-friendly message for this kind of common error. Daehyok Shin
2010 Nov 27
3
How to load data file without attribute names?
Hi all, I'm new to R and I'm struggling with loading a data file without attribute names, like: 1,72,0,5.6431,28.199 1,72,0,12.666,28.447 1,72,0,19.681,28.695 1,72,0,25.647,28.905 It has no names for the columns nor the rows. I tried data <- read.table(path,header = FALSE, sep = ",") and it seems to work. But later, when I try qqnorm to plot the graph, it gives me the
2009 Oct 27
4
automatically adjusting axis limits
Dear R users, I am a newbie. Just switched from MATLAB. So thanks a lot for your patience. I have 50000 spectra collected in field. Each spectra has two columns : Wavelength (56) and the actual measurement. Each measurement came in a different .txt file on disk (50000 files in total). I wrote a script that reads every spectra in a for loop and constructs two variables : Wavelength (56) and
2010 Jul 17
2
Plot error
Hi guys, I am a newbie to R, so apologies in advance. I created this simple table in excel, saved in tab delimited .txt: name value_1 value_2 1 bill 1 4 2 ben 2 2 3 jane 3 1 >test <-read.table("\path\to\file", sep="\t", header=TRUE) >x <-c(seq["value_1"]) >y <-c(seq["value_2"])
2012 Jul 31
3
time series line plot: Error in plot.window(...) : invalid 'xlim' value
Hello, This should be pretty simple but I cannot get it right. Please point to the right code. Thanks. > last <- read.csv(file.path(dataDir,"plot1.csv"), as.is=T,stringsAsFactors = FALSE) > last date r_wvht 1 8/6/2008 0.9766667 2 8/8/2008 0.7733333 3 8/11/2008 1.4833333 4 8/13/2008 1.5766667 5 8/14/2008 1.3900000 6 8/18/2008 0.7800000 7 8/20/2008