similar to: "subscript out of range" message

Hi All: I am working with a dataset on Arsenic toxicity, and I am trying to calculate the 20th, 40th, 60th, 80th, and highest percentiles for a variable, dietary Moisture (variable name dMoist). The inbuilt function quantile(dMoist) would print 0, 25th, 50th, 75th, and 100th percentile. Does there exist a function that can calculate xth percentile (where x = 10th, 20th, ... etc) values?

I don't find how to do what I need to do in Dalgaard or 'R Cookbook', so I'm asking here. I have a data frame with water chemistry data and I want to start exploring these data. There are three factors (site, date, chemical) associated with each measurement. The data frame looks like this: > summary(chemdata) site_id.sample_date.param.quant

Hi All: Greetings, and best wishes from the festive times here at Kolkata, India -- the time of Durga Puja celebrations. I seek your advice as I try plotting lines for my data. The problem: I have created a dataframe that looks like this (name: myFrame): lowest second third fourth highest significance INAS 0.107 0.115 0.123 0.115 0.166 0.000 MMA 0.091 0.107 0.115

R Users: My question is probably more about elementary statistics than the mechanics of using R, but I've been dabbling in R (version 2.2.0) and used it recently to test some data . I have a relatively small set of observations (n = 12) of arsenic concentrations in background groundwater and wanted to test my assumption of normality. I used the Shapiro-Wilk test (by calling shapiro.test()

Hello, I have a dataframe (var_1, var_2, ..., var_n) and I would like to export summary statistics to Latex in the form of a table. I want specific summary statistics by crossing numerous variables 2x2 AT ONCE. In each cell I would like sometimes to have the median (Q1 - Q3), or frequency and proportion, etc. CrossTable, xtab, etc... do not allow for multiple 2 by 2 crosstabulation. The table

Type e.g.: quantile(x,0.1) or Quantile(x,0.8) Which calculates the 10th and 80th quantile Matthias Templ -----Urspr??ngliche Nachricht----- Von: arinbasu at softhome.net [mailto:arinbasu at softhome.net] Gesendet: Montag, 26. April 2004 09:29 An: r-help at stat.math.ethz.ch Betreff: [R] Looking for help in calculating percentiles Hi All: I am working with a dataset on Arsenic toxicity,

#is there a way to get NA in the table of descriptive statistics instead of the function stopping Thank you in advance #data x.f <- structure(list(Site = structure(c(9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L, 9L), .Label = c("BC", "HC", "RM119", "RM148", "RM179", "RM185",

Hi all, I am looking for a clever way to create the following graph using R: I got information on the shares of some subgroups over time (summing up to 1 in each year). The graph I want to create should display the development of the individual shares over time by shading rectangulars for each share in a different color. Is there a clever of doing this? Thanks for your help Stefan

Dear all, After a thorough research, I still find myself unable to find a function that does linear regression of 2 vectors of data using the "total least squares", also called "orthogonal regression" (see : http://en.wikipedia.org/wiki/Total_least_squares) instead of the "ordinary least squares" method. Indeed, the "lm" function has a

Hi, I try to boxplot following data on the subset of (V1,V3,V5,V7) and (V2,V4,V6,V8) V1 V2 V3 V4 V5 V6 V7 V8 2 4 6 7 12 33 43 53 how can I use boxplot function to plot it? thanks, William

Hi All: I have written an R search plug-in based on Prof Jonathan Baron's R search site. This Firefox/Netscape plug-in lets you search R sites and R discussion group archives directly from your Mozilla (Seamonkey) or Firefox or Netscape browser. Here is the link to the installer for the plug-in: http://arinbasu.bravehost.com/installer.html If you want the source files or have other comments

Hello list members, I'm looking for a way to force the results of a crosstabulation to be square - that is, to include 0 values. For example: table(letters[1:4],letters[c(1:3,3)]) yields: a b c a 1 0 0 b 0 1 0 c 0 0 1 d 0 0 1 I would like to return: a b c d a 1 0 0 0 b 0 1 0 0 c 0 0 1 0 d 0 0 1 0 Any suggestions? Thanks! -- Manuel A. Morales

Hello! I have dataset where one variable is 'multiresponse', like this: [1] "1 2" "1 2 3" "4" "1 4" "4 3" etc. 'responses' separated by space. observations in different 'rows' of data.frame. I can do strsplit(data$var,' ') and make a list, where multiple responses are elements of character vectors, like this: $

I want to form a 3x3 crosstabulation for the signs of two vectors (i.e. Negative, Zero, Positive). The problem is that I am simulating the data so for some iterations one of the categories is absent. Thus the resulting table shrinks to 3x2. I want it to be 3x3 with zero column corresponding to the missing category. Moreover, I have tried but failed to give the dimension names. -- Sohail Chand

Hi All: A couple of weeks back, I asked a question on the list that I was invited to provide an introductory lecture on R to a group of academicians in Kolkata. I thank all of you who had generously guided me in providing me web links and words to the wise. Time to give back. I did the presentation on introduction to R and uploaded the presentation files at the following site:

Hi All: This follows my earlier post on webized slides on lecture presentation on introducing R. I learned that in Mozilla (Firefox) browsers, the slides did not show up. Sorry for the no show. As a reluctant windows user, I kind of carelessly clicked through Powerpoint to convert the presentation file to its html form, unwittingly leading to the mess. See if it got corrected now (I do not have

Before I reinvent the wheel, I have need for a relatively straightforward crosstabulation (2 x n) function. I know that R has table(), ftable(), xtabs(), and summary(xtabs()), but none of these produce a fully "tricked" out cross-tabulation with marginal totals, expected cell frequencies, and an array of statistics about the contingency table. Is there a more complete (something

? stato filtrato un testo allegato il cui set di caratteri non era indicato... Nome: non disponibile URL: <https://stat.ethz.ch/pipermail/r-help/attachments/20110828/d35f51a1/attachment.pl>

Hello R-users, My toy example: aa<-c(1:5) bb<-c(NA,2,NA,4,5) cc<-c(1,2,NA,4,NA) dd<-c("A","B","B","A","C") df<-data.frame(aa,bb,cc,dd=as.factor(dd)) table(unlist(df[,1:3])) Can anyone point me to what function let's me do a crosstabulation between table(unlist(df[,1:3])) and df$dd? I want to find out when dd==A (or B,

how about this: tapply(vector,list(factor1,factor2),function)? -----Original Message----- From: owner-r-help at stat.math.ethz.ch [mailto:owner-r-help at stat.math.ethz.ch]On Behalf Of Murray Jorgensen Sent: 24. september 2000 02:46 To: R-help Subject: [R] Crosstabulation I can't seem to find a function in R similar to Splus crosstabs() for creating a multi-way table from factors and a