similar to: extracting quoted text from character string

Full_Name: Corey A. Moffet Version: 1.8.1 OS: Windows 2000 and RHL 9 Submission from: (NULL) (199.133.140.156) The function model.tables.aov and perhaps other model.tables methods refer the user to use the function se.contrasts when the design is unbalanced. The function name is se.contrast (singular).

Dear R-Help, I have a generated file that looks like the following: ----- Begin file ----- # # Output File # float Version 2002.700000000000 int Numdays 31 int NumOFEs 1 # # Hillslope-specific variables # char HillVarNames[ 3 ] {Days In Simulation} {Hillslope: Precipitation (mm)}

Dear R-help: Does anyone know of a package in R that will do Welch's modified F-test for heterogeneous error variances? Are there other statistical techniques available in R that test the equality of means when homoscedastisity is violated? 't.test' does this in the pairwise sense when var.equal = TRUE. With best wishes and kind regards I am Sincerely, Corey A. Moffet Support

Dear R-Help, Does anyone know of a way to use CGIwithR in Windows? David Firth the author of CGIwithR states "It ought to be possible to adapt it for use also in conjunction with web servers running under Windows NT ... but the author has no plans for that." I have developed some applications in R that I would like to make available through a web interface using CGIwithR but at this

I am having difficulty with plot.formula. For example: ------------------- dat <- data.frame(y = c(1,1,1,2,2,2,3,3,3,4,4,4), x1 = as.ordered(c(1,1,1,1,1,1,2,2,2,2,2,2)), x2 = as.ordered(c(1,1,1,2,2,2,1,1,1,2,2,2))) plot(y ~ x1 + x2, data = dat) # Works fine "interactively" asking: # "Hit <Return> to see next plot:" #

Dear R-help, Does any one know of a function/package in R that will test the assumption of spericity in a split-plot analysis of variance? How are people dealing with this issue in R? With best wishes and kind regards I am Sincerely, Corey A. Moffet Support Scientist University of Idaho Northwest Watershed Research Center 800 Park Blvd, Plaza IV, Suite 105 Boise, ID 83712-7716 (208) 422-0718

I am trying to reproduce an analysis done in SAS from which Type III Sums of squares are used. How can you get Type III sums of squares in an aov similar to what SAS provides? With best wishes and kind regards I am Sincerely, Corey A. Moffet Instructor Department of Range, Wildlife, and Fisheries Management Mail Stop 2125 Texas Tech University Lubbock, Texas 79409-2125 (806) 742-2843 Voice

I have some data that was created for import into a Lotus 1-2-3 spreadsheet and on of the columns is time. The time is akin to Julian were the value 1 is mapped "01-Jan-00 12:00:00 AM" in Lotus 1-2-3. Is there a function in an R package that can convert this numeric vector to a POSIXct vector? With best wishes and kind regards I am Sincerely, Corey A. Moffet Instructor Department

Is there a function/package that will allow you to test the hypothesis beta1 = x in a simple linear regression, where x is a constant? The AOV tests if beta1 in different from 0 but what if I want to know if beta1 one is different from 1? With best wishes and kind regards I am Sincerely, Corey A. Moffet Instructor Department of Range, Wildlife, and Fisheries Management Mail Stop 2125 Texas

I have a function for plotting soil texture that I am having a problem with. The function is: plot.psd <- function(sand, clay, ...) { conv.ter <- function(x, y) { x.con <- 100 - x - y*cos(1/3*pi) y.con <- y*sin(1/3*pi) data.frame(x=x.con, y=y.con) } plot(conv.ter(sand, clay), xlim = c(0,100), ylim = c(0,100*sin(1/3*pi)), axes = FALSE, xlab="",

I have been using the xtable package to export great latex tables and am very pleased with the package. Is there a way to modify the format of the tables: (1) some of my tables are to long to fit on a single page. I would like to modify the xtable to produce a longtable compatible with the longtable.sty in latex. Are these modifications possible and if so where are they documented? (2) Is it

Dear G?tz Wiegand and Corey Moffet, Thanks for answering while I went to get a cup of coffee. This list is really excellent! The answer, for you other beginners, is in R a tab is represented "\t" Tord > >Dear all, >I want to produce a tab separated text file but R 1.6.2 does not respond to >the tab key on my keyboard. > >When I paste:

I was writing Rd documentation for a new package when I came across this issue. Here's the smallest example: > library(tools) > cat("\\examples{x <- '<%=rnorm(1)%>'}\n",file=file.path(tempdir(),'test.Rd')) > readLines(file.path(tempdir(),'test.Rd')) [1] "\\examples{x <- '<%=rnorm(1)%>'}" >

Dear Mao Jianfeng, "r-help-owner" is not the place for help, but: r-help at r-project.org (CC-ed here) In any case, strsplit() does the job, i.e.: > unlist(strsplit("BCPy01-01", "-")) [1] "BCPy01" "01" You can work with the whole variable, like: splitpop <- strsplit(df1$popcode, "-") then access the first part with >

I have a set of character strings like below: > data3[1] [1] "CB01_0171_03-27-2002-(Sample 26609)-(126)" > I am trying to extract the text 03-27-2002 and convert this into a date for the same record. I keep looking at the grep function, however I cannot quite get it to work. grep("\d\d-\d\d-\d\d\d\d",data3[1],perl=TRUE,value=TRUE) Any hints?

Hello R-users, I have code that gives me the important variables from an analysis. I need to input these variables into a different analysis. To do this, I need to modify them slightly... 1) remove all numbers at the end of the variables, 2) remove all periods. I tried to do it with the awkward code below. It works to remove all the numbers, but when I try to remove the period everything

Hi, I'm looking for some way to pick up the numbers which are contained and buried in a long character. For example, outtree.new="(((B:1204.25,E:1204.25):7581.11,F:8785.36):8353.85,C:17139.21);" num.char =

I have a text string that contains text within two brackets. e.g. "testdata[3]" "testdata[-4]", "testdata[-4g]", I wish to "extract" the string enclosed in brackets? What is a good way to do this? e.g. fun(testdata[3]) = '3' fun(testdata[-4g]) = '-4g' --------------------------------- Moody friends. Drama queens. Your life?

Hi folks, Suppose I create the character vector charvec by > charvec<-c("a1.b1","a2.b2") > charvec [1] "a1.b1" "a2.b2" and then I use strsplit on charvec as follows: > splitlist<-strsplit(charvec,split=".",fixed=TRUE) > splitlist [[1]] [1] "a1" "b1" [[2]] [1] "a2" "b2" I was wondering

Dear R users, Suppose I have a data set with inconsistent names for a field. I desire to make these to consistent names. i.e "University of New Jersey", "New Jersey Uni", "New Jersey University" (3 different inconsistent names) to "The University of New Jersey" (consistent name) Below are arbitrary data set produced from "state.name" (built