Displaying 20 results from an estimated 9000 matches similar to: "[R/S] strange"
2004 Sep 02
1
[R/S] question re solution
Dear R and S People:
First, thank you to so many people for your help to my problem.
Here is the solution:
a <- 0.5*(outer(1:n3,1:n3,function(x,y,n2.){n2. - pmax(x,y)},n2.=n2))
I have one final pesky question, please:
During my experiments, I tried the following:
a <- 0.5*(outer(1:n3,1:n3,function(x,y,n2.=n2){n2. - pmax(x,y)}))
Why doesn't this work please?
thank you!
Sincerely,
2004 Sep 01
0
Re: [S] [R/S] strange solution
Hi, Erin:
A cleaner way is to pass "n2" to "outer" as a "..." argument, as
in the following modification of your code:
boot1 <- function(y,method="f",p=1) {
n1 <- length(y)
n2 <- n1*p
n3 <- n2 - 1
a <- 0.5*(outer(1:n3,1:n3,function(x,y, n2.){n2. - pmax(x,y)}, n2.=n2))
return(a)
}
y1 <- c( 9, 8, 7, 3, 6)
boot1(y=y1,p=4)
2004 Sep 01
0
[R/S] strange solution
Dear R and S People:
I ended up using the "assign" command, and things work in S+.
boot1 <- function(y,method="f",p=1) {
n1 <- length(y)
#n2 <- n1*p
assign("n2",n1*p)
n3 <- n2 - 1
a <- 0.5*(outer(1:n3,1:n3,function(x,y){n2 - pmax(x,y)}))
return(a)
}
thanks for listening!
Sincerely,
Erin H
mailto: hodgess at gator.uhd.edu
2004 Sep 02
0
Re: [S] [R/S] question re solution
> Someone else mentioned Venables and Ripley (2000) S
> Programming (Springer). Please see this or some other discussion of
the
> "..." argument.
The "Introduction to R" (from Cran website) also talks about it. See pg
49 - section 10.4 (was just reading this the other day).
Cheers
Manoj
-----Original Message-----
From: r-help-bounces at stat.math.ethz.ch
2017 Jun 06
2
integrating 2 lists and a data frame in R
> On Jun 6, 2017, at 4:01 AM, Jim Lemon <drjimlemon at gmail.com> wrote:
>
> Hi Bogdan,
> Kinda messy, but:
>
> N <- data.frame(N=c("n1","n2","n3","n4"))
> M <- data.frame(M=c("m1","m2","m3","m4","m5"))
> C <-
2017 Jun 06
0
integrating 2 lists and a data frame in R
Thank you David. Using xtabs operation simplifies the code very much, many
thanks ;)
On Tue, Jun 6, 2017 at 7:44 AM, David Winsemius <dwinsemius at comcast.net>
wrote:
>
> > On Jun 6, 2017, at 4:01 AM, Jim Lemon <drjimlemon at gmail.com> wrote:
> >
> > Hi Bogdan,
> > Kinda messy, but:
> >
> > N <-
2017 Jun 06
1
integrating 2 lists and a data frame in R
Simple matrix indexing suffices without any fancier functionality.
## First convert M and N to character vectors -- which they should
have been in the first place!
M <- sort(as.character(M[,1]))
N <- sort(as.character(N[,1]))
## This could be a one-liner, but I'll split it up for clarity.
res <-matrix(NA, length(M),length(N),dimnames = list(M,N))
res[as.matrix(C[,2:1])] <-
2012 Jun 04
1
simulation of modified bartlett's test
Hi, I run this code to get the power of the test for modified bartlett's
test..but I'm not really sure that my coding is right..
#normal distribution unequal variance
asim<-5000
pv<-rep(NA,asim)
for(i in 1:asim)
{print(i)
set.seed(i)
n1<-20
n2<-20
n3<-20
mu<-0
sd1<-sqrt(25)
sd2<-sqrt(50)
sd3<-sqrt(100)
g1<-rnorm(n1,mu,sd1)
g2<-rnorm(n2,mu,sd2)
2017 Jun 06
1
integrating 2 lists and a data frame in R
Here's another approach:
N <- data.frame(N=c("n1","n2","n3","n4"))
M <- data.frame(M=c("m1","m2","m3","m4","m5"))
C <- data.frame(n=c("n1","n2","n3"), m=c("m1","m1","m3"), I=c(100,300,400))
# Rebuild the factors using M and N
C$m <-
2011 Sep 14
1
ruby to solve a physics question
I am trying to solve one of my graduate level physics problems with
ruby...
