similar to: confusion about what to expect?

Hi... With samba4 I sometimes feel like a bloody beginner even I use samba since ages. Miracle of the day: Users connecting using samba4 cannot write to group writeable folders even they should be able to. I upgraded one 3.6 fileserver to 4.2.3. PDC is always a samba 4.2.3 instance. I am using samba4 in classic PDC mode for a couple of reasons. On my fileserver I have a folder called

Hello all, due to unexplained differences between statistical results from collaborators and our lab that arose in the same large proteomics dataset we reevaluated the t.test() function. Here, we found a weird behaviour that is also reproducible in the following small test dataset: Suppose, we have two vectors with numbers and some missing values that refer to the same individuals and that

Hello All, I was wondering if it's possible to reshape data from long to wide in R without using a "timevar". I've pasted some sample data below along with some code. The data are sorted by Subject and Drug. I want to transpose the Drug variable into multiple columns in alphabetical order. My data have a variable called "RowNo" that functions almost like a

I want to change the way the plot is appearing in the barchart .. testdata <-

Hi All, For the following code, I'm not sure why the error bars are appearing horizontal. Can someone please tell me how to fix the problem. testdata <-

I posted this on R help, and a few others responded indicating they too were able to replicate the error as a function of missing data. I believe this should not be the case and hence and reporting it here. ### Code provided on R-Help by Ivar Herfindal # Simulate data testdata <- cbind.data.frame(gr=3Drep(letters[1:4], each=3D5), = aa=3Drnorm(20), bb=3Drnorm(20)) # Introduce some missingness

For the following code below, the x-axis ticks are 1,2,3,4,5,6,7 when I was expection them to be 1,2,8,9,10,11,12. Please help me figure out where is the mistake. library(lattice) testdata <- as.data.frame(t(structure(c( 1,2005,9.24,6.18,634, 2,2005,8.65,6.05,96, 8,2004,6.81,6.51,16, 9,2004,9.0,7.29,8, 10,2004,8.84,6.18,524, 11,2004,8.54,6.35,579, 12,2004,9.97,6.3,614, 12,2005,8.75,5.84,32,

I have a text string that contains text within two brackets. e.g. "testdata[3]" "testdata[-4]", "testdata[-4g]", I wish to "extract" the string enclosed in brackets? What is a good way to do this? e.g. fun(testdata[3]) = '3' fun(testdata[-4g]) = '-4g' --------------------------------- Moody friends. Drama queens. Your life?

Dear Everyone, I am having problems with use of the reshape package's cast function using length as an aggregating function. Unexpectedly, I receive the error: 2 arguments passed to 'length' which requires 1 I don't understand this at all - the data I'm using is very simple, and appears almost identical to that used in the ChickWeight example in the package. The problem can

Hello All, Recently developed the code below for graphing patterns of chemotherapy administration. As someone just starting to use R in their work, I managed to figure out some parts of the code but needed help with others. setwd("N:/Regimen Coding/0906/Plots Test") getwd() TestData <- structure(list(profile_key = c(1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3), line = c(1, 1,

Hi All.. Have a question.. For the following r code testdata <- as.data.frame(t(structure(c( "1/1/04","LV1",3.8,2,87, "2/1/04","LV1",3.2,3,28, "3/1/04","LV1",3.4,3,88, "4/1/04","LV1",3,2,26, "5/1/04","LV1",3.8,2,87, "6/1/04","LV1",3.2,3,28,

Sorry guys, but I have another one: I want to write a function that returns a certain column of a dataframe. The function accepts two argument: the dataframe and the name of the column, but the column is not given as a "string" but as a variable name. EXAMPLE ---------------------- > testdata start stop censor groupvar var1 var2 1 0 1 0 1

Dear all, I have a dataset where the interaction is more than obvious, but I was asked to give a p-value, so I ran a logistic regression using glm. Very funny, in the outcome the interaction term is NOT significant, although that's completely counterintuitive. There are 3 variables : spot (binary response), constr (gene construct) and vernalized (growth conditions). Only for the FLC construct

I am trying to add confidence (error) bars to lattice barcharts (and dotplots, and xyplots). I found this helpful message from Deepayan Sarkar and based teh code below on it: http://finzi.psych.upenn.edu/R/Rhelp02a/archive/50299.html However, I can't get it to work with groups, as illustrated. I am sure I am missing something elementary, but I am unsure what. Using R 2.1.1 on various

Hi,   I am trying to import data directly from an excel spreadsheet using the RODBC package. I am getting the following error messages, wondering if anyone can help me with it?   > connection = odbcConnectExcel('D:\\R files\\TestData.xls') > tables = sqlTables(connection) > tables    TABLE_CAT TABLE_SCHEM  TABLE_NAME TABLE_TYPE REMARKS 1 D:\\R files\\TestData        <NA>

Hello. I have used the "party" package to generate a regression tree as follows: >origdata<-read.csv("origdata.csv") >ctrl<-ctree_control(mincriterion=0.99,maxdepth=10,minbucket=10) >test.ct<-ctree(Y~X1+X2+X3,data=origdata,control=ctrl) The above works fine. Orig data was my training data. I now have a test data file (testdata), and

I am new to R. I want to graph group data using a "Traditional Bar Chart with Standard Error Bar", like the kind shown here: http://samiam.colorado.edu/~mcclella/ftep/twoGroups/twoGroupGraphs.html Is there a simple way to do this? So far, I have only figured out how to plot the bars using barplot. testdata <- scan(, list(group=0,xbar=0,se=0)) 400 0.36038 0.02154 200 0.35927

Hi, I encountered a problem when I am trying to write my own function which contains another function. To simplify a problem, I tried the following simplified function, hope someone can idenfity the problem for me. I have a simple data frame called "testdata" as following: >

Dear R community I have a problem to access particular list. I have a code given below where there is recursive process. It is not possible to run it because there are few other functions involved inside like sv, LN, RN etc. k=0; n=0; variable=c(); vr<-list() func <- function(data,testdata) { . . if(......){ n<<-n+1; vr[[n]] <<- variable; print(vr)

I'm sure this is a really simple problem, but I've spent hours digging and I keep running into roadblocks. I'm trying to get a simple chart with three time series. Similar to the attached example http://www.nabble.com/file/p25398419/Excel%2Bchart%2Bexample.pdf Excel+chart+example.pdf , something that was quite easy to do in Excel, except that I need a log y-axis: something that R