similar to: decompose a correlation matrix

Displaying 20 results from an estimated 2000 matches similar to: "decompose a correlation matrix"

2004 Nov 19
1
Rd and document formatting
I am trying to compose some documentation for a package I hope to release soon. However when I do the following: R CMD Rd2dvi --pdf mypackage.Rd I get two mainly blank pages prepended to the top of the document - the only text on either (at the top of the first page) is as follows: hyperindex,colorlinks,pagebackref,linktocpage,plainpages=false,linkcolor=Blue
2004 Feb 23
1
HTTP Post connections in R
Hi, Is there any existing functions to open an HTTP connection and HTTP POST some R data? like <form method="post" enctype="multipart/form-data"> etc. </form> but within R. Thanks, ===== Nathan Whitehouse Statistics/Programming Baylor College of Medicine Houston, TX, USA nlwhitehouse at yahoo.com http://rho-project.org: rho- open source
2004 Sep 10
1
R conversion
I am a newcomer to R trying to convert a SAS program to R. Does anyone know if there is a functional equivalent of the SAS 'Factor' procedure? For example in SAS: proc factor DATA=cor method=principal rotate=varimax proportion=0.9 scree where 'cor' is a correlation matrix (as in the R 'cor' function) This should get you a list of eigen values as well as a factor
2010 Jan 30
2
convert data frame of values into correlation matrix
Hi Group, Consider a data frame like this: mylabel1 <- rep(c("A","B","C"),each=3) mylabel2 <- rep(c("A","B","C"),3) corrs <- c(1,.8,.7,.8,1,.7,.7,.7,1) myData <- data.frame(mylabel1,mylabel2,corrs) myData mylabel1 mylabel2 corrs 1 A A 1.0 2 A B 0.8 3 A C 0.7 4 B
2007 Mar 08
2
augPred in lmer
I read the posts about augPred with lme, but does anyone know if there is a correlate for augPred for lmer? Specifically, I want to be able to use it to plot projections for all groups in an lmer class object using plot(augPred(lmer.object)). Thanks, Kyle *************************************** J. Kyle Roberts, Ph.D. Baylor College of Medicine Center for Educational Outreach One Baylor Plaza,
2012 Mar 20
2
igraph: decompose.graph: Error: protect(): protection stack overflow
I just got this error: > library(igraph) > comp <- decompose.graph(gr) Error: protect(): protection stack overflow Error: protect(): protection stack overflow > what can I do? the digraph is, indeed, large (300,000 vertexes), but there are very many very small components (which I would rather not discard). PS. the doc for decompose.graph does not say which mode is the default. --
2007 Feb 27
2
ts; decompose; plot and title
Is there any way to give a "decent" title after I plot something generated by decompose? For example: # generate something with period 12 x <- rnorm(600) + sin(2 * pi * (1:600) / 12) # transform to a monthy time series y <- ts(x, frequency=12, start=c(1950,1)) # decompose z <- decompose(y) # plot plot(z) Now, the title is the ugly "Decomposition of additive time
2008 Feb 02
1
Meaning of Error Message from decompose
Greetings, For the following quarterly data I did a classical decomposition by hand in a spreadsheet and got reasonably similar results using Minitab 15. x 1 36 2 44 3 45 4 106 5 38 6 46 7 47 8 112 9 42 10 49 11 48 12 118 13 42 14 50 15
2009 Jul 06
1
Decompose function : calculation of each component
Hello, I'd like to know how R does calculate each component in the decompose() function? More precisely, how is calculated the final trend component in this function? Thanks for your answer Myriam -- View this message in context: http://www.nabble.com/Decompose-function-%3A-calculation-of-each-component-tp24362207p24362207.html Sent from the R help mailing list archive at Nabble.com.