Here is what I have so far...
a6=0.0
for n1 in -10..10
for n2 in -10..10
for n3 in -10..10
if n1!=0 and n2!=0 and n3!=0
p=Math.sqrt(n1**2+n2**2+n3**2+n1*n2/1.414+n1*n3/1.41+n2*n3/1.414)
a6+=(1/p)**6
end
end
end
end
puts a6
What I''ve got here is a 10x10x10 face-centered
2017 Jun 06
0
integrating 2 lists and a data frame in R
Hi Bogdan,
Kinda messy, but:
N <- data.frame(N=c("n1","n2","n3","n4"))
M <- data.frame(M=c("m1","m2","m3","m4","m5"))
C <- data.frame(n=c("n1","n2","n3"), m=c("m1","m1","m3"), I=c(100,300,400))
2010 Jul 05
2
Function to compute the multinomial beta function?
Dear R-users,
Is there an R function to compute the multinomial beta function? That is, the normalizing constant that arises in a Dirichlet distribution. For example, with three parameters the beta function is Beta(n1,n2,n2) = Gamma(n1)*Gamma(n2)*Gamma(n3)/Gamma(n1+n2+n3)
Thanks in advance for any assisstance.
Regards,
Greg
[[alternative HTML version deleted]]
2010 Dec 29
2
How to create an array of lists of multiple components?
Hi,
how can I create an array of lists of three components?
This approach does not work:
n1 <- 2
n2 <- 4
n3 <- 5
res <- array(rep(vector("list",3), n1*n2*n3), dim = c(n1,n2,n3))
res[1,1,1] # is not a list with three components...
The goal is that res[1,1,1] is a list with three components. Also, appending the
components didn't work. For example, I tried:
component
2011 Jul 27
3
Reorganize(stack data) a dataframe inducing names
Dear Contributors,
thanks for collaboration.
I am trying to reorganize data frame, that looks like this:
n1.Index Date PX_LAST n2.Index Date.1 PX_LAST.1
n3.Index Date.2 PX_LAST.2
1 NA 04/02/07 1.34 NA 04/02/07 1.36
NA 04/02/07 1.33
2 NA 04/09/07 1.34 NA 04/09/07
2007 Apr 11
2
sem is not "taking" the model
A strange problem with sem:
I downloaded the sem library and then, I specified my simple measurement model (below). I highlighted it and ran it. It ran, but it did NOT tell me "22 lines read". And nothing works after that - it looks like it runs, but it does not produce anything...
Did I make a mistake somewhere in the model? (notice, TIME has only 1 indicator - t1, and I fixed t1's
2017 Jun 06
4
integrating 2 lists and a data frame in R
Dear Bert,
thank you for your response. here it is the piece of R code : given 3 data
frames below ---
N <- data.frame(N=c("n1","n2","n3","n4"))
M <- data.frame(M=c("m1","m2","m3","m4","m5"))
C <- data.frame(n=c("n1","n2","n3"),
2020 May 04
2
"Earlyclobber" but for a subset of the inputs
Hi all,
I'm working on a target whose registers have equal-sized subregisters and
all of those subregisters can be named (or the other way round: registers
can be grouped into super registers).
So for instance we've got 16 registers W (as in wide) W0..W15 and 32
registers N (as in narrow) N0..N31. This way, W0 is made by grouping N0 and
N1, W1 is N2 and N3, W2 is N4 and N5, ..., W15 is
2006 Jun 07
2
help with combination problem
hello:
I have 3 data.frame objects.
First df object:
Of dim (149,31). Columns 2:31 are marked as T1..T14
and N1..N16.
Name T1 T2 N1 T3 N2 N3 N4 T4
mu1 10 10 9 10 9 9 8 10
mu2 11 11 9 11 9 9 9 11
...
muN 12 12 9 11 9 9 8 12
Second df object:
of Dim (50000,31). Columns 2:31 are maked as T1...T14
and N1..N16.
2010 Jan 13
4
a question about deleting rows
I have a file like this:
id n1 n2 n3 n4 n5 n6
1 3 4 7 8 10 2
2 4 1 2 4 3 10
3 7 0 0 0 0 8
4 10 1 0 0 2 3
5 11 1 0 0 0 5
what I want to do is: only if n2=0 and n3=0 and n4=0 and n5=0 then delete
the row. how can I do that?
thank you,
karena
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2012 May 18
1
help with creating a box plot
Hi:
I am looking for some help in making two boxplots next to each other.
I have a data like this:
N1 T1 N2 T2 N3 T3 N4 T4 ... Nn Tn
7 8.2 4 5 8 10 4 5 ..... 10 11
I want to have box plot for all Normal samples (N1,N2,N3,N4,,,,Nn)
and another box plot for all tumors (T1,T2,T3,T4,...Tn).
I have data in a numeric class.
If data is represented as N1