similar to: R-2.0.0 CMD check . and datasets

Hi [MacOsX 10.4.6; R-2.2.1] I have a bundle that comprises three packages. I want to run R CMD check on each one individually, as it takes a long time to run on all three. I am having problems. The bundle as a whole passes R CMD check, but fails when I cd to the bundle directory and run R CMD check on a package directory. The whole bundle passes: octopus:~/scratch% R CMD check

Dear List please find on CRAN a new R bundle, BACCO, for Bayesian analysis of random functions, comprising two packages: emulator and calibrator. Package calibrator implements: ?Bayesian calibration of computer models?, M. C. Kennedy and A. O'Hagan 2001. Journal of the Royal Statistical Society B, 63(3) pp425-464 and package emulator implements: J. Oakley 2004. ?Estimating percentiles

Full_Name: Byron Ellis Version: R 1.9.0 (and 2.0.0) OS: Linux (Redhat Fedora Core) Submission from: (NULL) (140.247.241.197) It appears that `R CMD build` cannot handle spaces in the path when building packages for distribution. For instance: [ellis@net-78815 ~/Bayesian Networks]$ R CMD build bnsl * checking for file 'bnsl/DESCRIPTION' ... OK * preparing 'bnsl': * cleaning src *

Hi all, I am trying to setup a ZAP interface to do MF signaling for a handoff to a 911 tandem. The signaling I need to perform on the T1 is this: 9-1-1 Tandem: Wink CLEC end office: KP (Keypulse) NPA ST (Start) 9-1-1 Tandem: Wink CLEC end office: KP I (Info Digit) NXX XXXX ST As I'm not as familiar with the Zaptel configurabliity, I'm not really sure how to do this. Do I dial twice

Hi [this after some considerable thought as to R-help vs R-devel] I want to write a (S3) method for as.function(); toy example follows. Given a matrix "a", I need to evaluate trace(ax) as a function of (matrix) "x". Here's a trace function: tr <- function (a) { i <- seq_len(nrow(a)) return(sum(a[cbind(i, i)])) } How do I accomplish the following:

Hi I'm having difficulty making a package pass R CMD check. I need to read in a dataset from another package, modify it, and have the modified object available in the first package. help(require) says: The source code for a package that requires one or more other packages should have a call to 'require', preferably near the beginning of the source, and of course

Hi Anyone have experience with very large datasets and the Bayesian Network package, bnlearn? In my experience R doesn't react well to very large datasets. Is there a way to divide up the dataset into pieces and incrementally learn the network with the pieces? This would also be helpful incase R crashes, because I could save the network after learning each piece. Thank you.

Hi all, May i know does R has packages or code to run "Bayesian Relative Survival Analysis"? I have look through Bayesian Survival Analysis(2001) by Joseph George Ibrahim<http://www.google.com/search?tbo=p&tbm=bks&q=inauthor:%22Joseph+George+Ibrahim%22>, Ming-Hui Chen<http://www.google.com/search?tbo=p&tbm=bks&q=inauthor:%22Ming-Hui+Chen%22>, Debajyoti

Hi. I have a factor and I want to extract just those elements that appear exactly once. How to do this? Toy example follows. > a <- as.factor(c(rep("oak",5) ,rep("ash",1),rep("elm",1),rep ("beech",4))) > a [1] oak oak oak oak oak ash elm beech beech beech beech Levels: ash beech elm oak > table(a) a ash beech elm oak

Hi all, I am trying to concatenate words together to create new column names, using a loop. Please consider the following toy example: x <- matrix(nrow = 1, ncol = 3) colnames(x) <- c("a", "b", "c") x[1,1] <- "1" x[1,2] <- "2" x[1,3] <- "3" I would like to create a new matrix with column names based on the column names

Hi again everyone I have an arbitrarily dimensional array "a" and a list "jj" of length length(dim(a)). The elements of jj are vectors of indexes. How do I use do.call() to extract a[ jj[[1]], jj[[2]], jj[[3]], ...] ? Toy example follows: a <- matrix(1:30,5,6) jj <- list(5:1,6:1) I want the following a[ jj[[1]],jj[[2]] ] How do I do this? OBAttempts:

is there anyway that scaffold would read the database and I don''t have to specify any of the columns? it is really frustraiting specially when you''ve got a lotta cols and tables! I''d like to use rails for an enterprise app but not a toy app like all those apps in tutorials -- Posted via http://www.ruby-forum.com/. --~--~---------~--~----~------------~-------~--~----~

Hi I deal with long vectors almost all of whose elements are zero. Typically, the length will be ~5e7 with ~100 nonzero elements. I want to deal with these objects using a sort of sparse vector. The problem is that I want to be able to 'add' two such vectors. Toy problem follows. Suppose I have two such objects, 'a' and 'b': > a $index [1] 20 30 100000000

Hi I want to extract rows of a matrix, and preserve rownames even if only one row is selected. Toy example: R> a <- matrix(1:9,3,3) R> rownames(a) <- letters[1:3] R> colnames(a) <- LETTERS[1:3] R> a A B C a 1 4 7 b 2 5 8 c 3 6 9 Extract the first two rows: R> wanted <- 1:2 R> a[wanted,] A B C a 1 4 7 b 2 5 8 rownames come through fine. Now extract just

Dear Oscar,   Thanks for your help.It's so nice of you to explain this package to me.   Best Regards,   James LAN 发件人： Oscar Rueda [via R] <ml-node+s789695n4431468h14@n4.nabble.com> 收件人： monkeylan <lanjinchi@yahoo.com.cn> 发送日期： 2012年2月29日, 星期三, 下午 9:21 主题: Re: Bayesian Hidden Markov Models Dear James, The distances are normalized between zero and 1, so in your case all of

Hi. I'm having difficulty following the advice given in help(Recall). Consider the two following toy functions: f1 <- function(n){ if(length(n)>1){return(sapply(n,f1))} matrix(n,n,n) } f2 <- function(n){ if(length(n)>1){return(sapply(n,Recall))} matrix(n,n,n) } f1() works as desired (that is, f(1:3), say, gives me a three element list whose i-th element is an

I am an economist who decided it's high time that I learned some Bayesian statistics. I am following An Introduction to Modern Bayesian Econometrics by T. Lancaster. The book recommends using BUGS, but I wonder if there are any alternatives which are free software and fully integrated to R (which I have been using for more than two years for numerical computations.) I would like to learn

Dear useRs, French reading people among you might be interested by the following book: Noel, Y. (2013). Psychologie statistique avec R [Statistical psychology with R, in French], coll. PratiqueR, Paris: Springer. http://www.springer.com/psychology/book/978-2-8178-0424-8 This book provides a detailed presentation of all basics of statistical inference for psychologists, both in a fisherian

Hi I have a little vector function that takes a vector A of strictly positive integers and outputs a matrix M each of whose columns is the vector, modified in a complicated combinatorical way. Now I want to generalize the function so that A can include zeroes. Given A, I want to strip out the zeroes, pass it to my function, and pad M with rows at positions corresponding to the zeroes

Hi How do I make do.call() take "+" as a function for a list of more than two elements? Toy problem follows: f <- function(i){matrix((1:6)^i,2,3)} # Thus f() returns a matrix of size 2x3; I want to add a whole bunch of such matrices, # as in f(1) + f(2) + f(3) + f(4) # But: > do.call("+",sapply(1:4,f,simplify=FALSE)) Error in do.call("+",