similar to: datetime data and plotting

In the following, can anyone tell me why length(eee) returns 9? I was expecting 15398, and when I try to add this vector to a data frame with that many rows, it fails complaining that the vector is of length 9. In what I thought was an identical situation with a related dataset, the same code worked as expected. > length(fff) [1] 15398 > str(fff) int [1:15398] 20010102 20010102

I am trying to specify a legend title to be other than the variable name, but I find that the legend splits because scale_shape() takes effect but scale_colour() does not. Can someone spot my error? Here's some toy code that produces the problem on my system (R2.8.1, windows, today's CRAN package updates): library(ggplot2) a <- sample(letters[1:5],100,replace=T) b <-

Running R 2.13.1 on Windows XP. I would like to get week of the year (1-52) for each date. library(chron) dts <- dates(c("02/27/92", "02/27/92", "01/14/92","02/28/92", "02/01/92")) dts dts.chron <- as.chron(dts) dts.chron class(dts.chron) # all of these component extractions work: months(dts.chron) weekdays(dts.chron) years(dts.chron)

Dear all I use aggregate with variables of type numeric and dates. For type numeric functions, such as sum() are very fast, but similar simple functions, such as min() are much slower for the variables of type 'dates'. The difference gets bigger the larger the 'id' var is - but see this sample code: dts <- dates(c("02/27/92", "02/27/92",

Hello dear useRs and wizaRds, I encountered the following problem using the hist() method for the 'times' classes from package 'chron'. You should be able to recreate it using the code: library(chron) # pasted from chron help file (?chron) dts <- dates(c("02/27/92", "02/27/92", "01/14/92", "02/28/92", "02/01/92")) class(dts)

Hello, today I've updated on the newest R-Version. But sadly a function I needed didnt want to work: The input is e.g. days(as.Date("21-07-2005","%d-%m-%y")) the error is: Fehler in Math.Date(dts): floor nicht definiert f??r Date Objekte (Error in Math.Date(dts): floor not defined for date objects) Same for year. Only months gives me the correct output. In Version

Hello, I'm running FreeBSD 8.3-stable on a machine with an AMD A8-5600K cpu. tingo at kg-quiet$ uname -a FreeBSD kg-quiet.kg4.no 8.3-STABLE FreeBSD 8.3-STABLE #2: Fri Jan 4 19:18:15 CET 2013 root at kg-quiet.kg4.no:/usr/obj/usr/src/sys/GENERIC amd64 tingo at kg-quiet$ dmesg | grep CPU | head -1 CPU: AMD A8-5600K APU with Radeon(tm) HD Graphics (3618.02-MHz K8-class CPU)

The problem with POSIXt is that you must consider timezones and daylight vs. standard time issues even if you don't want to. This violates modularity (viz. your routines becomes coupled to unrelated information) and leads to subtle errors where different routines are assuming different time zones. The problem is that the time, date, day of the week, month, etc. of a date depend on its

Hello All: I am trying to generate a sequence of dates using library(chron). Using the following code, I got most of what I want, dts <- seq.dates("01/02/1998", "01/10/2001", by="day") dts <- dts[!is.weekend(dts)] a sequence of weekdays only (no weekend dates), with first observation appearing as 01/02/98 and the last 01/10/01. But I would

Hi, I am using aggregate() to add up groups of data according to year and month. It seems that the function aggregate() automatically sorts the levels of factors of the grouping elements, even if the order of the levels of factors is supplied. I am wondering if this is a bug, or if I missed something important. Below is an example that shows what I mean. Does anyone know if this is just the way

I know that this is correct: library(chron) x = dates("01-03-04", format="d-m-y", out.format="day mon year") print(x) It gives me the string "01 Mar 2004" which is correct. I also know that I can say: print(day.of.week(3,1,2004)) in which case he says 1, for today is monday. My question is: How do I combine these two!? :-) I have a

I'm getting warnings when I plot a zoo object: > dts <- chron(rep("2007-09-10", 5), paste("00:0", 0:4, ":00", sep=""), c("y-m-d", "h:m:s")) > dat.zoo <- zoo(1:5, dts) > plot(dat.zoo) Warning messages: 1: In v[[perm[1]]] : partial match of 'm' to 'month' 2: In v[[perm[2]]] : partial match of 'd'

Hello, I gather variants of this question have been asked previously. I have done some reading but only became more confused, as I suspect what I am trying to do is more basic than other applications. The following code readily calculates the difference in days between two dates: newdays <- ISOdate(2005, 5,12) - ISOdate(2006, 12, 22) However, I wanted to be able to deduct the dates in

what package should I include to use timeDate? I want to convert a double (num of millis) into date object.

Hi all, I need to compare time series data files of different time formats. I had no problems with text format using strptime. But how can I convert datetime numbers from Excel (days since 30.12.1899 00:00:00) into POSIXt objects? For example 29770.375 should be converted to "03.07.1981 09:00:00" I tried the following code and encountered strange results: t1-t0 gives 29770.33

Hello, I am trying to use HMisc describe on a data frame. I have specified certain variables as dates using, for example: df1$aidsdate <- dates(aidsdate,format="day.mon.year", origin=c(month = 1, day = 1, year = 1960)) When I use describe on the dataframe I get this error: Error in Ops.dates(weights, x) : * not defined for chron objects Has anyone had this problem? I had

note: whole function is below- I am sure I am doing something silly. when I use it like USGS(input="precipitation") it is choking on the precip.1 <- subset(DF, precipitation!="NA") b <- ddply(precip.1$precipitation, .(precip.1$gauge_name), cumsum) DF.precip <- precip.1 DF.precip$precipitation <- b$.data part, but runs fine outside of the function: days=7

Hi, I'm a bit confused how julian() works. If I understand right, it returns the number of days since the origin. I have a vector: > SLDATX[1:10] [1] "1986-01-06" "1986-01-17" "1986-02-02" "1986-02-04" [5] "1986-02-04" "1986-02-21" "1986-03-06" "1986-03-25" [9] "1986-04-06"

Dear Rusers, I have some data in .csv file like "2004-8-1" and "2004-10-1", and i need to convert them into days from the origin (January 1, 1960). I have tried the function date.mmddyyyy(), but cannot get it. Anybody can show me how to handle the date data? Thanks very much! My dataset like: time 2004-8-1 2004-10-1 2001-9-1 2002-9-1 -- With Kind Regards,

There seems no default setting for tck, causing problems for plot.times() > library(chron) > dts <- dates(c("02/27/92", "02/27/92", "01/14/92", + "02/28/92", "02/01/92")) > y<-chron(dts,out.format=c("dmy","h:m:s")) > y [1] 270292 270292 140192 280292 010292 > plot(y,1:5) Error in axis(n, at =