similar to: Generation of labels for 2 factors

Hi, How can I include accents and signs like '?' '?' in the plots generated by R? I try, but R automatically transforms the name ex: > countries <- c("M?xico", "Espa?a") > countries [1] "M\216?xico" "Espa\216?a" > I've seen in some Spanish texts about R how is it normal to include labels of the plots and other names with

Cordial Saludo.Deseo sacar los datos resultado de una encuesta en mysql procesarlos en r con el paquete de lógica difusa y proyectarlos en una pagina web dinámica.... de preferencia una solución multiplataforma... Linux. Windows. Necesito la mejor solución... Ya que encuentro muchos paquetes en r que podrían servir pero no estoy seguro... No se si un server web ejecute r eficientemente usando

Suppose we observe N individuals, for each of which we have a time-series. How do we correctly create a lagged value of the time-series variable? As an example, suppose I create: A <- data.frame(year=rep(c(1980:1984),3), person= factor(sort(rep(1:3,5))), wage=c(rnorm(15))) > A year person wage 1 1980 1 0.17923212 2 1981

I wonder if this is an intentional feature or an oversight. in some column summaries or in ifelse operations, apparently I am losing the date property of my vector. > a <- c(198012, 198101, 198102) > b <- a*100+31 > c <- as.Date( as.character(b), "%Y%m%d" ) > summary(c) Min. 1st Qu. Median Mean 3rd Qu. Max.

Hola, ¿Alguien me puede indicar cómo conseguir que un gráfico se adapte al formato DIN-A4, con su correspondiente verticalidad?. ¿Hay que hacerlo "manualmente" o existe algún parámetro/función que lo controle?. Gracias. Eva [[alternative HTML version deleted]]

Hi people, I need reorganization several databases. I would like to know if that is possible in R. My problem is like that: original data base: Age x1980 x1981 1 5 8 3 7 9 5 9 15 7 11 20 future data base year age x 1980 1 5 1980 3 7 1980 5 9 1980 7 11 1981 1 8 1981 3 9 1981 5

Hi, I got following error in write.table() : > write.table(dataa, file="c:/data1.csv", row.names=F, col.names=T, sep=",") Error in file(file, ifelse(append, "a", "w")) : cannot open the connection In addition: Warning message: In file(file, ifelse(append, "a", "w")) : cannot open file 'c:/data1.csv': Permission denied

Hello all! I have a problem with ggplot2 library. I want to do an heat map and the y variables are the year months. If I use the following code, he y values are in alphabetical order, but I want it in month order. The code is: library(reshape) library(ggplot2) library(scales) p <- ggplot(data.m, aes(variable, Month)) + geom_tile(aes(fill = value),

Greetings all, I have two questions. I have a data set that is arranged in the example below. I wish to obtain a plot of the performance of each ID over Year on v1. It's not clear how I set this up? ID Year V1 1 1980 1 1 1981 2 1 1982 6 1 1983 4 2 1980 5 2 1981 5 2 1982 5 2 1983 6 Also,I would like to transpose the data to have the

A late friday afternoon coding question. I'm having a hard time thinking of the correct search terms for what I want to do. If I have a df like this: a <- data.frame(name=c(rep('a',10),rep('b',15)),year=c(1971:1980,1971:1985),amount=1:25) name year amount 1 a 1971 1 2 a 1972 2 3 a 1973 3 4 a 1974 4 5 a 1975 5 6 a 1976

Hi Starting to use R as a serious tool, I have come across a programming problem that I can't see the answer too yet. Can someone advise me plese. The problem is that I want to plot a series of lines which represent short term growths. All the data is in a single vector and I can indicate the index via a second vector. In GLIM, if the second vector is a factor, a single $GRA Size Year

Hi, I'm plotting a bar chart like this: ggplot() + geom_bar(data=res,aes(fill=f1,x=f2,y=y),stat="identity",position="dodge") f1 contains quite a few levels and the plot is really quite difficult to read when the order of bars on the graph and on the legend does not match. This problem has been discussed recently here:

Hi, I have a dataset of historical monthly temperature data that is grouped by weather station. I want to create z-scores of the monthly data using a base period of a subset of years. I subset the dataset first to include only data from the years (V2) that make up the base period so I could calculate the appropriate means and standard deviations V1 V2 V3 V12 V15 V16 V19 84

You can just use the same code that I provided before but now use your dataset. Like this df <- read.csv(file="data2.csv",header=TRUE) dates <- as.Date(paste(df$year,"-01-01",sep="")) myXts <- xts(df,order.by=dates) head(myXts) #The last command "head(myXts)" shows you the first few rows of the xts object year cnsm incm wlth

Hello, I could need some help on this one: >From the data.frame "Test.dataset2" below (TSCS data for 151 "countries.to.map" for "year" 1973-95; each "country.to.map" is described by a unique code), I would like to extract a vector "color" that for each "country.to.map" takes on the value of "dv" (a categorical variable with

Hi, I have a DF like this: DF = data.frame(read.table(textConnection(" A B C 1 b1 1999 0.25 2 c1 1999 0.25 3 d1 1999 0.25 4 a2 1999 0.25 5 c2 1999 0.25 6 d2 1999 0.25 7 a3 1999 0.25 8 b3 1999 0.25 9 d3 1999 0.25 10 a4 1999 0.25 11 b4 1999 0.25 12 c4 1999 0.25 13 b1 2001 0.5 14 a2 2001 0.5 15 b1 2004 0.33 16 c1 2004 0.33 17 a2 2004 0.33 18 c2 2004

Hello, We are looking to adjust the font size of the axis annotation on the graph that results from use of the metaplot() function. Metaplot seems to respond to cex and cex.lab to change those graphical parameters, but it doesn't respond to cex.axis. Is there a way to work around this by creating a customized x-axis, and if so, how? Thanks for all your help. Syntax is below. Best, Dawn

# Hello, # I have a data set that looks something like the following: site<-c(rep('a',5),rep('b',2),rep('c',4),rep('d',11)) year<-c(1980, 1981, 1982, 1993, 1995, 1980, 1983, 1981, 1993, 1995, 1999, c(1980:1990)) count<-c(60,35,36,12,8,112,98,20,13,15,15,65,43,49,51,34,33,33,33,40,11,0) data<-data.frame(site, year, count) # > site year count # 1

oky.. thank you very much to all of you On Sat, Sep 16, 2017 at 2:06 PM, Eric Berger <ericjberger at gmail.com> wrote: > You can just use the same code that I provided before but now use your > dataset. Like this > > df <- read.csv(file="data2.csv",header=TRUE) > dates <- as.Date(paste(df$year,"-01-01",sep="")) > myXts <-

Assuming the input data.frame, DF, is of the form shown reproducibly in the Note below, to convert the series to zoo or ts: library(zoo) # convert to zoo z <- read.zoo(DF) # convert to ts as.ts(z) # Note: DF <- structure(list(year = c(1980, 1981, 1982, 1983, 1984), cnsm = c(174, 175, 175, 172, 173), incm = c(53.4, 53.7, 53.5, 53.2, 53.3), with = c(60.3, 60.5, 60.2, 60.1, 60.7)),