similar to: retrieve rows from frame assuming criterion [corrected]

sorry for my previus (WRONG) answer, as someone already pointed out a solution could be subset(data, PUNTAR==c("IX49","IX48")) > -----Messaggio originale----- > Da: Guazzetti Stefano > Inviato: venerd?? 23 luglio 2004 15.55 > A: 'Luis Rideau Cruz'; r-help at stat.math.ethz.ch > Oggetto: R: [R] retrieve rows from frame assuming criterion > >

Hi all, I have a data frame in which one column(PUNTAR) is of character type. What I want is to retrieve is the frame but only with those rows matching elements of PUNTAR with a list characters (e.g c("IX49","IX48") ) Year TUR STODNR PUNTAR 1994 9412 94020061 IX49 1994 9412 94020062 IX48 1994 9412 94020063 X32 1994 9412 94020065 X23 1994 9412

Yes, paraphrasing Murphy I can say of myself: "Nothing seems to be able to stop a stupid thought in its pathway from the brain to the keyboard". :-) Sorry once again and thank for your patience. Stefano > -----Messaggio originale----- > Da: Prof Brian Ripley [mailto:ripley at stats.ox.ac.uk] > Inviato: venerd?? 23 luglio 2004 16.30 > A: Guazzetti Stefano > Cc: Luis

R-help, In the following loop : for(i in 1:8) { cc[[i]]<-tapply(test[,i+6],list(puntar=test$puntar),sum)/tapply(test[,5],list(puntar=test$puntar),sum) cbind.data.frame(cc[[1]],cc[[2]],cc[[3]],cc[[4]], cc[[5]],c[[6]],cc[[7]],cc[[8]]) } Is there anyway I can 'cbind.data.frame' the objects cc[[ i ]] without actually writing every single element?? In this case there are 8 but what if

R-help, I'm trying to do a simple box-and-whisker plot to some data. The data are a subset of a large data frame but when running the "boxplot" function on the subset data all the factors are still present in the graph leaving a huge empty space until the actuals factors are shown. This produces a spurious box-and-whisker plot. If the subset data are exported to another R session

Dear all, curve(x^3*(1-x)^7, from = 0, to = 1) works as expected but, omitting the "xlim" or the "to" and "from" arguments and calling "curve" more than once: par(mfrow = c(2,2)) for (i in 1:4) curve(x^3*(1-x)^7) gives an expected (al least to me) result. Note also that a "pu" object is returned by curve > pu [1] -0.1802445 1.1802445

Buenas a todos, La gente de DataCamp se han puesto en contacto con el grupo de Madrid para ofrecernos una oferta para usar gratuitamente su plataforma con diferentes cursos de R durante un mes. Les hemos preguntado si sería posible compartir este ofrecimiento con toda la lista de R-Help-es y no ven mayor problema, les ha parecido muy bien la posibilidad. El link de acceso es el siguiente:

Hola a todos, Tengo un problema con RStudio y la conexión a una base de datos. Desde la terminal no tengo problemas para ejecutar, por ejemplo: library(RODBC) channel <- odbcConnect("MiBaseDatos", uid = "MiUsuario", pwd = "MiContrasena") datos <- sqlQuery(channel,"SELECT TO_CHAR(S.B_STOD_DATO,'YYYY') \ , M.STODNR \ ... ... ...") pero desde

oops!, I pressed the 'send' key too soon, ... see ?replace replace(x, is.na(x), median(x, na.rm=T)) take also a look at the function itself > replace function (x, list, values) { x[list] <- values x } <environment: namespace:base> Stefano >-----Messaggio originale----- >Da: r-help-bounces at stat.math.ethz.ch >[mailto:r-help-bounces at

Carlos, al parecer tengo instalado el paquete RODBC en : /home/luisr/R/i686-pc-linux-gnu-library/3.0/RODBC/ no hay nada en (carpeta vacia): /usr/local/lib/R/site-library/ en el directorio: /usr/local/lib/R/site-library hay paquetes que vienen con R pero RODBC no saludos, Luis -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- Luis Ridao Cruz Faroe Marine Research Institute Nóatún 1,

