similar to: binomial glm warnings revisited

Displaying 20 results from an estimated 1000 matches similar to: "binomial glm warnings revisited"

2003 Nov 23
4
remove 0 rows from a data frame
Dear all, As part of a larger function, I am randomly removing rows from a data frame. The number of removed rows is determmined by a Poisson distribution with a low mean. Sometimes, the random number is 0, and that's when the problem starts: My data frame: > temp occ x y dbh age 801 0 2977.196 3090.225 6 36.0 802 0 2951.892 3083.769 8 40.6 803 0 2919.111
2003 Oct 20
4
warning from return() in 1.8 but not in 1.7.0 (PR#4687)
To whom it may concern, I get the following message when I run my function: Warning message: multi-argument returns are deprecated in: return(call.fn, repl, time, from, to, last.year, occup.m, ant.occ.m, > version platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major 1 minor 8.0
2003 May 22
7
extract half a matrix
Dear all, I'm new to matrix operations in R. I couln't find a solution to the following problem among earlier help mails or in An introd to R, I guess because the question is really basic. I want to extract all above the diagonal, i.e. from 1 2 3 4 1 0 26 49 49 2 26 0 44 40 3 49 44 0 21 4 49 40 21 0 I want 26 49 44 49 40 21 Thanks in advance! Sincerely, Tord
2003 Dec 07
2
par(las = 1) not possible in polymap(), library(splancs)?
Dear all, I want my PhD thesis which I hand in tomorrow to look even nicer: Does polymap in the splancs library not allow horizontal plotting of y-labels? I have tried polymap(studyarea, xlab = "x (m)", ylab = "y (m)", las = 1) but it doesn't change the labels? Mayby some function in library(spatstat) support las? Thanks! Sincerely, Tord
2003 Jan 22
3
Error when using polr() in MASS
Dear all, I get an error message when I use polr() in MASS. These are my data: skugg grupp frekv 4 1 gr3 0 5 2 gr3 3 6 3 gr3 6 10 1 gr5 1 11 2 gr5 12 12 3 gr5 1 > > summary(polr(skugg ~ grupp, weights=frekv, data= skugg.cpy1.dat)) Error in optim(start, fmin, gmin, method = "BFGS", hessian = Hess, ...) :
2003 Feb 05
1
simplify a data frame
Dear all, For the past three hours I have tried simplify a data frame. I would be really happy if someone could help solving this, I'm sure simple, problem. I want to "aggregate" the data frame: ObjektID BalteNummer Baltessegment S.13 S.13.1 S.13.1.2 S.13 S.13.1 S.13.1.3 S.13 S.13.2 S.13.2.1 S.13 S.13.2 S.13.2.2 S.13 S.13.2 S.13.2.3 S.13 S.13.3 S.13.3.6 S.13 S.13.3 S.13.3.7
2002 Jan 04
4
line up a matrix
Dear all, I try to rearrange my ref. database (now in Excel!! :( ) for importing it into a reference manager program (RIS format). My file basically look like this [3,4]-matrix: rbind(c("a", "b", "c", "d"), c("e", "f", "g", "h"), c("i", "j", "k", "l")) [,1] [,2] [,3]
2003 Jul 21
2
bold AND italic as font in text()
Dear all, Is it possible to somshow plot text as italic AND bold. I tried font=c(2,3) in text(), but it doesn't work. It seems like the latter value is used. Thanks in advance! Sincerely, Tord ----------------------------------------------------------------------- Tord Sn?ll Avd. f v?xtekologi, Evolutionsbiologiskt centrum, Uppsala universitet Dept. of Plant Ecology, Evolutionary Biology
2003 Jul 31
2
how as.numeric() !-> factor
Dear all, I have divided two vectors: Np.occup97.98<- as.data.frame(cbind(site = levels(sums$site), Np.occup97.98 = sums$Ant.Nptrad97.98/Ant.trad$Ant.trad97.98)) > Np.occup97.98 site Np.occup97.98 1 erken97 0.342592592592593 2 erken98 0.333333333333333 3 rormyran 0.48471615720524 4 valkror 0.286026200873362 However, at a later stage of the analysis I want >
2003 Jan 02
1
replace NA with factor class
Dear all, I have a tree data matrix. For some trees I lack info about tree species, but I want to set them to be spruce. For some reason the tree species names on the remaining (non-NA) rows are changed into numbers (that I do not recognise). I guess that ifelse is not the correct function to use, but I have not found any better one in my searches. Thanks in advance! Sincerely, Tord >
2003 Sep 09
1
tree mortality risk model using glm()
Dear all, I've used glm(family=binomial(link="logit")) several times, but now I think that a log link is more appropriate. I want to fit a model for probability of tree fall (TF)), with tree diameter (dbh) and soil moisure (soil) as predictors. A large number of trees have been checked every second year whether they stand up (0) or have fallen (1). I assume that the tree fall
2001 Nov 21
2
distances from points to line
Dear all, I have discovered that there are many things that I used to do in my GIS which are easily done directly in R, for example calculating interpoint distances using geoR and pick out points inside a polygon using splancs. I now wonder, is there a function to create a line object like a watercourse and then calculate the distances between many points in space and this line? I couldn't
2002 Mar 20
4
spatial library
Hi everybody, I want to download the spatial library but I don't find it at the CRAN list package. Where can I find the package ? I have to download it to use the function correlogram. Thanks in advance, Paola. -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info",
2001 May 27
2
library for mixed GLM?
