similar to: Simple Lookup... why so slow

Dear all, is there any function to calculate the center of a polygon mass in R? Actually I need to find the best location within polygons to place labels. Thanks for any hint Jens Oehlschl?gel -- COMPUTERBILD 15/03: Premium-e-mail-Dienste im Test\ --------...{{dropped}}

Dear R-helpers, I have 4-dimensional atmospheric data (x,y,z,t), which I want to analyse on spatio-temporal diversities. As far as I understand there only exists the possibility to construct time series as two-dimensional matrices (mts). For the moment, I hold it in different objects: 1. a four-dimensional array for the spatial related analyses 2. a two-dimensional mts timeserie, which was

When I just run a for loop it works. But if I am going to run a for loop every time for large vectors I might as well use C or any other language. The reason R is powerful is becasue it can handle large vectors without each element being manipulated? Please let me know where I am wrong. for(i in 1:length(news1o)){ + if(news1o[i]>s2o[i]) + s[i]<-1 + else + s[i]<--1 + } --

Dear Guru's My first steps with R have ground to a halt! I have a vector of sample identifiers > sampleIDs [1] "D1_1" "D1_2" "D1_3" "D1_4" "D1_5" "D1_6" "D1_7" "D1_8" [9] "D1_9" "D1_10" "D1_11" "D1_12" "F1_13" "F1_14"

Hi, I have been analyzing the LLVM vectorizer by running some benchmarks. For vectorization, I have used the following flags: -O3 -ffast-math -mavx2 Am I missing any other flags which will improve vectorizer performance? Thanks, Santanu Das IIT Hyd -------------- next part -------------- An HTML attachment was scrubbed... URL:

Hi all, I have some email addresses that I would like to sort in reverse lexicographic order so that addresses from the same domain will be grouped together. How might that be done? Murray -- Dr Murray Jorgensen http://www.stats.waikato.ac.nz/Staff/maj.html Department of Statistics, University of Waikato, Hamilton, New Zealand Email: maj at waikato.ac.nz

Hi I'm not sure how to ask this, but its a very easy question to answer for an R person. What is an easy way to check for a column value and then assigne a new column a value based on that old column value? For example, Im doing colordata <- data.frame(id = c(1,2,3,4,5), color = c("blue", "red", "green", "blue", "orange")) for (i in

ifelse is vectorised, so just use that without the loop. colordata$response <- ifelse(colordata$color == 'blue', 1, 0) David On 7 April 2016 at 12:41, Michael Artz <michaeleartz at gmail.com> wrote: > Hi I'm not sure how to ask this, but its a very easy question to answer for > an R person. > > What is an easy way to check for a column value and then assigne a

On Thu, Jan 31, 2019 at 4:05 PM Philip Reames via llvm-dev <llvm-dev at lists.llvm.org> wrote: > Do such architectures frequently have arithmetic operations on the mask registers? (i.e. can I reasonable compute a conservative length given a mask register value) If I can, then having a mask as the canonical form and re-deriving the length register from a mask for a sequence of

== is also vectorised, and you're better off with TRUE and FALSE rather than 1 and 0, so I'd recommend: colordata$response <- colordata$color == 'blue' Hadley On Thu, Apr 7, 2016 at 6:52 AM, David Barron <dnbarron at gmail.com> wrote: > ifelse is vectorised, so just use that without the loop. > > colordata$response <- ifelse(colordata$color ==

Hi, As a follow up to Patch D23646 <https://reviews.llvm.org/D23646>, I'm trying to figure out if there should be an alignment check and what the correct approach is. Some background: For stores, the pass turns: %i.vec = shuffle <8 x i32> %v0, <8 x i32> %v1, <0, 4, 8, 1, 5, 9, 2, 6, 10, 3, 7, 11> store <12 x i32> %i.vec, <12 x i32>* %ptr

Dear People, I hope someone can help me with this. I have a function (density) which I am trying to plot using curve. I am calling mg.hist(3,2,1), and getting the following errors. Error in xy.coords(x, y, xlabel, ylabel, log) : x and y lengths differ In addition: There were 50 or more warnings (use warnings() to see the first 50) > warnings() 1: longer object length is not a multiple of

? Tue, 11 Jun 2024 18:44:08 +0000 "Levine, Michael" <mlevins at purdue.edu> ?????: > Let us say we have a function > > F <- function(x){ body of the function} > > Where x is, in general, a d by 1 vector with d>1. Now I want to > integrate out some of the coordinates of x, e.g. x[1] or x[2] or both > of them etc. I'm well aware of how to integrate

On 1 July 2015 at 17:15, Russell Wallace <russell.wallace at gmail.com> wrote: > I'm proposing that LLVM unilaterally replace most undefined behaviour with > implementation-defined behaviour. That's precisely the problem. Which behaviour? Let's have an example: struct Foo { long a[95]; char b[4]; double c[2]; }; void fuzz(Foo &F) { for (int i=0; i<100;

Hi I'm trying to get to grips with R and establish R as a teaching medium in my secondary school. I would like to use R to analyse text so I can produce frequency analysis of the text for subsequent examination of ciphers. I can produce code in VBA but I am struggling when writing in R to examine each character. There must be a clear method using the vectorised format of R. Furthermore,

Hi all, I have a data.frame with the following colnames pattern: x1 y11 x2 y21 y22 y23 x3 y31 y32 ... I.e. I have an x followed by a few y's. What I would like to do is turn this wide format into a tall format with two columns: "x", "y". The structure is that xi needs to be associated with yij (e.g. x1 should next to y11 and y12, x2 should be next to y21, y22, and

Yes, SVE can vectorize early exit loops by using speculative (first-faulting) loads, which essentially give a predicate of the lanes loaded successfully. For uncounted loops with these special loads, the loop predicate tests can be done using a 'ptest' instruction, checking if the last element is active. Amara On 3 February 2017 at 10:15, Simon Pilgrim <llvm-dev at redking.me.uk>

Hi. Here is a piece of cpp code. It works, but I do not understand the rational for the use of "R::dpois" to call the function dpois since in the examples I have always found directly "dpois" or "Rcpp::dpois" that both do not work in my code. Could anyone be so patient to explain me why should it be like that? Thaks a lot, Enrico #include <Rcpp.h> using

I have matrix multiplication and stencil code. I vectorise it through the following command. opt -S -O3 -force-vector-width=2048 stencil.ll -o stencil_o3.ll in both the examples of matrix mult and stencil it vectorises fine when my loop iterations >2048. but if i keep both iterations and vector width=2048. it produces scalar code IR not vectorizes it. Is it llvm bug? Please help me.

Hello, Or even simpler, without ifelse, colordata$response <- colordata$color == 'blue' + 0 Hope this helps, Rui Barradas ? Citando David Barron <dnbarron at gmail.com>: > ifelse is vectorised, so just use that without the loop. > > colordata$response <- ifelse(colordata$color == 'blue', 1, 0) > > David > > On 7 April 2016 at 12:41, Michael