similar to: [R/S] strange

Displaying 20 results from an estimated 9000 matches similar to: "[R/S] strange"

2004 Sep 02
1
[R/S] question re solution
Dear R and S People: First, thank you to so many people for your help to my problem. Here is the solution: a <- 0.5*(outer(1:n3,1:n3,function(x,y,n2.){n2. - pmax(x,y)},n2.=n2)) I have one final pesky question, please: During my experiments, I tried the following: a <- 0.5*(outer(1:n3,1:n3,function(x,y,n2.=n2){n2. - pmax(x,y)})) Why doesn't this work please? thank you! Sincerely,
2004 Sep 01
0
Re: [S] [R/S] strange solution
Hi, Erin: A cleaner way is to pass "n2" to "outer" as a "..." argument, as in the following modification of your code: boot1 <- function(y,method="f",p=1) { n1 <- length(y) n2 <- n1*p n3 <- n2 - 1 a <- 0.5*(outer(1:n3,1:n3,function(x,y, n2.){n2. - pmax(x,y)}, n2.=n2)) return(a) } y1 <- c( 9, 8, 7, 3, 6) boot1(y=y1,p=4)
2004 Sep 01
0
[R/S] strange solution
Dear R and S People: I ended up using the "assign" command, and things work in S+. boot1 <- function(y,method="f",p=1) { n1 <- length(y) #n2 <- n1*p assign("n2",n1*p) n3 <- n2 - 1 a <- 0.5*(outer(1:n3,1:n3,function(x,y){n2 - pmax(x,y)})) return(a) } thanks for listening! Sincerely, Erin H mailto: hodgess at gator.uhd.edu
2004 Sep 02
0
Re: [S] [R/S] question re solution
> Someone else mentioned Venables and Ripley (2000) S > Programming (Springer). Please see this or some other discussion of the > "..." argument. The "Introduction to R" (from Cran website) also talks about it. See pg 49 - section 10.4 (was just reading this the other day). Cheers Manoj -----Original Message----- From: r-help-bounces at stat.math.ethz.ch
2017 Jun 06
2
integrating 2 lists and a data frame in R
> On Jun 6, 2017, at 4:01 AM, Jim Lemon <drjimlemon at gmail.com> wrote: > > Hi Bogdan, > Kinda messy, but: > > N <- data.frame(N=c("n1","n2","n3","n4")) > M <- data.frame(M=c("m1","m2","m3","m4","m5")) > C <-
2017 Jun 06
0
integrating 2 lists and a data frame in R
Thank you David. Using xtabs operation simplifies the code very much, many thanks ;) On Tue, Jun 6, 2017 at 7:44 AM, David Winsemius <dwinsemius at comcast.net> wrote: > > > On Jun 6, 2017, at 4:01 AM, Jim Lemon <drjimlemon at gmail.com> wrote: > > > > Hi Bogdan, > > Kinda messy, but: > > > > N <-
2017 Jun 06
1
integrating 2 lists and a data frame in R
Simple matrix indexing suffices without any fancier functionality. ## First convert M and N to character vectors -- which they should have been in the first place! M <- sort(as.character(M[,1])) N <- sort(as.character(N[,1])) ## This could be a one-liner, but I'll split it up for clarity. res <-matrix(NA, length(M),length(N),dimnames = list(M,N)) res[as.matrix(C[,2:1])] <-
2012 Jun 04
1
simulation of modified bartlett's test
Hi, I run this code to get the power of the test for modified bartlett's test..but I'm not really sure that my coding is right.. #normal distribution unequal variance asim<-5000 pv<-rep(NA,asim) for(i in 1:asim) {print(i) set.seed(i) n1<-20 n2<-20 n3<-20 mu<-0 sd1<-sqrt(25) sd2<-sqrt(50) sd3<-sqrt(100) g1<-rnorm(n1,mu,sd1) g2<-rnorm(n2,mu,sd2)
2017 Jun 06
1
integrating 2 lists and a data frame in R
Here's another approach: N <- data.frame(N=c("n1","n2","n3","n4")) M <- data.frame(M=c("m1","m2","m3","m4","m5")) C <- data.frame(n=c("n1","n2","n3"), m=c("m1","m1","m3"), I=c(100,300,400)) # Rebuild the factors using M and N C$m <-
2011 Sep 14
1
ruby to solve a physics question
I am trying to solve one of my graduate level physics problems with ruby... Here is what I have so far... a6=0.0 for n1 in -10..10 for n2 in -10..10 for n3 in -10..10 if n1!=0 and n2!=0 and n3!=0 p=Math.sqrt(n1**2+n2**2+n3**2+n1*n2/1.414+n1*n3/1.41+n2*n3/1.414) a6+=(1/p)**6 end end end end puts a6 What I''ve got here is a 10x10x10 face-centered
2017 Jun 06
0
integrating 2 lists and a data frame in R
Hi Bogdan, Kinda messy, but: N <- data.frame(N=c("n1","n2","n3","n4")) M <- data.frame(M=c("m1","m2","m3","m4","m5")) C <- data.frame(n=c("n1","n2","n3"), m=c("m1","m1","m3"), I=c(100,300,400))
2010 Jul 05
2
Function to compute the multinomial beta function?