Dear all, I am taking a course in GLM given by a devoted SAS user. He has given us a homework where a mixed GLM with a logistic link and binomially distributed observations should be fitted. I know of the library nlme for mixed effect models but as I understand it, one cannot choose between different links and distributions in the functions provided there. I have so far managed very well with
2006 Dec 27
3
counties in different colours using map()
Hi, I would like to plot a map of US counties using different colors. map() seems to be the function to use, e.g. library(maps); map('usa'); map('county', 'colorado', add=T,fill = T, col=c(1:5)) plots Colorado counties using colours 1 to 5. However, I want each color to represent a certain value - a value to be picked from a data frame. This code should show a
2005 Sep 19
4
factor as seq() in for loop
Dear all, I would like to use the values in vegaggr.BLMCMR02$colony str(vegaggr.BLMCMR02) `data.frame': 1678 obs. of 3 variables: $ vegtype : Factor w/ 27 levels "2010","2020",..: 3 4 5 19 4 5 19 5 $ colony : Factor w/ 406 levels "0","1","10","100",..: 1 1 1 1 2 2 2 $ Totvegproparea: num 0.00055 0.03956 0.95705
2000 Dec 10
1
basic plot() question
Dear all, I try to plot a logstic regression model as follows: Valkror<- read.table("Valkror.txt", header=T) np.bark<- glm(Npinc~bark, family=binomial, data=Valkror) plot.formula(np.bark$fitted.values~ Valkror$bark) The above looks nice but I want to connect the points with a line so I try: plot.formula(np.bark$fitted.values~ Valkror$bark, type="b") but it gives a
2003 Jan 16
1
problem with as.data.frame.table
Dear all, I think that what I want is an as.data.frame.table-object, but see error message below. I have a data frame with one tree per row, diaclass tells if it is a small, mid or large tree > cpy.tradart[1:5, ] ObjektID diaclass 1 AX.Grb.1 bigdia 2 AX.Grb.1 middia 3 AX.Grb.1 middia 4 AX.Grb.1 smalldia 5 AX.Grb.1 middia > I want a data frame telling no of trees per diameter
2003 Jan 02
1
aggregate: "sum" not meaningful for factors
Dear all, I try to summarise my data per category using aggregate, but for some reason I get the error message "sum" not meaningful for factors even though my vector is numeric. The data set is shown below. Could someone please give a hint. Thanks in advance! Sincerely, Tord > names(test) [1] "ObjektID" "tallstubbyta" > is.factor(test$ObjektID);
2002 Mar 05
3
newbie: remove column with low mean from a matrix
Dear all, Sorry to bother you with one more newbie question. I have a dataobject with several hundreds of columns. I want to remove columns with a mean of the column values below a certain value: > a<- c(1,2,3,4,5,6) > b<-c(2,4,6,8,10,12) > c<- c(3,6,9,12,15,18) > test<- as.matrix(cbind(a, b, c)) > mean(a) [1] 3.5 > mean(b) [1] 7 > mean(c) [1] 10.5 Say the