similar to: Error:length of dimnames [2] not equal to array extent ?

Created a new data set with 3 numeric variable to find correlation CR1<- mar%>% as_data_frame%>% select(AGE, OLD_CAR_PURCHASE_YRS, Total.Spend.With.AA) had to convert it to a data frame, code: as.matrix(as.data.frame(CR1)) Now i need to run a correlation plot for these 3 variables: corrplot(CR1, method = "circle") But i am getting this error: Error in

I'm assuming you are using the corrplot package. If so, your data object does need to be a matrix, not a data frame. Since it's already a data frame, your line of code: as.matrix(as.data.frame(CR1)) doesn't need the as.data.frame function, but more importantly, you didn't assign the result to anything: as.matrix() does not work in place. CR1 <- as.matrix(CR1) Now try. If

Hello, all, I'm a new R user (new to any programming language in general, really), so I apologize if this is easy/has already been answered (I've attempted searching online but did not understand the pages I found). My data is stored in text files with the headers LANE, RNA_NAME, SEQ, and SEQCNT. I've been using x = "filename.txt" y = aggregate(x$SEQCNT, list(x$RNA_NAME),

That does clarify for me that you're missing a step: I didn't clearly follow your description at first. corrplot expects a correlation matrix, not your original data. You need to use cor() first. That's pretty clear in the documentation. See for instance the examples: data(mtcars) M <- cor(mtcars) corrplot(M) Sarah On Sat, Mar 17, 2018 at 12:00 PM Shivi Bhatia <shivipmp82 at

Hi Sarah, Thank you for your help. I tried using CR1<-as.matrix(CR1) but gives error Error in corrplot(CR1, method = "circle") : The matrix is not in [-1, 1]!. I am using a corrplot library. Please find the reproducible example: dput(head(CR1,10)) structure(c(26L, 46L, 39L, 38L, 47L, 59L, 56L, 61L, 43L, 60L, 78L, 63L, 2L, 58L, 8L, 1L, 1L, 9L, 11L, 2L, 1037500L, 46747L, 346300L,

Hello all, I'm trying to use the user-created multinomRob to make some models for my data. While documentation for that function is fine and I think I'm using it correctly, I'm getting the following error when I try to use my lists of variables. data <- read.csv("data.csv", header=FALSE) subj1 <- data.frame(radius=data$V3[9:11], x1=data$V4[9:11], x2=data$V5[9:11],

Hi, how can I get a more descriptive text instead of the variable names in my XY-lattice plot, according to the table below? Variable text acet = "Acetylaspartate Thalamus" chol = "Choline Thalamus" acetp = "Acetylaspartate parieoc" ino = "Inositole Thalamus" I could not find a solution. Please have a look at my syntax. Thanks a lot,

I have a large dataset grouped by a factor and I want to perform a regression on each data subset based on this factor. There are many ways to do this, posted here and elsewhere. I have tried several. However I found one method posted on the R wiki which works exactly as I want, and I like the elegance and simplicity of the solution, but I don't understand how it works. Its all in the formula

I posted this question way down at teh end of another thread realted to an error in step, but that was stupid since it really is another matter altogether. I should have posted it separately, as I have now done. The code below creates a data.frame comprising three marginally noisy surfaces. The code below (including a fix courtesy of David Winsemius that avoids a step function error through use

Dear list, If anyone knows how to assign dimnames to matrices or arrays I would be most grateful for help. I've tried various permutations of likely-looking code but get error messages every time. I could find no example in the documentation. Many thanks, Dan Bebber Department of Plant Sciences University of Oxford South Parks Road Oxford OX1 3RB UK Tel. 01865 275000

Hi I am trying to add a less than equal sign to a plot. I have previously done this using unicode but is not working in this instance. Any suggestions would be great thanks example code: library(ggplot2) df<-data.frame(vis=c(0,0,1,1) , count=c(10,15,20,10) , grp=c(0,1,0,1)) df$grp <-factor(df$grp ,levels=c(0,1) , labels =c("x \u2265 10" , "x > 10")) ggplot(df,

Hi. The quick question: Is there a way of forcing a Samba server that is an Active Directory member server to limit lookups to it's local domain only and not all trusted domains? The question in more detail: I have a Samba server that is joined to my local AD domain ("css.ad.example.com"). There are other domains under ad.example.com such as lps.ad.example.com and

Dear community, I had been looking for an easy way to produce latex tables from R output. xtable() and the package apsrtable produce good outputs but they are not exactly what I was looking for. I wrote this code that generates regression tables from multiple R linear models. I want to share it because it might be useful for someone else, and because I would appreciate comments on how to

This question appears to have been asked previously, but not answered. the last response I can find to this previous thread is here: http://tolstoy.newcastle.edu.au/R/help/04/07/0126.html. The asnwer was to provide debugging info, not an answer. So the problem is that I'm trying to use lda on my dataset. You can download my data here: http://northstar-www.dartmouth.edu/~jgilbert/nolda, I used

I am hoping for some assistance with a problem that has puzzled me. Immediately below is the error messages I obtained when I tried to perform two functions. (A) tapply(outcome,na.rm=T,grp,mean) Error in tapply(outcome, na.rm = T, grp, mean) : arguments must have same length +++++++++++++++++++++++++++++++++++++++++++++++ (B) library(nlme) > anova(lme(outcome ~ grp * time,

hello, i have been trying to convert my data frames to matrices in the hopes of speeding up some of my more complicated scripts. to assist with this, i am trying to create a "matrix column operator" like $: "%$%" = function(data,field) { as.numeric(data[,grep(field,unlist(dimnames(data)[2]))]) } the idea here is that you can use a matrix like a dataframe:

Dear list members, How can I replace the nested for loops at then end of the script below with more efficient code? # Begin script__________________________________________________ # Dichotomous scores for 100 respondents on 3 items with # probabilities of a correct response = .6, .4, and .7, # respectively x1 <- rbinom(100,1,.6) x2 <- rbinom(100,1,.4) x3 <- rbinom(100,1,.7) #

Hello, I'm hoping someone with a wide experience with R may be able to see what the program is trying to tell me. I've got an array: y1=rnorm(41,0.2) y2=rnorm(41,0.2) y3=rbind(y1,y2) data11<-array(0,c(41,2,2)) data11[,1,]=y3 data11[,2,]=y3 rownames(data11)<-rownames(data11, do.NULL = FALSE, prefix = "Obs.") colnames=c("V","R")

Hello, I’m trying to follow the syntax of a script from a journal website. In order to create a regression formula used later in the script, the regression matrix must have column names “X1”, “X2”, etc. I have tried to assign these column names to my matrix ScoutRSM.mat using a for loop, but I don’t know how to interpret the error message. Suggestions? Thanks, Paul

I observe dificulties with using data.frame(I(matrix)) > mat <- matrix(letters, 2, 2) > dimnames(mat) <- list(c(1:2), c("x","y")) > mat x y 1 "a" "c" 2 "b" "d" > dd <- data.frame(I(mat)) > ddd I.mat..x I.mat..y 1 a a 2 b b 3 c c doesn't look too bad, but, has