similar to: Data frame transpose

Dear kind R-experts. Does anybody have an experience to use optim function? If yes, what is the main difference between two method "BFGS" vs "L-BFGS-B"? I used "BFGS" method and got what I wanted. But when I used "L-BFGS-B" the error message said that "L-BFGS-B needs finite values of fn". So that means "BFGS" method can handle even if fn

Hello, I think this is easy, but I can't seem to find a good way to do this in the R help. I have a list of sites, with multiple years of data for each site id. I want to create a new column that gives a number describing whether it is the 1st year ("1" ) the data was collected for the site, the second year ("2"), etc. I have different years for each siteid, but I don't

I'm estimating two models for data with n = 179 with four clusters (21, 70, 36, and 52) named siteid. I'm estimating a logistic regression model with random intercept and another version with random intercept and random slope for one of the independent variables. fit.1 <- lmer(glaucoma~(1|siteid)+x1 +x2,family=binomial,data=set1,method="ML",

Dear, R experts. Does anybody have experience with 'optim' function? I have an error message as the following. Error in optim(transcoefs, fn = hfdeviance, gr = hfdeviance.grad, method = "BFGS", : initial value in vmmin is not finite I want to make a comment when this happen. Is there way I can put *my* message after this error occur? Thanks in advance

I don't understand this behavior: > a <- c(0, 1, 2, 3) > b <- c(1, 2, 3, 4) > ifelse (a == 0, 0, b[a]) [1] 0 2 3 1 rather than the desired 0 1 2 3. Thanks for any explanation.

Hello! I have written an R script on a Windows platform where I calculate eight result matrices I plot using matplot. I would like to display the resulting plots successively, rather than simultaneously, and I was wondering if anyone could point me in the right direction as to how to do this. The graphs pop up in this manner by default when I run my script in S-PLUS, with tabs separating them so I

I'm having trouble figuring out how to create a function using "body<-" (). The help file for body() says that the argument should be a list of R expressions. However if I try that I get an error: > tmpfun <- function(a, b=2){} > body(tmpfun) <- list(expression(z <- a + b),expression(z^2)) Error in as.function.default(c(formals(f), value), envir) :

> I am using a random intercept model with SITEID as random and NAUSEA as > outcome. > > I tried using a dataset without missing values and changed my model > statement accordingly but still get the same error. Follwoing in an excerpt. > > anal.data <- read.table("nausea.txt", header=T, sep="\t") > > list(names(anal.data)) > [[1]] > [1]

I know R has a steep learning curve, but from where I stand the slope looks like a sheer cliff. I'm pawing through the available docs and have come across examples which come close to what I want but are proving difficult for me to modify for my use. Calculating simple group means is fairly straight forward: data(PlantGrowth) attach(PlantGrowth) stack(mean(unstack(PlantGrowth)))

Folks, I've run into trouble while writing functions that I hope will create and modify a dataframe or two. To that end I've written a toy function that simply sets a couple of variables (well, tries but fails). Searching the archives, Thomas Lumley recently explained the <<- operator, showing that it was necessary for x and y to exist prior to the function call, but I haven't

Hello everybody When one is working with complex matrices, "transpose" very nearly always means *Hermitian* transpose, that is, A[i,j] <- Conj(A[j,i]). One often writes A^* for the Hermitian transpose. I have only once seen a "real-life" case where transposition does not occur simultaneously with complex conjugation. And I'm not 100% sure that that wasn't a

Hi:   I am using the following code to read a data set in txt in R and using the follwoing model. But it seems to give me an error ' expected variable name error pos 134022'. Any help is greatly appreciated.   Code: anal.data <- read.table("nausea.txt", header=T, sep="\t") list(names(anal.data)) attach(anal.data) n.samples <- dim(anal.data) [1] # number of data

Greetings, I have a meta-analysis problem in which I have fixed effects regression coefficients (and estimated standard errors) from identical models fit to different data sets. I would like to use these results to create pooled estimated regression coefficients and estimated standard errors for these pooled coefficients. In particular, I would like to estimate the model \beta_{i} = \mu +

SAS proc rank has ties options of high and low that would allow producing ranks of the type found in the sports pages, e.g., rank (c(1,1,2,2,2,2,3)) == 1 1 3 3 3 3 7 Could R support these ties.methods?

Suppose this is my list of transactions: set.seed(200) tran=random.transactions(100,3) inspect(tran) items transactionID 1 {item80} trans1 2 {item8, item20} trans2 3 {item28} trans3 I want to get the 'transpose' of the data, i.e. transactionID items 1 {trans2} item8 2 {trans2} item20 3 {trans3} item28 4 {trans1} item80 I

When I run Rcmd check on a package on my Windows 2000 machine, I get a series of error messages like the following: * checking generic/method consistency ...c:\DOCUME~1\R5018~1.WOO\LOCALS~1\Temp/R utils138414013: cannot open c:DOCUME~1R5018~1.WOOLOCALS~1Temp/Rin138408157: no s uch file It looks as if a Windows style path to the temp directory is not being interpreted correctly, with backslashes

I am using a random intercept model with SITEID as random and NAUSEA as outcome. Thanks. Anamika I tried using a dataset without missing values and changed my model statement accordingly but still get the same error. Follwoing in an excerpt. > anal.data <- read.table("nausea.txt", header=T, sep="\t") > list(names(anal.data)) [[1]] [1] "SITEID"

I want to transpose a dataframe like level 2006 2007 2008 A .... B ..... C ........ into level year A 2006 A 2007 A 2008 B 2006 B 2007 ...... There is a procedure in SAS can do this, is there any function in R can do this? -- View this

I wanted a data frame component to be named "next", for example: > m <- data.frame (matrix (0, nrow=2, ncol=2)) > names (m) <- c("prev", "next") > m prev next 1 0 0 2 0 0 But "next" being reserved prevents $ indexing without quotes: > m$next Error: syntax error > m$"next" [1] 0 0 Although they are mostly

Hi Listers, Is there a way that I can transpose an array... Suppose I have the following array... x<-array(c(1,2,3,4),dim=c(1,2,2)) , , 1 [,1] [,2] [1,] 1 2 , , 2 [,1] [,2] [1,] 3 4 And I would like to get the following result... , , 1 [,1] [1,] 1 [,2] 2 , , 2 [,1] [,2] [1,] 3 [,2] 4 Thanks in advance, Marcio -- View this message in context: