similar to: Xtable giving an interesting problem

Hello: I s there a way to use xtable with objects from the psych package, particularly principal()? Is there a difference between princomp and principal? xtable seems to play better with princomp. Thank you. Yours, Simon Kiss ********************************* Simon J. Kiss, PhD Assistant Professor, Wilfrid Laurier University 73 George Street Brantford, Ontario, Canada N3T 2C9

Hello, I am trying to use the package "exams" to construct problem sets. I have constructed an exercise which generates a list of integers and asks the student to compute the median. rx is the vector of n numbers >str(rx) num [1:16] 21 9 8 18 4 12 17 2 9 7 ... I want to print out the entire vector as part of the problem. When I use \Sexpr(rx) only the first value (in this case

At one time (version 1.7), the code below used to work for converting and extracting based on the Date Time. In version 1.8.1, something changed I know, but I cannot for the life of me figure out what... Data: UserName,RequestDate,PO,OrderDate,ExpDelivDate,Vendor,Total "Woody, Jim",12/19/2002,AP15063,1/7/2003,2/10/2003,Ames ,8570 "Harrold,

As part of my work, I am trying to append matrices onto data frames. Naively I assumed that when rbinding a data.frame and matrix, the matrix would be coerced and appended, keeping the names from the data frame. Clearly, I am not fully understanding the process by which rbind works. Example code: > A<-data.frame(1,1,1); names(A)=letters[1:3] ; B<-matrix(0,2,3) > rbind(A,B)

Dear list members, I would like to merge multiple dataframes and seems that this task is going to be required quite often, so I decided to write a simple (pseudo)recursive merge. I started with the case when dataframes are merged by rows (0). But there is a problem when a dataframe to be merged in the step n has some items that are not in previous ones. Then I get "Error in match.names(clabs,

I've been experimenting recently with the fantastic Sweave/xtable combination for generating latex. In the xtable vignette, I found this great example of printing a ts object by months. Is there a way to modify this code to generate RED numbers inside xtable for negative results in x.ts? Thanks in advance. - Ken # Sweave/xtable snippet below

Full_Name: Martin Elff Version: 1.5.0 OS: MS Windows 98 Submission from: (NULL) (134.155.91.46) Merging of two data frames by variables with different names (using by.x and by.y) is no longer possible (it was possible in version 1.4.1). Call: mvoteint.classd.matadd <- merge( unique(mvoteint.classd), unique(subset(dimens.mpp,

I have installed package xtable with su -c 'R CMD INSTALL xtable' and got this promising feedback: * Installing *source* package 'xtable' ... ** R ** data ** help >>> Building/Updating help pages for package 'xtable' Formats: text html latex example * DONE (xtable) Despite that, R returns: Error: couldn't find function "print.xtable"

I could have sworn that yesterday xtable(file, booktabs = TRUE) was giving me toprule , midrule and bottomrule outout. Today : library(xtable) aa <- table( sample(letters[1:9], 100, replace = TRUE)) xtable(aa, booktabs = TRUE) gives me \begin{table}[ht] \centering \begin{tabular}{rr} \hline & V1 \\ \hline a & 15 \\ b & 11 \\ c & 13 \\ d &

I've been experimenting recently with the fantastic Sweave/xtable combination for generating latex. In the xtable vignette, I found this great example of printing a ts object by months. Is there a way to modify this code to generate RED numbers inside xtable for negative results in x.ts? Thanks in advance. - Ken # Sweave/xtable snippet below

Hi all Suppose I do the following: set.seed(1000) library(xtable) x <- runif( 10 ) y <- 1 + 2*x + rnorm( length(x) ) test.lm <- lm( y ~ x ) summary( test.lm ) xtable ( summary( test.lm ) ) The final xtable output follows: % latex table generated in R 1.8.1 by xtable 1.2-2 package % Tue Jun 22 09:56:36 2004 \begin{table}[ht] \begin{center} \begin{tabular}{rrrrr} \hline &

Dear useRs, Am trying to use xtable on the following data.frame and I don't get what I expect: example.table <- data.frame(rbind( c("Gender"," "," "," "), cbind(rep(" ",2),c("Male","Female"),c(3.0,4.0),c(3/7,4/7)) )) colnames(example.table) <- c(" "," ","number of

Hello, I am trying to use Sweave to write up a report, and I have used the plm package to do some panel models. I am trying to use xtable to make a nice table for my regression objects (returned by the plm command), but I am getting the error: Error in UseMethod("xtable") : no applicable method for "xtable" It seems like I would want to have xtable treat plm objects exactly

Hola a todos Les consulto por un problema con xtable y nlme, tomando un ejemplo del manual de nlme para obtener los resultados en latex utilizando xtable, se puede utilizar el siguiente código, pero hay un problema y causa error. library(nlme) library(xtable) fm1 <- nlme(height ~ SSasymp(age, Asym, R0, lrc), data = Loblolly, fixed = Asym + R0 + lrc ~ 1,

I am just starting to learn Sweave (really neat tool). I am pretty early in the learning curve (I had to think a moment ago whether a # or % was the appropriate comment character). I have successfully incorporated simple graphics and outputs, but am having trouble getting a latex (xtable) table to function properly. Latex is seemingly treating the xtable code as input or verbatim text. That

hi, I use xtable to convert data.frames to html tables. But when I use the print-command I always get the whole output printed even if I just want to save the html table into a variable; table <- print(xtable(CERAT), type="html") How can I suppress that output is printed? thanks! [[alternative HTML version deleted]]

Dear All I am running Sweave with xtable and want to put the caption placement on top. But this does not work. Any idea what is going wrong? Here is an example that runs properly with the exception of the caption placement in the pdf-file. \documentclass[11pt,a4paper]{article} \usepackage{Sweave} \begin{document} <<>>= x = runif(100, 1, 10) y = 2 + 3 * x + rnorm(100)

Hi there, I'm very new on R and I hope someone can help me to solve the problem in using the ifelse statement with the xtable function(library xtable). I'm trying to get the printing of the elements of two lists in a sorted way. These two list have in common the their names. I will try to give an example: the first list looks like this: $code1 Code code1 Nation

Dear R help: I am trying to use paste(), within an ifelse() statement to insert latex commands into an object that has been created using xtable(). I cannot make the strings behave as I would like, the '\t' is creating a tab, the usual method of '\\t' is not working either - nor is any series of backslashes. The xtable object, I think, automatically alters the strings. How

Hi, Does anyone know how to manually configure the number of digits printed out from xtable()? For example, I'm exporting a data frame through xtable() into a LaTeX table, I only have two columns in the data frame so by default I only get two decimal places. But I'd like at least 5 decimal places. I had a look at ?xtable() but can't seem to find an example. Cheers, Kevin