similar to: interesting feature

Displaying 20 results from an estimated 10000 matches similar to: "interesting feature"

2004 Feb 27
4
question
Hi everybody. The question: I get two vectors 'iFalseFalse' and 'i2'. I think they should be the same but they are not. Is it because R does not handle complicated logical expressions in such cases or I do something wrong? > z1 = c(NA, "", 3, NA, "", 3) > z2 = c("", "", 3, NA, 3, NA) > cV = (as.character(z1)==as.character(z2))
2004 Feb 27
2
question about if else
Today is a good day for asking question, I guess. > c() NULL > > length(c())==0 [1] TRUE > > r = ifelse(length(c())!=0, c(), c(1,2)) ### OK > r = c() ### OK > r = ifelse(length(c())==0, c(), c(1,2)) ### why this is not OK (given > the previous two)? Error in "[<-"(`*tmp*`, test, value = rep(yes, length =
2004 Feb 05
2
correction to the previously asked question (about merging factors)
I have two factors l1, l2, and I'd like to merge them. (Remark: The factors can not be converted to charaters) Function c() does not give me the result I want: > l1 = factor(c('aaaa', 'bbbb')) > l2 = factor(c('ccc', 'dd')) > lMerge = factor(c(l1, l2)) > lMerge [1] 1 2 1 2 Levels: 1 2 > I'd like to merge l1 and l2 and to get lMerge
2004 Feb 05
1
What is the correct way of using function C() for factors:
The funciton c() works differently for strings and for factors: For strings: > l = c('a', 'b') > l [1] "a" "b" For factors: > l = c(factor('a'), factor('b')) > l [1] 1 1 What should be the right technique for merging factors? -- Svetlana Eden Biostatistician II School of Medicine
2004 Feb 27
1
question about setdiff()
Thank you for your answers, I have another question: the behaviour of setdiff(indicesFalse, indicesNA) does not seem predictable to me. > indices [1] 1 2 3 4 5 6 > compareVector [1] NA TRUE TRUE TRUE FALSE NA > indicesNA = indices[is.na(compareVector)] > indicesNA [1] 1 6 > indicesFalse = indices[compareVector == FALSE] > indicesFalse [1] NA 5 NA >
2004 Mar 26
1
lookup.xport in foreign ignoring some datasets (PR#6701)
The Details. In the following version. > version _ platform i386-pc-linux-gnu arch i386 os linux-gnu system i386, linux-gnu status major 1 minor 8.1 year 2003 month 11 day 21 language R > lookup.xport ignores some datasets in sas export file. File "emptySasData3.xpt" (available at http://biostat.mc.vanderbilt.edu/tmp/emptySasData3.xpt) is a
2004 Feb 24
1
bug in ifelse (PR#6611)
> version _ platform i386-pc-linux-gnu arch i386 os linux-gnu system i386, linux-gnu status major 1 minor 8.1 year 2003 month 11 day 21 language R > aa <- as.POSIXct(c('1/1/1980','1/2/1980','')) > ifelse(is.na(aa),as.POSIXct('1/3/1980'),aa) Error in rep.int(unclass(x), times) : Argument "times" is missing,
2011 Apr 07
1
Automated Fixed Order Stepwise Regression Function
Greetings, I am interested in creating a stepwise fixed order regression function. There's a function for this already called add1( ). The F statistics are calculated using type 2 anova (the SS and the F changes don't match SPSS's). You can see my use of this at the very end of the email. What I want: a function to make an anova table with f changes and delt R^2. I ran into
2017 Aug 07
2
vrp
On Mon, Aug 7, 2017 at 2:14 AM, Anastasiya Ruzhanskaya via llvm-dev <llvm-dev at lists.llvm.org> wrote: > I am trying to print it like this (maybe here is smth wrong?) > > > LazyValueInfo &LV = getAnalysis<LazyValueInfoWrapperPass>().getLVI(); > DominatorTree &DT = > getAnalysis<DominatorTreeWrapperPass>().getDomTree(); > LV.printLVI(F,
2017 Aug 07
2
vrp
Hello, I am trying to figure out, what vrp propagation does in llvm. I tried this program: #include <stdio.h> int main() { int s = 0; int j = 0; for (int i = 0; i < 100; i++) { j = j+i+1; s+=j; } return (s+j); } And got this under optimized version ( I don't want everything to be eliminated) define i32 @main()
2017 Aug 07
2
vrp