2011 Aug 24
2
regarding changing of title of decompose graph
Hi All, I am new to this forum. I have just started learning R. When i use plot(decompose(x)), i am getting the title " Additive time series decomposition". How to make this title off and change to some other title. Any help regarding this is highly appreciated. With sincerer regards, Upananda -- View this message in context:
2009 Feb 22
1
split/decompose lines
Dear R users, I have a very simple problem but I can't find the function in R to deal with it. I need to split (or decompose) one line into many lines using one field as a reference. I have a table with the following format: A B Frequency 23 3 2 24 2 5 25 1 3 And need to split each line into several lines according to the frequency to achieve something like this: A B
2004 May 17
1
Problem with package SJava
Hello all, I'm trying to run SJava package (0.65 modified downloaded from : http://stats.math.uni-augsburg.de/iPlots/alpha/) on windows NT 2000 and R 1.8.01. I have also downloaded the PDF Calling R from Java and when I want to execute the following code: import org.omegahat.R.Java.*; import java.io.*; public class Essai{ public static void main (String [] args) { REvaluator e = new
2010 Oct 12
1
Help with STL function to decompose
Hi everyone. I'm having some troubles with STL function to decompose some data. My issue is that I have monthly data from September 2005 up to August 2010 i. e. 60 observations. I define it in the following way: *u<-read.csv("C:/CELEBREX.csv",header = TRUE) u.ts<-ts(u, start=c(2005,9), frequency=12) * The issue is that when I try to use stl(u.ts, 'per') Then the
2004 Apr 29
1
I'm trying to use package ts (decompose). How do you set up the data/ See attached. thanks
InDATA <-read.table("C:/Data/May 2004/season.txt",header=T) X <- decompose(InDATA) print(X) Period Connections Q1 67519 Q2 69713 Q3 68920 Q4 69452 Q1 70015 Q2 59273 Q3 57063 Q4 65596 Q1 73527 Q2 58586 Q3 69522 Q4 60091 Q1 51686 Q2 63490 Q3 55702 Q4 53200 Q1 51033 Q2 48175 Q3 52709 Q4 50106 Q1 50855 Q2 43466 Q3 48190 Q4 41702 Q1 48747 Q2 51441 Q3 42537
2006 Jul 05
3
Invoking SAS in order to use sas.get
I am trying to use the sas.get function to bring a SAS dataset into R. After calling the sas.get function I got an error message stating that 'sas' is not a recognized internal or external command, etc. I am guessing that I need to specify the internal command to invoke SAS in the sasprog option for the sas.get function, but I don't know how to determine what that command might be.
2006 Jun 16
6
modeling logit(y/n) using lrm
I have a dataset at a hospital level (as opposed to the patient level) that contains number of patients experiencing events (call this number y), and the number of patients eligible for such events (call this number n). I am trying to model logit(y/n) = XBeta. In SAS this can be done in PROC LOGISTIC or GENMOD with a model statement such as: model y/n = <predictors>;. Can this be done
2008 Oct 01
3
lapply where each list object has multiple parts
Hi. I have a list where each object in the list has multiple parts. I'd like to take the mean of just one part of each object. Is it possible to do this with lapply? If not, can you recommend another function? Thanks. eric > x1 <- c(0,1,2,3) > x2 <- c(7,8) > x3 <- c(2,6,6,8) > x4 <- c(4,8) > > Lst1 <- list(label1 = x1,label2 = x2) > Lst2 <-
2002 Sep 30
2
Decompose numerical factor into orthog. poly parts
Consider the following analysis of a class experiment done as a Latin Square: > spinner <- gl(4,4,16,label=c("Murray","Angela","Shasha","Stephen")) > order <- gl(4,1,16) > treat <- scan() 1: 1 2 4 3 5: 4 3 1 2 9: 3 4 2 1 13: 2 1 3 4 17: Read 16 items > coin <-
2017 May 23
2
[imaptest] Explaining errors
Hi, I'm an Apache James committer and we are curious to use imaptest in order to validate our IMAP protocol implementation. I'm using the nightlybuild : imaptest-20170506 I follow the examples given in the /T/ /est IMAP server compliancy/ examples https://imapwiki.org/ImapTest/Examples. And I wanted to analyse the errors reported, here are some: Error: user1 at james.org[11]: seq too
2013 Feb 17
6
histogram
HI Elisa, You could use ?cut() vec1<-c(33,18,13,47,30,10,6,21,39,25,40,29,14,16,44,1,41,4,15,20,46,32,38,5,31,12,48,27,36,24,34,2,35,11,42,9,8,7,26,22,43,17,19,28,23,3,49,37,50,45) label1<-unlist(lapply(mapply(c,lapply(seq(0,45,5),function(x) x),lapply(seq(5,50,5),function(x) x),SIMPLIFY=FALSE),function(i) paste(i[1],"<x<=",i[2],sep="")))