Dear R-users, Is there an R function to compute the multinomial beta function? That is, the normalizing constant that arises in a Dirichlet distribution. For example, with three parameters the beta function is Beta(n1,n2,n2) = Gamma(n1)*Gamma(n2)*Gamma(n3)/Gamma(n1+n2+n3) Thanks in advance for any assisstance. Regards, Greg [[alternative HTML version deleted]]
2010 Dec 29
2
How to create an array of lists of multiple components?
Hi, how can I create an array of lists of three components? This approach does not work: n1 <- 2 n2 <- 4 n3 <- 5 res <- array(rep(vector("list",3), n1*n2*n3), dim = c(n1,n2,n3)) res[1,1,1] # is not a list with three components... The goal is that res[1,1,1] is a list with three components. Also, appending the components didn't work. For example, I tried: component
2011 Jul 27
3
Reorganize(stack data) a dataframe inducing names
Dear Contributors, thanks for collaboration. I am trying to reorganize data frame, that looks like this: n1.Index Date PX_LAST n2.Index Date.1 PX_LAST.1 n3.Index Date.2 PX_LAST.2 1 NA 04/02/07 1.34 NA 04/02/07 1.36 NA 04/02/07 1.33 2 NA 04/09/07 1.34 NA 04/09/07
2007 Apr 11
2
sem is not "taking" the model
A strange problem with sem: I downloaded the sem library and then, I specified my simple measurement model (below). I highlighted it and ran it. It ran, but it did NOT tell me "22 lines read". And nothing works after that - it looks like it runs, but it does not produce anything... Did I make a mistake somewhere in the model? (notice, TIME has only 1 indicator - t1, and I fixed t1's
2017 Jun 06
4
integrating 2 lists and a data frame in R
Dear Bert, thank you for your response. here it is the piece of R code : given 3 data frames below --- N <- data.frame(N=c("n1","n2","n3","n4")) M <- data.frame(M=c("m1","m2","m3","m4","m5")) C <- data.frame(n=c("n1","n2","n3"),
2020 May 04
2
"Earlyclobber" but for a subset of the inputs
Hi all, I'm working on a target whose registers have equal-sized subregisters and all of those subregisters can be named (or the other way round: registers can be grouped into super registers). So for instance we've got 16 registers W (as in wide) W0..W15 and 32 registers N (as in narrow) N0..N31. This way, W0 is made by grouping N0 and N1, W1 is N2 and N3, W2 is N4 and N5, ..., W15 is
2006 Jun 07
2
help with combination problem
hello: I have 3 data.frame objects. First df object: Of dim (149,31). Columns 2:31 are marked as T1..T14 and N1..N16. Name T1 T2 N1 T3 N2 N3 N4 T4 mu1 10 10 9 10 9 9 8 10 mu2 11 11 9 11 9 9 9 11 ... muN 12 12 9 11 9 9 8 12 Second df object: of Dim (50000,31). Columns 2:31 are maked as T1...T14 and N1..N16.
2010 Jan 13
4
a question about deleting rows
I have a file like this: id n1 n2 n3 n4 n5 n6 1 3 4 7 8 10 2 2 4 1 2 4 3 10 3 7 0 0 0 0 8 4 10 1 0 0 2 3 5 11 1 0 0 0 5 what I want to do is: only if n2=0 and n3=0 and n4=0 and n5=0 then delete the row. how can I do that? thank you, karena -- View this message
2012 May 18
1
help with creating a box plot
Hi: I am looking for some help in making two boxplots next to each other. I have a data like this: N1 T1 N2 T2 N3 T3 N4 T4 ... Nn Tn 7 8.2 4 5 8 10 4 5 ..... 10 11 I want to have box plot for all Normal samples (N1,N2,N3,N4,,,,Nn) and another box plot for all tumors (T1,T2,T3,T4,...Tn). I have data in a numeric class. If data is represented as N1