similar to: Problem in Installing Package from CRAN...

After entering ?library(rpart)?, I tried to plot an existing rpart tree, and got this error message: Error: couldn't find function "plot.rpart". However, ??plot.rpart? does bring up the help for the function. The same things occur for text.rpart, although print(my.tree) does work. So, I tried to re-install rpart using Packages | Install from CRAN, but then I get this

Full_Name: michael cole Version: 1.9.1 OS: Windows Submission from: (NULL) (80.219.153.13) When trying to install lattice graphics... I receieve the following: trying URL `http://cran.r-project.org/bin/windows/contrib/1.9/lattice_0.9-16.zip' Content type `application/zip' length 496618 bytes opened URL downloaded 484Kb package 'lattice' successfully unpacked and MD5 sums

I'm trying to update my Matrix package given the update last night. But the following error is generated. I've tried restarting R and deleting my old Matrix package. Can anyone suggest how this might be resolved? > install.packages('Matrix') trying URL 'http://www.ibiblio.org/pub/languages/R/CRAN/bin/windows/contrib/2.1/Mat rix_0.98-1.zip' Content type

When trying to update (various) packages using update.packages() I get the following error message for various packages package 'fBasics' successfully unpacked and MD5 sums checked Error in unpackPkg(foundpkgs[okp, 2L], foundpkgs[okp, 1L], lib) : malformed bundle DESCRIPTION file, no Contains field > This happens with other packages besides fBasics (Matrix, as well as others) and I

When trying to update (various) packages using update.packages() I get the following error message for various packages package 'fBasics' successfully unpacked and MD5 sums checked Error in unpackPkg(foundpkgs[okp, 2L], foundpkgs[okp, 1L], lib) : malformed bundle DESCRIPTION file, no Contains field > This happens with other packages besides fBasics (Matrix, as well as others)

Hi I have been trawling the web, FAQs, and R manuals for help on the following issue, but have failed and was wondering if anyone has a solution to the following problem: After having installed R 2.6.2 for Windows (binary), I tried to install various packages. Every time I try loading a package (any package) via the built-in menu, I run into the following error message. >

The file src/library/base/R/print.R contains this line: x0 <- xm[okP]==0 != (as.numeric(Cf[okP])==0) I didn't know R allowed that, and I wonder if it is deliberate? In mathematics, you would expect x = y not= z to mean (x = y) and (y not= z).; In R, it is parsed as (x == y) != z. While I have to admit that the spacing around == and != in

Dear all, i was working under R 1.6.2 but i wanted to install bioconductor under WinXP, and because R 1.7.1 contains the TclTk package and automatic installation of bioconductor packages, so i install it. Everything is fine except this message which appear after the installation of packages. "> local({a<- CRAN.packages(CRAN=getOption("BIOC")) +

Hi, I'm using rw2000dev.exe (Win32) built on August 14. If this isn't already planned, can I suggest that when checkS3methods() (called by R CMD check) fails because of a syntax error in a dependent package listed in the DESCRIPTION file of the main package being checked, it would be nice if checkS3methods() reported which dependent package caused it to fail? Running R CMD check on my

Dear useRs, Lately I noticed a strange warning in the summary of a lm-object. Any idea what this warning is about? I'm using R 2.5.1 on Win XP pro. > x <- rnorm(100) > y <- rnorm(100) > summary(lm(y~x)) Call: lm(formula = y ~ x) Residuals: Min 1Q Median 3Q Max -1,77809 -0,68438 -0,04409 0,63891 2,30863 Coefficients: Estimate Std.

Hello, I have R1.9.0 under Windows XP. My program plots several plots using x11() par(cex = 0.75) ...... x11() par(cex = 0.75) ...... x11() par(cex = 0.75) ...... x11() par(cex = 0.75) ...... Sometimes, one of them generates a small frame only with title area "R graphics: Device X (ACTIVE)". The message in the console window is Error in plot.new() : Figure margins too large

Could anyone please explain to me why the following writes nothing into "all.Rout" file? If the "for" loop is removed, t.test output can be written into "all.out". Thanks in advance. Minghua Yao ...... zz <- file("all.Rout", open="wt") sink(zz) for(i in 1:n) { Cy3<-X[,2*i-1]; Cy5<-X[,2*i]; t.test(Cy3, Cy5)

Dear all, I have the following output generated by linear regression. Since there is only one regression intercept and one slope for one set of data, what is the meaning of std. error for intercept and that of slope? Thanks in advance. Sincerely, Minghua > data(thuesen) > attach(thuesen) > lm(short.velocity~blood.glucose) Call: lm(formula = short.velocity ~ blood.glucose)

Hi, all, I want to use lowess(x, y) where x and y are vectors of length of 4000+. In fact, x and y are log of some vectors. So, some of the elements are NaN. lowess() can not take away those elements then do the fitting. It will give the error message and do nothing. 1. Can anybody tell me how to get rid of those NaN's and use lowess()? 2. How to get the LOWESS fitting values for any

Hi, Can anybody tell me how to open new a new window for plot()? Thanks. Minghua

Hi, Is there any function that can arrange a character in alphabetic order? Thanks for answer -MY [[alternative HTML version deleted]]

Gurus, I used predict(loess(Y~X)); where Y and X are of the same length. But there are same NA's in both Y and X. Those NA's are in the same locations in Y and X. The following is the error messageI got: Error in "[<-"(*tmp*, , i, value = predict(loess(Y~X))) : number of items to replace is not a multiple of replacement length If I replaced the NA's with a

Hello, everyone, I don't quite understand the following message: > TTT <- t.test(1:10, y=c(7:20)) > class(TTT) [1] "htest" > TTT@p.value Error: Trying to get slot "p.value" from an object whose class ("htest") is not defined > TTT$p.value [1] 1.855282e-05 Why the message says the class of TTT is not defined while class(TTT) gets

Hi, Anyone can tell me how to generate "A01", "A02", ..., "A99"? paste("A", 1:99, sep="") generates "A1", "A2",..., "A99". This is not what I want. Thanks for the help. -MY [[alternative HTML version deleted]]

Hi, A simple question. I want to assign values to columns (or rows) of a matrix. It seems that AA[,i]<-A; # A is a vector or array; doesn't work. How can I accomplish that? Thanks alot. -MY