similar to: help("print") seems truncated

Displaying 20 results from an estimated 10000 matches similar to: "help("print") seems truncated"

2003 Nov 02
2
cannot have a function argument named 'break'
Dear list - I just discovered to my surprise that I cannot define a function with an argument named 'break' or 'while'! 'breaks' is okay. Maybe this is no surprise to the R developers. R-1.7.1, 2003-06-16, i686-pc-linux-gnu. - tom blackwell - u michigan medical school - ann arbor -
2003 May 05
5
null plotting symbol ?
I am calling plot() with argument pch as a vector of numeric symbol codes, the same length as x and y. Is there some code which produces no symbol - a blank - so that I can come back with a second call to points() and fill in these locations using a different fill color and a different symbol size ? There's always a work-around, but both x and y are generated on the fly by calls
2004 Mar 15
0
Simple numeric
Regarding the flame, your might be interested in the following: read.table(myfile, as.is=T) which will interpret character columns as character rather than factor and still reads in the numeric columns as numbers. You can also specify specific columns such as as.is=3:4 if you want columns 3 and 4 to be character but other character columns to be factors. --- Date: Mon, 15 Mar 2004 11:04:08
2003 May 22
1
Plot observed vs. fitted values (weighted nls)
Dear WizaRds, Given the experimental data, csdata<-data.frame( time=c(0,1,3,9,20), conc=c(638.697,395.69,199.00,141.58,112.16) ) weighted nls is applied, wt.MM<- function(resp, time,A1,a1,A2,a2) { pred <- A1*exp(-a1*time)+A2*exp(-a2*time) (resp - pred) / sqrt(pred) } # cs.wt <- nls( ~ wt.MM(conc, time,A1,a1,A2,a2), data=csdata,
2003 Oct 02
3
Query: weighting cells in histogram
I have the 'breaks' for the histogram ('hist') but I want weight the cells instead of using actual observations. I thought that using freq=FALSE implied that the numbers in 'x' were weights but this turned out to be wrong. Any help and/or comment is very much appreciated. Regards, M?rten M?rten Bjellerup Doctoral Student in Economics School of Management and Economics
2003 Nov 10
8
Memory issues..
Hi dear R-listers, I'm trying to fit a 3-level model using lme in R. My sample size is about 2965 and 3 factors: year (5 levels), ssize (4 levels), condition (2 levels). When I issue the following command: > lme(var~year*ssize*condition,random=~ssize+condition|subject,data=smp,method ="ML") I got the following error: Error in logLik.lmeStructInt(lmeSt, lmePars) :
2003 Oct 27
3
expanding factor with NA
I have a factor (with "n" observations and "k" levels), with only "nobs" < n of the observations not missing. I would like to produce a (n x k) model matrix with treatment contrasts for this factor, with rows of NAs placeholding the missing observations. If I use model.matrix() I get back a (nobs x k) matrix. Is there an easy way to get the (n x k) without
2003 Oct 07
2
R-1.8.0 memory.limit()
Using R-1.8.0 (d/l and compiled on 2003-10-01) on WinXP, I seem to be unable to determine the maximum memory allocated to R. The help still says to use memory.limit(size=NA), but this returns the value NA. In addition, I have set --max-mem-size=2G but I run out of memory somewhere around 500Mb (which is why I am trying to find out how much memory is allocated). I don't have any other programs
2003 Oct 15
3
Fw: SIMCA algorithm implementation
I have used PCA for data classification by visual examination of the 3D scatter plot of the first 3 principal components. I now want to use the results to predict the class for new data. I have used predict.princomp to predict the scores and then visualise the results on a 3D scatter plot using the rgl library. However, is there an R function that will fit the new data to the class assignments
2003 Nov 20
3
file not found?