I am primarily interested in phi nodes and their induction variables, in ValueTracking file there is an analysis of them, but if the upper bound is inf, it is not working? 2017-08-07 11:41 GMT+02:00 Anastasiya Ruzhanskaya < anastasiya.ruzhanskaya at frtk.ru>: > So, it is not supported to determine by this instruction : %cmp = icmp slt > i32 %i.03, 99, > that %i.03 = phi i32 [ 0,
2012 Aug 13
6
named character question
Dear R People: Here is a goofy question: I want to extract the zip code from an address and here is my work so far: > add1 results.formatted_address "200 W Rosamond St, Houston, TX 77076, USA" > add1[1][32:36] <NA> <NA> <NA> <NA> <NA> NA NA NA NA NA > str(add1) Named chr "200 W Rosamond St, Houston, TX 77076,
2012 Apr 05
4
Appropriate method for sharing data across functions
In trying to streamline various optimization functions, I would like to have a scratch pad of working data that is shared across a number of functions. These can be called from different levels within some wrapper functions for maximum likelihood and other such computations. I'm sure there are other applications that could benefit from this. Below are two approaches. One uses the <<-
2015 Aug 21
3
unset() function?
Does R have a function like the S/S++ unset() function? unset(name) would remove 'name' from the current evaluation frame and return its value. It allowed you to safely avoid some memory copying when calling .C or .Call. E.g., suppose you had C code like #include <R.h> #include <Rinternals.h> SEXP add1(SEXP pX) { int nProtected = 0; int n = Rf_length(pX);
2013 Apr 23
2
[LLVMdev] 'loop invariant code motion' and 'Reassociate Expression'
Hi, I am investigating a performance degradation between llvm-3.1 and llvm-3.2 (Note: current top-of-tree shows a similar degradation) One issue I see is the following: - 'loop invariant code motion' seems to be depending on the result of the 'reassociate expression' pass: In the samples below I observer the following behavior: Both start with the same expression: %add = add
2007 May 21
2
Source code of add1
Se ha borrado un texto insertado con un juego de caracteres sin especificar... Nombre: no disponible Url: https://stat.ethz.ch/pipermail/r-help/attachments/20070521/f7808713/attachment.pl
2013 May 14
1
problem in add1's F statistic when data contains NAs?
Shouldn't the F statistic (and p value) for the x2 term in the following calls to anova() and add1() be the same? I think anova() gets it right and add1() does not. > d <- data.frame(y=1:10, x1=log(1:10), x2=replace(1/(1:10), 2:3, NA)) > anova(lm(y ~ x1 + x2, data=d)) Analysis of Variance Table Response: y Df Sum Sq Mean Sq F value Pr(>F) x1 1
2013 Apr 25
2
[LLVMdev] 'loop invariant code motion' and 'Reassociate Expression'
It's an interesting problem. The best stuff I've seen published is by Cooper, Eckhart, & Kennedy, in PACT '08. Cooper gives a nice intro in one of his lectures: http://www.cs.rice.edu/~keith/512/2012/Lectures/26ReassocII-1up.pdf I can't tell, quickly, what's going on in Reassociate; as usual, the documentation resolutely avoids giving any credit for the ideas. Why is that?
2004 Aug 09
0
[LLVMdev] API on JIT, code snippets
Reid wrote: > I have to agree with Misha on this. None of us knows "everything" about > LLVM and as you can see, Misha responded three hours before I did :). > Asking questions here is encouraged, so please feel free to post them on > LLVMdev. We'll always help where we can. well, OK :) Please find the attachment with the first approach to such an example i've
2004 Aug 09
5
[LLVMdev] API on JIT, code snippets
Valery, Attached are three files: "valery.cpp" which contains your original, "reid.cpp" which contains corrections to most of the FIXME items and "diffs" which shows the differences between them. The differences should be instructive on what to do. You were really, really close .. just a few details changing. The code in "reid.cpp" compiles but I