No, no estoy usando Rstudio Server El 1 de abril de 2014, 9:07, Carlos J. Gil Bellosta <cgb@datanalytics.com>escribió: > Una pregunta... no estarás utilizando RStudio server, ¿verdad? > > En tal caso, lo que tienes que hacer es configurar > /etc/rstudio/rstudio.conf tal como indica en > > http://www.rstudio.com/ide/docs/server/configuration > > En particular,

Hola, ¿qué tal? ¿Puedes comparar la salida del comando Sys.getenv("LD_LIBRARY_PATH") en una sesión en la que funciona RODBC y otra en la que obtienes el error anterior? Un saludo, Carlos J. Gil Bellosta http://www.datanalytics.com P.D.: A propósito, también he estado tratando de utilizar RODBC en Linux y me he acabado rindiendo. Sobre todo porque RJDBC funciona bastante bien.

Dear Professor Bernhard, Sorry for take your time, but I found something strange that I am not able to explain/understand. Suppose that I compute the ADF test by using the criterion="BIC" to select the lags: summary(CADFtest(y, max.lag.y = 20, type = "drift", criterion="BIC")) Suppose that 2 lags are selected. Next, if I set the lags to 2: summary(CADFtest(y,

Pues ahí lo tienes. De alguna manera R (a través de RStudio) no está incorporando el directorio /u01/app/luisr/product/11.1.0/client_1/lib donde se ve que tienes las librerías de ODBC al "LD path". Échale un vistazo a https://support.rstudio.com/hc/communities/public/questions/200641818-How-to-configure-libPaths-?locale=en-us Aparentemente RStudio tiene su propio sistema para

Hello, I am using the function stepAIC (library MASS) to run a backward elimination on my linear regression. The new model stepAIC calculates contains coefficients that have a Pr(>|t|) value below 0.1, but I'd like to have only coefficients with 0.001 or below. How can I change the stop criterion for stepAIC, so that it is more strict? There is a parameter "steps", but it is

Dear Dr. Gilbert, Dr. Varadhan and all R-help list members, I'm using the function BBsolve( ) and I have some questions on the stopping criterion "maxit" and "noimp" specified in the option "control". Here are two such examples I'm having problem with. In these two examples, the function BBsolve( ) always stops at iteration 100, overlooking the values

Hi, I have data for one dependent variable and multiple independent variables y = b0 + b1*x1 + b2*x2 + ... I want to a list of all models that have some subset of the independents (just x1 x2, and not x3, etc.) and their corresponding BIC values. Is there a pre-existing function that does this? I saw that you can calculate individual BIC values using 'lm' and something like AIC(lm1, k

Hi, As an example, how can I get the data such that field a of ab, ab["a"], equals 3? I expect the answer to be the union of 2 and 4, as Thanks, > a<-c(1,3,4,3,5,6,5) > b<-c(2,4,6,7,3,1,2) > ab<-data.frame(a,b) > ab a b 1 1 2 2 3 4 3 4 6 4 3 7 5 5 3 6 6 1 7 5 2 > ab[a==3] Error in `[.data.frame`(ab, a == 3) : undefined columns selected >

I'm interested in writing some model selection functions (for linear regression models, as a start), which incorporate the PRESS criterion since it, to my knowledge, is not currently implemented in any available model selection procedure. I thought it would be simplest to build on already existing functions like regsubsets in package leaps. It's easy enough to calculate the PRESS

Dear R users, I'm using the rpart package to build classification trees. I'm interested in implementing the ordered Twoing as a splitting criterion. Does anyone have experience with this task ? Thank you for your help Paolo Paolo Radaelli Dipartimento di Metodi Quantitativi per le Scienze Economiche ed Aziendali Facolt? di Economia Universit? degli Studi di Milano-Bicocca Via Bicocca