similar to: Boot package

Good day R help list!!! I've been trying to do Bootstrap in R on Censored data. I encountered WARNING/ERROR messages which I could not find explanation. I've been searching on the literature for two days now and still can't find answers. I hope there's anyone out there who can help me with these two questions: 1. If the "Loglik converged before variable..." message

Hi, The following code, from Angelo Canty article on line "Resampling Methods in R: the boot Package, 2002", works fine for Angelo Canty using R 2.6.0 on Windows XP. It also works for me using R 1.2.1 and S-PLUS 2000 on Windows XP after installing the S-PLUS bootstrap library, with slight differences in my outputs. > library(boot) > library(survival) >

Dear R Help list, My question is regarding extracting the standard error or Z-score from a cph or coxph call. My Cox model is: - modz=cph(Surv(TSURV,STATUS)~RAGE+DAGE+REG_WTIME_M+CLD_ISCH+POLY_VS, data=kidneyT,method="breslow", x=T, y=T) I've used names(modz) but can't see anything that will let me extract the Z scores for each coefficient or the standard errors in the same

Dear all, I run the example of "censboot" contained in "boot" package. But, I can't find the confidence interval of the resulted "censboot" object. Any idea ? > aml.fun <- function(data) { + surv <- survfit(Surv(time, cens)~group, data=data) + out <- NULL + st <- 1 + for (s in 1:length(surv$strata)) { +

Hi, The following code, from Angelo Canty article on line "Resampling Methods in R: the boot Package, 2002", works fine for Angelo Canty using R 2.6.0 on Windows XP. It also works for me using R 1.2.1 and S-PLUS 2000 on Windows XP after installing the S-PLUS bootstrap library, with slight differences in my outputs. > library(boot) > library(survival) >

Hi, The following code, from Angelo Canty article on line "Resampling Methods in R: the boot Package, 2002", works fine for Angelo Canty using R 2.6.0 on Windows XP. It also works for me using R 1.2.1 and S-PLUS 2000 on Windows XP after installing the S-PLUS bootstrap library, with slight differences in my outputs. > library(boot) > library(survival)

Hi, The following code, from Angelo Canty article on line "Resampling Methods in R: the boot Package, 2002", works fine for Angelo Canty using R 2.6.0 on Windows XP. It also works for me using R 1.2.1 and S-PLUS 2000 on Windows XP after installing the S-PLUS bootstrap library, with slight differences in my outputs. > library(boot) >

Hello, I have been trying to use the censored bootstrap function 'censboot' from the library boot, with the function 'survfit' from the library survival5. My code is: surv.fun <-function(data) { sur<-survfit(Surv(data[,1],data[,2]), data=data) } c.boot<-censboot(m,surv.fun,R=99) m is my data set I get the error message: Error in

Dear R user, I am trying to convert the contents of a date.frame to a matrix. Since there are negative values in the date.frame, when I use data.matrix(x, rownames.force = NA), the resulting matrix is not the same as the original one. Basically I think R treats the numbers in the date.frame as character and converts it to corresponding numerics. Any idea on this issue? Many Thanks, Hongyuan

Dear All, since years I am struggling with Surv objects in data.frames. The following seems to have to do with it. See below the modified example from the help page of survSplit. The original works, as expected. If, however, a Surv object is added to the data.frame, each record gets doubled. Is there some solution other than avoiding Surv objects in data.frames? Thanks, Heinz

Hello: Using the built-in dataset aml as an example: data(aml) If I use instead dummy variables: aml$x1 = (aml$x=="maintained")aml$x2 = (aml$x=="unmaintained") and I want to plot the survival curve using x1, x2, and I just want the 2 levels, rather than 4 curves from: fit <- survfit(Surv(time, status) ~ x1+x2, data=aml) plot(fit) I guess because there are 2 levels

Hi there, I have a question about one command sentence when I follow the example in the book of "Survival analysis in S": > aml1<-aml[aml$group==1] but I got the error warning: NULL data frame with 23 rows Thus, I couldn't keep going on the next command: esf.fit<-survfit(Surv(aml1,status)~1). and also when I try > aml1<-aml[aml$group==1,]

Los datos no son de desgaste de cuchilla, sino de consumo de las mismas. Por ello tengo los datos de la siguiente forma: Unidades cambiadas Fecha En unidades cambiadas, suele ser una y en fecha el dia que se hizo el cmabio. Con eso no se muy bien como estructurar los datos para hacer el análisis. Gracias Jesús > Date: Mon, 7 Dec 2015 16:27:18 +0100 > From: griera en yandex.com

On Fri, Nov 22, 2019 at 12:30 PM Rafael J. Wysocki <rafael at kernel.org> wrote: > > On Fri, Nov 22, 2019 at 11:36 AM Mika Westerberg > <mika.westerberg at intel.com> wrote: > > > > On Thu, Nov 21, 2019 at 11:39:23PM +0100, Rafael J. Wysocki wrote: > > > On Thu, Nov 21, 2019 at 8:49 PM Mika Westerberg > > > <mika.westerberg at intel.com>

On Sun, May 29, 2016 at 05:50:06PM +0200, Lukas Wunner wrote: > Hi Peter, > > On Fri, May 27, 2016 at 03:07:33AM +0200, Peter Wu wrote: > > On Tue, May 24, 2016 at 06:03:27PM +0200, Lukas Wunner wrote: > > > nouveau_drm_load() calls pm_runtime_put() if nouveau_runtime_pm != 0, > > > but nouveau_drm_unload() calls pm_runtime_get_sync() unconditionally. > >

On Thu, Nov 21, 2019 at 12:03 PM Rafael J. Wysocki <rafael at kernel.org> wrote: > > On Thu, Nov 21, 2019 at 11:14 AM Mika Westerberg > <mika.westerberg at intel.com> wrote: > > > > On Wed, Nov 20, 2019 at 10:36:31PM +0100, Karol Herbst wrote: > > > with the branch and patch applied: > > >

Pero como haría el data frame?? Porque las cuchillas son de la misma referencia. En realidad es para ver cada cuanto se gstan las cuchillas y ver que pedidos hay que hacer de las mismas. La tabla que tengo es: 25 enero-> 1 cuchilla gastada 30 enero -> 1 cuchilla gastada 3 de febrero -> 2 cuchillas gastadas 5 de febrero -> 1 cuchilla gastada Y así.... No tiene necesariamente que ser

On Thu, Nov 21, 2019 at 12:03:52PM +0100, Rafael J. Wysocki wrote: > On Thu, Nov 21, 2019 at 11:14 AM Mika Westerberg > <mika.westerberg at intel.com> wrote: > > > > On Wed, Nov 20, 2019 at 10:36:31PM +0100, Karol Herbst wrote: > > > with the branch and patch applied: > > >

Hi I am Aadhithya I am trying to write a code to classify microarray data (AML and ALL) using SVM in R my code goes like this : library(e1071) train<-read.table("Z:/Documents/train.txt",header=T); test<-read.table("Z:/Documents/test.txt",header=T); cl <- c(c(rep("ALL",10), rep("AML",10))); model<- svm(train,cl); pred <-

Dear experts, I would like to know how to plot the log-minus-log plot for survival analysis (to check the proportional assumption) in R. Using the AML example. fit <- survfit(Surv(time, status) ~ x, data=aml) length(fit$surv) #20 as the length of fit$surv is shorter than aml$x and aml$time. I don't know how to plot. Thank you. Regards, CH -- CH Chan Research Assistant - KWH