Displaying 20 results from an estimated 2000 matches similar to: "header line generated write.table"
2010 May 11
1
create a data.frame for aov
Hi R-experts,
I try to find a way to transfer a matrix to a data.frame that is used as input of aov.
can you give me advice for that?
>mdat <- matrix(c(1,2,3, 11,12,13), nrow = 2, ncol=3, byrow=TRUE, dimnames = list(c("row1", "row2"), c("Col1", "Col2", "Col3")))
>mdat
Col1 Col2 Col3
row1 1 2 3
row2 11 12 13
===>
2009 Dec 02
2
Help: barchart() {Lattice}
Hi R Users,
I'm using following data/code (data is attached also) to produce a stacked
barplot.
# Sample Data:
Names Col1 Col2 Col3
Row1 -20 40 -10
Row2 30 -20 40
Row3 30 10 -20
Row4 20 20 -10
# R Code:
dta<-read.table("data.txt", header=TRUE, row.names="Names")
barchart(data.matrix(dta),
horizontal=FALSE,
stack=TRUE,
par.settings = simpleTheme(col =
2009 Dec 02
1
barchart() {Lattice} -- auto.key()
Hi R Users,
I'm using following data/code (data is also attached) to produce a stacked
barplot.
*I need help with changing legend boxes, currently I'm using
"rectangles=TRUE". Is it possible to get small squares instead -- may be
with a small gap between colored squares.* Currently there is no gap between
the colored rectangles.
# Sample Data:
Names Col1 Col2 Col3
Row1 -20 40
2009 Nov 26
3
barchart() {Lattice} help.
Hi R Users,
I'm trying to plot a stacked barplot. Here is data:
Sample Col1 Col2 Col3
Row1 -2 4 -1
Row2 3 -2 4
Row3 3 5 -2
Row4 4 1 -1
I'm using following R code:
library(lattice)
dta<-read.table("data.txt", header=TRUE, row.names="Sample")
barchart(data.matrix(dta),
horizontal=FALSE,
stack=TRUE,
col=2:4,
2009 Dec 02
1
Fw: Re: Help: barchart() {Lattice}
I HAVE BEEN ASKED TO BE REMOVED FROM THIS LIST OVER 20 TIMES, PLEASE CAN I BE REMOVED!!!!!!!!!!!!!
--- On Thu, 3/12/09, Peng Cai <pengcaimaillist@gmail.com> wrote:
From: Peng Cai <pengcaimaillist@gmail.com>
Subject: Re: [R] Help: barchart() {Lattice}
To: "Felix Andrews" <felix@nfrac.org>
Cc: r-help@r-project.org
Received: Thursday, 3 December, 2009, 10:17 AM
Got it
2018 Nov 27
1
Subsetting row in single column matrix drops names in resulting vector
Dmitriy Selivanov (selivanov.dmitriy at gmail.com) wrote:
> Consider following example:
>
> a = matrix(1:2, nrow = 2, dimnames = list(c("row1", "row2"), c("col1")))
> a[1, ]
> # 1
>
> It returns *unnamed* vector `1` where I would expect named vector. In fact
> it returns named vector when number of columns is > 1.
> Same issue applicable
2012 Aug 03
3
embedding data frame in R code?
I would like to insert a few modest size data frames directly into my
R code. a short illustration example of what I want is
d <- read.csv( _END_, row.names=1 )
, "col1", "col2"
"row1",1,2
"row2",3,4
__END__
right now, the data sits in external files. I could put each column
into its own vector and then combine into a data frame, but this seems
2009 Aug 27
1
generating multiple sequences in subsets of data
I'm running into a problem I can't seem to find a solution for. I'm
attempting to add sequences into an existing data set based on subsets
of the data. I've done this using a for loop with a small subset of
data, but attempting the same process using real data (200k rows) is
taking way too long.
Here is some sample data and my ultimate goal
>
2009 Nov 13
3
sum(row1==y) if row2=x
Hi to all
is there any construct to sum
data=data.frame(row1=c(1,1,3,1,2,3,2,2,1,3,4,5,2,3,2,1) ,
row2=c(2,2,1,1,1,2,1,2,1,1,1,1,2,2,2,1) )
Means I would like to get all y of row1 if in row2 of the data.frame is
an x
f.e row1=3 and row2=2
so I would like to get 6
And is there another construct to get the count of pairs where
row1=3 and row2=2
means the result should be
2010 Mar 30
1
Adding RcppFrame to RcppResultSet causes segmentation fault
Hi,
I'm a bit puzzled. I uses exactly the same code in RcppExamples
package to try adding RcppFrame object to RcppResultSet. When running
it gives me segmentation fault problem. I'm using gcc 4.1.2 on redhat
64bit. I'm not sure if this is the cause of the problem. Any advice
would be greatly appreciated. Thank you.
