similar to: sprintf("%c",...)

something like "sprintf" in C? so I can do: print(sprintf("the correct result is %3.4f\n", myresult)); ------- Also, I am desperately looking for a "clear console screen" function in R... thanks a lot! [[alternative HTML version deleted]]

Full_Name: Chris Evans Version: 2.3.1 OS: Windoze XP Submission from: (NULL) (217.34.100.197) If I give "vignette("introduction")" I get: Error in sprintf(gettext(fmt, domain = domain), ...) : use format %s for character objects vignette() works for some other vignettes and "vignette()" gets me a list of vignettes and shows three with the name

I can't get the PERL subexpression translated to R. Following, for example, B. Ripley's http://finzi.psych.upenn.edu/R/Rhelp02a/archive/58984.html I am using sub, but it looks like an ugly substitute. Assume I want to extract the first alpha part and the first numeric part, but only if they are in sequence. Do I really have to use the sub twice, first extracting the first variable, then

Hello; I am a R newbie and would like to know correct and efficient method for doing string replacement. I have a large data set, where I want to replace character "M", "b", and "K" (currency in Million, Billion and K) to millions. That is 209.7B with (209.7 * 10e6) and 100.00K with (100.00 *1/100) and etc.. d <- c("120.0M", "11.01m",

Hi all, I am using R trying to get a inverse matrix of (X^T)X , but I keep getting the error message like: no b argument and no default value for sprintf(gettext(fmt, domain = domain), ...) . -------------------------------------------------------------------------------------------- # my code X<-Matrix(rep(1,500),100,5) X[lower.tri(X)]<-1-10^-7 XtX<- t(X)%*% X XtXu<-lu(XtX)

Would it be good enough to pass it as a formula? Using your definition of foo foo(~ A -> result) ## result <- ~A foo(~ result <- A) ## ~result <- A On Fri, Mar 1, 2024 at 4:18?AM Dmitri Popavenko <dmitri.popavenko at gmail.com> wrote: > > Hi everyone, > > I am aware this is a parser issue, but is there any possibility to capture > the use of the inverse

Dear Sir I would appreciate recieving the manul instruction of the program foe geochemical calculations.please what are the requirmentsof using the program Thanks Tanat university faculty of science , geology department ,tanta Egypt Prof.Mohamed Fouad Ghoneim Ph.D- D.Sc. Head of Geology Department Faculty of Science Tanta University, Egypt www.profghoneim.tk

Hi, I am new to R, coming from a few years using Stata. I've been twisting my brain and checking several R and S references over the last few days to try to solve this data management problem: I have a data set with a unique patient identifier that is repeated along multiple rows, a variable with month of patient encounter, and a continous variable for cost of individual encounters. The data

I am trying to read an ftable using read.ftable, but I get the following error message: > jobSatTable <- read.ftable("http://definetti.uark.edu/~gpetris/stat5333/jobSatisfaction.dat",skip=2) Error in seek(file, where = 0) : no applicable method for "seek" In addition: Warning messages: 1: no non-missing arguments to max; returning -Inf 2: no non-missing arguments to

Hi everybody, I need your precious help for, I think, a simple request, but I do not manage to solve this. When I use a "table" function with dates in the rows, the rows are coerced to number after the table function. So I need to transform the row names into date format. But I do not manage. Therefore, for an example, I manage to write this : datetest<-"06/01/2001"

Hi everybody, I need your precious help for, I think, a simple request, but I do not manage to solve this. When I use a "table" function with dates in the rows, the rows are coerced to number after the table function. So I need to transform the row names into date format. But I do not manage. Therefore, for an example, I manage to write this : datetest<-"06/01/2001"

I have date data as a numeric and hourly data in 0 to 2300 hours in a dataframe. d <- rep(20110101,24) h <- seq(from = 0, to = 2300, by = 100) df <- data.frame(LST_DATE = d, LST_TIME = h, data = rnorm(24, 0, 1)) S <- chron(dates. = as.character(df$LST_DATE), times. = paste(as.character(df$LST_TIME/100), ":0:0", sep = ""), format =

ABCD are four matrix. A * Inverse((Transpose(A)*Tranpose(B)*B*A+C)) * Transpose(A) * Transpose(B) * D how to write in R in an efficient way? --------------------------------- [[alternative HTML version deleted]]

Hello List, I would like to orthonormalize vectors contained in a matrix X taking into account row weights (matrix diagonal D). ie, I want to obtain Z=XA with t(Z)%*%D%*%Z=diag(1) I can do the Gram-Schmidt orthogonalization with subsequent weighted regressions. I know that in the case of uniform weights, qr can do the trick. I wonder if there is a way to do it in the case of non uniform

It seems like you want to use -> and <- as arrows with different meanings to "A gets the value of B" in your package, as a means of writing expressions in your package language. Another possibility would be to use different symbols instead of the problematic -> and <-, for example you could use <.~ and ~.> which are not at all flipped or changed before you get a chance

Dear All, The following code should return 1, but it returns 0: source("http://r-bc.googlecode.com/svn/trunk/R/bc.R") bc("9 % 2") Do you confirm this bug? Paul

Full_Name: Wacek Kusnierczyk Version: 2.8.0 and 2.10.0 r48163 OS: Ubuntu 8.04 Linux 32bit Submission from: (NULL) (129.241.198.172) the following code illustrates a problem with sprintf which consistently causes a segfault when applied to certain type of arguments. it also shows inconsistent consequences of the segfault: (e = tryCatch(stop(), error=identity)) # e is an error object

Hi I'm using R 2.0 in SuSE 9.2. When I plot data as a boxplot, the boxes appear on the plot in alphabetical order (of group) rather than the order in which they appear in the data. So far, the only thing I can do to fix this is to prefix the group labels with a,b,c...etc to trick R into plotting them in the right order. Can sorting be turned off? How should I address this sensibly? Thanks

In R's sprintf() if any of the arguments has length 0 the function aborts. E.g., > sprintf("%d", integer(0)) Error in sprintf("%d", integer(0)) : zero-length argument > sprintf(character(), integer(0)) Error in sprintf(character(), integer(0)) : 'fmt' is not a non-empty character vector This comes up in code like x[nchar(x)==0] <-

I have two vectors, a and b. b is a text file. I want to find in b those elements of a which occur at the beginning of the line in b. I have the following code, but it only returns a value for the first value in a, but I want both. Any ideas please. a = c(2,3) b = NULL b[1] = "aaa 2 aaa" b[2] = "2 aaa" b[3] = "3 aaa" b[4] = "aaa 3 aaa"