similar to: Generalized linear model

Readers, The attempt is to create a bar plot with text labels adjacent to each datum value. Data file: 1,3,A 1,8,B 1,1,C 1,9,D 2,5,C 2,4,E 2,2,F 2,0,G testbarplot<-read.csv('data1.csv', header=FALSE) barplot(axes=FALSE, ann=FALSE, horiz=TRUE, testbarplot[,2], ylab= 'group', xlab= '(x values)', space=c(1,0,0,0, 1,0,0,0)) text(testbarplot[,2], testbarplot[,1],

I'm new to R (previously used SAS primarily) and I have a genetics data frame consisting of genotypes for each of 300+ subjects (ID1, ID2, ID3, ...) at 3000+ genetic locations (SNP1, SNP2, SNP3...). A small subset of the data is shown below: SNP_ID SNP1 SNP2 SNP3 SNP4 Maj_Allele C G C A Min_Allele T A T G ID1 CC GG CT AA ID2 CC GG CC AA ID3 CC GG nc AA

Use only plain text emails. Don't attach file types that will be stripped. See the footer at the bottom of your email for more information. Do give us the data using dput(): > dput(testbarplot) structure(list(V1 = c(1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L), V2 = c(3L, 8L, 1L, 9L, 5L, 4L, 2L, 0L), V3 = structure(c(1L, 2L, 3L, 4L, 3L, 5L, 6L, 7L), .Label = c("A", "B",

Dear List, I have been trying to extract associations from a matrix whereby individual locations are within a certain distance threshold from one another. I have been able to extract those individuals where there is 'no interaction' (i.e. where these individuals are not within a specified distance threshold from another individual) and give these individuals a unique Group ID containing

I would like to know how I can assign a name to a name. I have a dataset that has different years in it. I am writing scripts using R and I would like to give a month a generic name and then use the generic name to do different analysis. The reason for the generic name would be so that I only have to change one thing if I wanted to change the year. For example. Year1 = 1999 datayear <-

Hi, I have two datasets stored in tab-separated format in the following way file1: country year1 year2 Germany var1 var1 Hungary var1 var1 file2: country year1 year2 Germany var2 var2 Hungary var2 var2 I can easily read in these files, but how can I merge them as a panel dataset? Thanks, Viktor

Hello, I am trying to see whether there has been a significant difference in whether people experienced damages from wildlife in two different years. I therefore have two columns: year 1: yes no no no yes yes no year 2: no yes no yes I wanted to do a chisq.test, but if I enter it this way: chisq.test(year1, year2) I get the error saying the columns are two different lengths. So then I tried

I need to apply a yearly inflation factor to some wages and supply some simple sums by work category. I have gone at it with a brute force "for" loop approach which seems okay as it is a small dataset. It looks a bit inelegant and given all the warnings in the Intro to R, etc, about using loops I wondered if anyone could suggest something a bit simpler or more efficent? Example:

Hi, I was wondering if I might be able to ask some advice about doing residual plots for the lmer function in the lme4 package. Our group's aim is to find if the expression staining of a particular gene in a sample (or "core") is related to the pathology of the core. To do this, we used the lmer function to perform a logistic mixed model below. I apologise in advance

Dear R Experts, I am trying to produce a legend for a series of plots which are generated in a loop. The legend is supposed to look like this: 2000: gamma=1.8 where gamma is replaced by the greek letter and both the year and the value of gamma are stored in variables. Everything works fine as long as I have only one data series: year = 2001 g = 1.9 plot(1) legend('top',

Hello! I have measurements (length and volume) of fish collected in two years. I want to know if the the relationship between length and volume is the same for both years. The number of fish measured is different for each year. I don't know whether lm or aov is more appropriate to use. Here are the two output options: Call: lm(formula = Volume ~ Length * Year) Residuals: Min 1Q

Hi everyone, I'm trying to send a FAX with the following configuration: Analog FAX machine (OKI) <----->SPA21000<----->LAN<----->Asterisk<--------> PSTN I'm restricted to use passthru mode for faxing, instead of T.38 protocol, because the Asterisk box is running v1.2 and cannot be changed as it is in a heavy production environment. Anyway, it "should"

Hello! I have a boot problem with ISOLinux 2.00, downloaded yesterday. The CD works fine with every PC except on an IBM Thinkpad. If I poweron the TP and try to boot from CD I get back a "isolinux: disk error 01, ax = 4211,8B". Then, if I reboot (ctrl-alt-canc) your isolinux works fine. May you help me? -- Stefano Pettini spettini at inwind.it New ICQ number: 159144497 Notary of

Hi R-helpers, My real data is a panel (unbalanced and with gaps in years) of thousands of firms, by year and industry, and with financial information (variables X, Y, Z, for example), the number of firms by year and industry is not always equal, the number of years by industry is not always equal. #reproducible example firm1<-sort(rep(1:10,5),decreasing=F) year1<-rep(2000:2004,10)

I am graphing longitudinal data from three time points. I'd like to draw a solid line from point 1 to point 2, and then a dashed line from point 2 to point 3. It works if I do it in two steps: > first.vector <- c(mean(year1$variable1), mean(year2$variable1)) > second.vector <- c(NA, mean(year2$variable1), mean(year3$variable1)) > plot(first.vector, type="b",

Dear R Helpers I have following data - cash_flow = c(7, 7, 107)  # 107 = Principle 100 + interest of 7% t = c(1,2,3) and zero rate table as rating         year1           year2           year3 AAA            3.60            4.17              4.73 AA              3.65            4.22              4.78 A                 3.72           4.32              4.93 BBB            4.10           

Good day, For lack of a better solution (or perhaps I am ignorant to something more elegant), I have been bootstrapping panel data by hand so to speak and I would like to know if there is a way to define multiple variables in a loop using the loop variable. I found a post (here: https://stat.ethz.ch/pipermail/r-help/2002-October/026305.html ) that discussed naming multiple variables but it

I have a matrix of claims at year1 that I get simply by claims<-read.csv(file="Claims.csv") qq1<-claims[claims$Year=="Y1",] I have MemberID and ProviderID for every claim in qq1 both are integers An example for the type of questions that I want to answer is how many times ProviderID number 345 appears together with MemberID 23 in the table qq1 In order to answer

Dear r experts, Sorry for this basic question, but I can't seem to find a solution? I have this data frame: df <- data.frame(id = c("id1", "id1", "id1", "id2", "id2", "id2"), A = c(11905, 11907, 11907, 11829, 11829, 11829), v1 = c(NA, 3, NA,1,2,NA), v2 = c(NA,2,NA, 2, NA,NA), v3 = c(NA,1,NA,1,NA,NA), v4 = c("N",

Dear R users, I have a big text file formatted like this: x x_string y y_string id1 id1_string id2 id2_string z z_string w w_string stuff stuff stuff stuff stuff stuff stuff stuff stuff // x x_string1 y y_string1 z z_string1 w w_string1 stuff stuff stuff stuff stuff stuff stuff stuff stuff // x x_string2 y y_string2 id1