Rob.
int numCol=4;
std::vector<std::string>
2008 Dec 16
2
converting a data-frame by a defined rule
Hi,
I have a data frame with several columns.
Now I want to transfer the data into a new variable (also a data
frame), but I only want a part of the data, defined by a rule ...
for example; I have following data frame:
row1 row2 row3
x 2 3
x 1 4
y 5 3
y 2 3
I know want a data frame, only with lines containing x in row1.
I know how to do that for one row (f <-
2008 Dec 16
1
refer to next line within a data-frame an select cases
Hi,
I have a problem sorting and selecting entries within a data-frame and
I don't know if it is possible to solve it with R ... (probably yes,
but I have no idea how).
Following Data;
row1 row2
a 12
pos NA
a 3
neg NA
a 5
neg NA
a 11
pos NA
I want to extract the values in row 2 in the lines with an "a" in row1.
But I want to have two vectors: vector x with all
2012 Mar 09
1
index values of one matrix to another of a different size
> Hello,
>
> Is this the fastest way to use indices from one matrix to reference rows
> in another smaller matrix? I am dealing with very big data (lots of columns
> and I have to do this lots of times).
>
> ######sample data ##############
> vals = matrix(LETTERS[1:9], nrow=3,ncol=3)
> colnames(vals) = c('col1','col2','col3')
> rownames(vals)
2010 Sep 06
1
Creating named.list from two matrix columns
Hi Friends,
I am new to R.
On R utility class pages, creating "named.list" is described with this command :
new("named.list",a=1,b=2)
For large matrix having two columns, such as :
"row1" 2334
"row2" 347
"row3" 379
...
I want to create a named.list like :
$row1
[1] 2334
$row2
[1] 347
...
Can anyone explain how "named.list"
2005 Nov 28
7
combine two columns
Hi,
I have an R programming problem and I havent found anything in the
documentation yet:
I have a data matrix, in which two neighbouring columns represent
replicates of the same experiment, e.g. something like this:
A A B B C C
row1 1 1 1 2 2 2
row2 1 1 1 1 1 2
I would like to test, if the values for the two replicates in a row
are the same or if they differ and generate a new
2010 Sep 10
4
for loop help please!
Hi Everyone,
I have a 2-dim data.matrix(e.g., table1) in which row1 specifies a range of
values. row2 - rown specify the number of times I want to replicate each
corresponding value in row1. I can do this with the following function:
rep(c(table1[1,]),c(table1[X,])) #where X would go from 2 - n.
Now, I can do this manually by changing the values of X and save each
resulting array/vector in
2008 Sep 04
1
restricted bootstrap
Hello List,
I am not sure that I have the correct terminology here (restricted
bootstrap) which may be hampering my archive searches. I have quite a large
spatially autocorrelated data set. I have xy coordinates and the
corresponding pairwise distance matrix (metres) for each row. I would like
to randomly sample some number of rows but restricting samples such that the
distance between them is
2009 Jun 13
3
How Can I insert another column data into the CSV file when I use FasterCSV?
Hi, All,
Suppose I have a CSV file, there is data in it.
* Column 1 Column2 Column 3 Column 4
Row1 a b c
Row2 a2 b2 c2*
You know, the column 4 is no data
Now, I would like to insert data to Column 4, after save, the CSV file will
be:
* Column 1
2013 May 01
1
Combine multiple tables into one
Hi,
May be this helps:
dat1<- as.data.frame(table1)
?dat2<- as.data.frame(table2)
names(dat2)<-c("V3","V4")
library(plyr)
res<-join(dat1,dat2,type="full")
?res[is.na(res)]<- 0
?res
#? V1 V2 V3 V4
#1? 1? 1? 0? 0
#2? 1? 2? 0? 0
#3? 0? 0? 0? 1
#4? 0? 0? 0? 4
?combinedtable<-as.matrix(res)
?colnames(combinedtable)<- NULL
?combinedtable
#???? [,1] [,2]
2007 Nov 12
1
update matrix with subset of it where only row names match
I guess this has a simple solution:
I have matrix 'mat1' which has row and column names, e.g.:
A B C
row1 0 0 0
row2 0 0 0
....
rown 0 0 0
I have a another matrix 'mat2', essentially a subset of 'mat1' where the
rownames are all in 'mat1' e.g.:
B
row3 5
row8 6
row54 7
I want to insert the values of matrix mat2 for column B (in reality it
could be some or