Hi R maintainers: when I use update.packages() And I try to update the package "maps" maps : Version 2.0-9 in D:/rw1080/library Version 2.0-10 on CRAN Update (y/N)? y The following message appears: trying URL `http://cran.r-project.org/bin/windows/contrib/1.8/maps_2.0-10.zip' Error in download.file(url, destfile, method, mode = "wb") : cannot open URL
2003 Apr 22
7
Subject: Eliminate repeated components from a vector X-Mailer: VM 7.00 under 21.4 (patch 6) "Common Lisp" XEmacs Lucid Reply-To: fjmolina at lbl.gov FCC: /home/f/.xemacs/mail/sent Does anyone know how I can eliminate repeated elements from a vector?
2003 Mar 05
2
problem with cclust[er] package
I have checked that section already. Sorry, I should have mentioned that. Memory limit increase does not work. Installtion of msvcrt.dll does not work either. Thank you. -----Original Message----- From: ripley at stats.ox.ac.uk [mailto:ripley at stats.ox.ac.uk] Sent: Wednesday, March 05, 2003 2:44 PM To: Igor Oleinik Cc: r-help at stat.math.ethz.ch Subject: Re: [R] problem with cclust[er]
2003 Jun 04
2
plot rpart tree's from list object
Hello, i want the post plot's from a rpart list object with 18 tree's , getting no error - but getting no files,too? Perhaps i should using assign!? for (i in 1:length(treeList)) { post(treeList[[i]],filename=paste("Tree","i",sep=".ps"), title="Arbeitszufriedenheit", digits=getOption("digits") - 0,use.n=TRUE) } many thanks for help,
2004 Mar 24
7
binding vectors or matrix using their names
Hello list, I have two vectors x and x2: x=runif(10) x2=runif(10) and one vectors with their names : my.names=c("x","x2") I would like to cbind these two vectors using their names contained in the vector my.names. I can create a string with comma ncomma=paste(my.names,collapse=",") and now, I just need a function to transform this string into a adequate
2003 Oct 06
4
Apply and its friends
Hi, Forgive a very basic question... I need to take two lists-of-lists, and apply a function to each pair of elements in the lists to return a single list... For example l1 <- list(1:5,6:10,2:15) l2 <- list(1:8,4:12,1:19,4:20) I could easily do an lapply across each of them, but is there a function that does a sort-of pairwise-apply across both together? Does anybody know of a good
2003 Dec 18
3
mclust - clustering by spatial patterns
Dear All, I have spatial data (presence/absence for 4000 squares) on 250 bird species and would like to use a model-based clustering technique to test for species associations. Is there any way of passing a distance/correlation matrix to mclust as with hclust, rather than the actual data? Or alternatively, is there a way of getting mclust to handle binary data? I'd appreciate any
2002 Mar 14
2
Some users can't log in -- server shows username as "nobody"
Okay, this is a recurring problem that really has me frustrated. I have a samba server that's using security=server. There are four people who use it. It works fine for three of them, but the fourth one gets endlessly prompted for his password and is never allowed to log in. All are from NT 4.0 clients. What's really puzzling is that when I look at the log at debug level 2, I get the
2000 Aug 21
2
rect() question.
Hello. I have another rect question. If I want to make a lot of rectangular, without borders, and without any spaces between them, how could I do it? I.e. > plot(-1:1., -1:1., type = "n") > rect(0,-1,1,1,col="red",lwd=0,border=F,xpd=T) > rect(-1,-1,0,1,col="blue",lwd=0,border=F,xpd=T) will produce two rectangular, but there is space between them. How
2004 Feb 17
10
How to write efficient R code
I have been lurking in this list a while and searching in the archives to find out how one learns to write fast R code. One solution seems to be to write part of the code not in R but in C. However after finding a benchmark article (http://www.sciviews.org/other/benchmark.htm) I have been more interested in making the R code itself more efficient. I would like to find more info about this. I have
2004 Jan 04
5
Analyzing dendograms??
I have used heatmap to visualize my microarray data. I have a matrix of M-values. I do the following. #The distance between the columns. sampdist <- dist(t(matrix[,]), method="euclidean") sclus <- hclust(sampdist, method="average") #The distance between the rows. genedist <- dist(matrix[,], method="euclidean") gclus <- hclust(genedist,