similar to: labeled break statements in R?

Hi, I have a simple question about matrix/data frame manipulation. I have a data frame that looks a something like this X Y Z 1 0 "apples" -1 -1 "oranges" ... 0 -1 "bananas" and I'd like to pull out all the rows for which X and Y are (un)equal into a submatrix. How can I do that? Many thanks, Roger Levy

Hi, In the exactRankTest package, I've become aware that you can get anomalous p-values (i.e., above 1) from the wilcox.exact method, as in: > wilcox.exact(c(-0.6,0.8,-0.5)) Exact Wilcoxon signed rank test data: c(-0.6, 0.8, -0.5) V = 3, p-value = 1.25 alternative hypothesis: true mu is not equal to 0 This is disturbing. Has anyone encountered this before, and if so

Hello. I'm currently trying to wrap up data frames into OCaml via OCaml-R, and I'm having trouble with data frame subsetting: > # x#column 1;; > Erreur dans (function(x, i, exact) if (is.matrix(i)) as.matrix(x)[[i]] else .subset2(x, : > l'?l?ment 1 est vide ; > la partie de la liste d'arguments de 'is.matrix' en cours d'?valuation ?tait : > (i)

In ?exists it says: inherits: should the enclosing frames of the environment be searched? I believe what it is saying is that if inherits is TRUE and it fails to find the variable it will look in the parent environment and the parent of the parent, etc. (as opposed to looking in the calling frame next and the caller of the caller, etc.) Now I thought that standard terminology in R was: 1.

R programming question, not machine learning, although that's the content. Apologies to all for whom the following code is eye-burning. I am using foreach() to run a simulation on a randomForest model (actually conditional randomForest ... "party" package). The simulation is in two dimensions. examining how "mtry" and "ntrees" are related in terms of predictive

I ran into an interesting issue with `evalq` (and also `eval(quote(...))`): ???? f <- function() { ?????? list( ???????? sys.parent(1), ???????? evalq(sys.parent(1)), ???????? evalq((function() sys.parent(2))()),? # add an anon fun layer ???????? evalq((function() sys.parent(1))()) ?????? ) ???? } ???? res <- f() ???? str(res) ???? ## List of 4 ???? ##? $ : int 0???????? # sys.parent(1)

In 3.1.2 eval does not store the result of the bquote-generated call in the given environment. Interestingly, in 3.2.1 eval does store the result of the bquote-generated call in the given environment. In other words if I run the given example with eval rather than evalq, on 3.1.2 "x" is never stored in "fenv," but it is when I run the same code on 3.2.1. However, the given

The help page of eval says: The 'evalq' form is equivalent to 'eval(quote(expr), ...)'. But the following is not equivalent. Can anyone give me some explaination? Thanks very much. > f1 <- function(x,digits=5) lapply(x, f2) > f2 <- function(x) eval(quote(print(x+1,digits=digits)),list(x=x),parent.frame(2)) > f1(list(x1=1)) [1] 2 $x1 [1] 2 > > f1 <-

On Jul 15, 2015, at 12:51 PM, William Dunlap wrote: > I think rapply() was changed to act like lapply() in this respect. > When I looked at the source of the difference, it was that typeof() returned 'language' in 3.2.1, while it returned 'list' in the earlier version of R. The first check in rapply's code in both version was: if (typeof(object) != "list")

Hello, I upgraded from 3.1.2 to 3.2.1 and am receiving errors on code that worked as I intended previously. Briefly, I am using bquote to generate expressions to modify data.table objects within a function, so I need the changes to actually be stored in the given environment. Previously, I used code like the following: test <- list(bquote(x <- 10)) fenv <- environment() rapply(test,

David, If you are referring to the solution that would be: rapply(list(test), eval, envir = fenv) I thought I explained in the question that the above code does not work. It does not throw an error, but the behavior is no different (at least in the output or result). Using the above code still results in the x object not being stored in fenv on 3.1.2. Dayne On Wed, Jul 15, 2015 at 4:40 PM,

Hi, In order to avoid deep copies by passing large arguments to functions or returning values, I'm trying to do the assignment of variables in a given environment. The problem is when I try to assign a structure: a list for example. If I have: ind <- c("a","b") my idea is doing something like l <- alist() l[ind] <- as.list(c(20,40)) in a given

Dear List: I have the following simple program: x<- sample(site) VarGuilda1<- var(tapply(x,site,func1)) VarGuilda2<- var(tapply(x,site,func2)) VarGuilda3<- var(tapply(x,site,func3)) VarGuilda4<- var(tapply(x,site,func4)) VarGuilda5<- var(tapply(x,site,func5)) VarGuilda6<- var(tapply(x,site,func6)) VarGuilda7<- var(tapply(x,site,func7)) VarGuilda8<-

Dear mailing list, I have found some strange behaviour which I think relates to parent frames and eval. Can anyone explain what's going on here? First example: > test.parent.funcs_ function() { outer.var_ 5 subfunc1_ function() substitute( outer.var, envir=parent.frame()) print( subfunc1()) subfunc2b_ function() eval( quote( outer.var), envir=parent.frame()) print(

Hi, In my data set I have created a matrix of distances. How can I get a list of minimum value in each row? thanks a lot, Rog?rio

On 01/04/2015 1:35 PM, Gabriel Becker wrote: > Joris, > > > The second argument to evalq is envir, so that line says, roughly, "call > environment() to generate me a new environment within the environment > defined by data". I think that's not quite right. environment() returns the current environment, it doesn't create a new one. It is evalq() that created

Dear expeRts, I would like to download a time series of historical data from the ticker with symbol "ROG.VX". Interestingly, I obtain constant values (138.3 for each day in the chosen period) although the yahoo.finance website tells me that the time series is not at all constant. What's wrong? Cheers, Marius require(tseries) hq <- get.hist.quote(instrument="ROG.VX",

Hi there, people. On Sep 22 2009, Clint Adams wrote: > On Tue, Sep 22, 2009 at 08:23:00PM -0300, Rog?rio Brito wrote: > > If any of you could lend me a hand with the subject, I could make a > > better package (the other issues that I left on the package are > > really trivial). > > If you rebase your changes against bzr://bzr.debian.org/pkg-xiph/libtheora That should

Hi Everyone, My CentOS 4.4 mail server is having problems sending mail after updating it to 4.4 Before the update, I did not have any problems. My ISP requires that email clients must authenticate to their mail servers before mail can be sent out. I setup smtp auth to get postfix to relay mail through the ISP's mail servers. Here's my config: main.cf -------- relayhost =

Dear speex developers, Would it be possible to have tags in speex files? I have a good amount of spoken audio (currently in MP3 format) and I would like to convert it to speex, since it seems to be the best choice for voice recordings. Unfortunately, without tags, it is quite hard to identify the speeches. Ideally, I would love if tag support were included into easytag, so that I can manipulate