similar to: basic questions: any place for them

I've started a "tribe" for discussing R and sharing scripts. Tribe.net is one of the popular on-line social communities, like "Friendster". Visit and see if it is a forum that you find useful. To join the "tribe" you will need to register with Tribe.net. I hope it will be of help to newbies, although I'm new to R myself. Here is the url:

Hi a) I want to make a list out of a data.frame, where each element of the list is a column of the data.frame. I looked in the archives and saw a lot of postings but surprsingly none elucidated me. I also tried the split, aggregate help files and counldn't see any easy way to do this. I wouldn't be surprised if it's there, but I really didn't see it. I solved the problem

Hi I have a data.frame with 2 columns. The first column is an ID column. The other columns are description of the ids. There is more than one description for each Id. Want I want to get as a value is a data.frame where each row corresponds to one ID and has as many columns as different descriptions. I have used a very convoluted step, but I'm very convinced there is an easier way to do

I'm puzzled by the following problem, which appears when attempting to run an analysis on part of a dataset: If I try: csubset <- dat$Diagnosis==0 cont <- lme(fixed=cform, random = ~1|StudyName, data=dat,subset=csubset,na.action=na.omit) Then I get: Error in eval(expr, envir, enclos) : Object "csubset" not found But if I do

Hello! I'm trying the hard way to use a formula, in a function, to specify the names of several important columns in a data.frame. Maybe I'm just battling to figure out the right search terms :-( This is on XP, R 1.8.1. So, for instance, wery[1:5,] V1 V2 V3 V4 V5 congr V7 V8 V9 ok RT 1 1 1 960 520 1483 c 1 r r 1 760 2 1 2 1060 450 3753 c 1 r r 1 555

Hello, I would like to access my data frame without one variable. E.g.: > colnames(x) [1] "Besch" "Ang.m" "Arb.m" "i10" "Umsatz" "arbstd" I can try x[,-1], but this variable must be called by it??s name. x[,-"Besch"] x[,!"Besch"] attach(x) x[-Besch] ... ... does not work. I could not found a solution of

Hi I want to extract a row from a data.frame but I want that object to be a vector . After trying some different ways I end up always with a data.frame or with the wrong vector. Any pointers? x <- data.frame(a = factor(c('a',2,'b')), b = c(4,5,6)) I want to get "a" "4" I tried: as.vector(x[1,]) a b 1 a 4 (resulting in a data.frame even after in my

Hi I want to extract all the rows in a data frame that have duplicates for a given column. I would expect this question to come up pretty often but I have researched the archives and surprisingly couldn't find anything. The best I can come up with is: x <- data.frame(a=c(1,2,2,3,3,3), b=10) xdup1 <- duplicated(x[,1]) xdup2 <- duplicated(x[,1][nrow(x):1])[nrow(x):1] xAllDups <-

I want to read data from a number of files into R. Reading individual files one by one requires writing enormous amount of code that will look something like the following. **************** maptools:::dbf.read("wb-01vc.dbf")->dist1 maptools:::dbf.read("wb-02vc.dbf")->dist2 maptools:::dbf.read("wb-03vc.dbf")->dist3

Dear ALL, I fear my question has already been answered many times before, but I haven't fund that in archives... I am working on spatial datasets and, in most arrays I'm handling, there are two columns dedicated to (x,y)-coords. For different reasons - notably to draw image() plots, I need to have these two columns sorted in increasing order. But sort() and order() seem to apply to

Dear all, I hope to remove a whole column from a data frame or matrix (> 2000 columns). All value in the column are same. The first thing is to select those columns. For instance, I hope to remove the V3~6 column, for all the value in those colume is zero. V3 V4 V5 V6 V7 V8 V9 V10 1 0 0 0 0 0.000 0.000 0.000 0.000 2 0 0 0 0 0.000 0.000 0.000 0.000 3 0 0 0

Dear R-listers: I want to import a reasonably big file into a table. (15797 x 257 columns). The file is tab delimited with NA in every empty space. I have reproduced what I have used as my read.table instruction. I have read the R-dataImportExport FAQ and still couldn't solve my problem. (I might have missed it, of course). I'm using R.2.01 in a Mac G4, 10.3.7. I can import the

Dear R mailing list, I have a dataset with genotypes from trios and I would like to infer haplotypes for each mother, father and child. The package that I could find that can do this is tdthap. But when the mother is homozygous (e.g., 2/2) the haplotype is called as not possible to infer (0); I would prefer for it to call the genotype (2). From what I understand it is doing what I would like

Hi to you all My question is: there is a package written in UNIX for which there is no Mac version. I would like to know if it's possible to install the R UNIX version on the MacOSX and run that UNIX package on my Mac (through this UNIX R Vresion on a Mac) I have seen a porfile for r version 1.8.1 on darwin: http://r.darwinports.com/ is that it? aother question related to that if it's

Is there a modulus operator in R? Anna

> -----Original Message----- > From: Richard A. O'Keefe [mailto:ok at cs.otago.ac.nz] <snip> > The very existence of an "is.na<-" which accepts a logical > vector containing FALSE as well as TRUE ... And don't forget this is not the only usage of is.na<-. In fact it is designed to take any valid indexing value. For example: > a<-1:10 >

Hi! I have a 3d array: > dim(ib5km15.dbc) [1] 190 241 19 and a set of positions to extract: > ib5km.lincol.random[1:3,] [,1] [,2] [1,] 78 70 [2,] 29 213 [3,] 180 22 Geting the values of a 2D array for that set of positions would be: > ima <- ib5km15.dbc[,,1] > ima[ib5km.lincol.random[1:10,]] but don't find the way for the case of the 3D array: >

Hi! Apologies for sending the mail without any code. Apparently somewhere along the way the .R attachments got filtered out. I have included the code below as clean as possible. My original mail is below the code. Thank you again for your time. regards, Paul vincentize <- function(data, bins) { if ( length(data) < 2 ) { stop("The data is really short. Is that ok?"); }

I think the thread ended up with several people (not only me) feeling certain they didn't like `is.na<-` but with the developers defending it and me not really understanding why. Uwe Ligges was going to come up with an example of `<- NA` going wrong (sorry Brian R, I mean behaving unexpectedly), but never did, and I think the problem has been fixed. It was apparently a problem with

yes I have tries, and nothing. It just shows the strings with the slashn, just like i typed it. -----Original Message----- From: Rashid Nassar [mailto:rnassar at duke.edu] Sent: ÐÝì?ôç, 16 Óå?ôåìâñßïõ 2004 15:44 To: Christos Rodopoulos Subject: Re: [R] How do I insert a newline in my title in a plot? Have you not tried what you have already suggested: title("this is a title\nIn 2