Displaying 20 results from an estimated 2000 matches similar to: "Interpretation of loess"
2010 Aug 31
1
summary in Hmisc and Latex
Dear all,
With the latest update of Hmisc I no longer have any problems with latex. However using the ctable option produces latex code that at least on both the miktex distribution at work and mactex distribution at home refuses to run due to an extra blank line inserted between the multicolumn lines in the latex code... It runs fine if the line is deleted or if the ctable option is left out.
2008 Oct 08
1
NA's in multiple choice summary table in Hmisc
Hi,
I have a set of 30 binary variables measuring side effects after drug
treatment. Since each subject can have multiple side effects, I want to
display these side effects in a multiple choice table. I'm using the summary
and mChoice functions of the Hmisc package, because it produces nicely
formatted latex tables. My problem is, that table includes a category for
people who have at
2010 Jun 18
1
Latex problem in Hmisc (3.8-1) and Mac Os X with R 2.11.1
Dear all,
I did post this more or less identical mail in a follow up to another
question I posted, but under another heading. I try again, but now
under the correct header.
upon running this code (from the Hmisc library-latex function) I
believe the call to summary.formula is allright and produces wonderful
tables, but the latex command results in a correct formatted table but
where all the
2010 Apr 09
0
Trouble with mChoice() in the Hmisc package.
Hi All:--
I've started using the the Hmisc reporting facilities recently, mostly
successfully. I'm having some trouble with mChoice() multiple-choice
objects, though. Here's some example code and output from R-help a
couple of years ago:
library(Hmisc)
Symptom1 <- c("Headache", "Headache", NA)
Symptom2 <- c(NA, "Anxiety", NA)
Symptoms <-
2003 Jul 30
2
Plotting a function with curve()
Why does
> curve(function(y) y^2, from=0,to=1)
not work, whereas
> myf <- function(y) y^2
> curve(myf, from=0,to=1)
work?
For the former, I get the error message
Error in curve(function(y) y^2, from = 0, to = 1) :
'expr' must be a function or an expression containing 'x'
I'm using R1.7.0 under Windows XP.
Damon Wischik.
2003 Jan 10
1
Superposed histograms
I woud like to plot cumulative histograms. Specifically,
I have data like
Sex M M F M F F M F
Height 6 6.3 6.1 5.5 7.2 6.2 5.9 6.0 ....
and I want to plot a histogram of the distribution of all heights,
colouring the histogram bars according to sex, for example
| o
| oo o
| o oo ** o o = observations of women
| o o*o***o * = observations of
2005 Jul 12
1
getting panel.loess to use updated version of loess.smooth
I'm updating the loess routines to allow for, among other things,
arbitrary local polynomial degree and number of predictors. For now,
I've given the updated package its own namespace. The trouble is,
panel.loess still calls the original code in package:stats instead of
the new loess package, regardless of whether package:loess or
package:lattice comes first in the search list. If I
2003 Mar 10
2
Biplots
I want to plot biplots. I have seen the function biplot, but there are
some extra features I would like, that I do not know how to achieve.
1. My observations, and my variables, fall into groups. Is there a way to,
say, plot the observations in several different colours, according to
which group the observation falls into? Similarly with the variables? I am
used to the lattice idiom, in which one
2011 Jul 12
1
LOESS function Newton optimization
I have a question about running an optimization function on an existing LOESS
function defined in R. I have a very large dataset (1 million observations)
and have run a LOESS regression. Now, I want to run a Newton-Raphson
optimization to determine the point at which the slope change is the
greatest.
I am relatively new to R and have tried several permutations of the maxNR
and nlm functions with
2006 Jul 07
0
User Error (was LOESS (PR#9064))
Please do as we ask (repeatedly) and study the help page before posting.
'family' is a separate argument, not part of loess.control, as the help
page correctly documents. If you use
cars.lo2 <- loess(dist ~ speed, cars, family = "symmetric",
control = loess.control(surface = "direct", iterations = 20))
cars.lo2$pars$iterations
it prints *20*, as it is
2023 Mar 23
1
loess plotting problem
Dear Anupam Tyagi,
You didn't include your data, so it's not possible to see exactly what
happened, but I think that you misunderstand the object that loess()
returns. It returns a "loess" object with several components, including
the original data in x and y. So if pass the object to lines(), you'll
simply connect the points, and if x isn't sorted, the points
2023 Mar 23
1
loess plotting problem
Thanks, John.
However, loess.smooth() is producing a very different curve compared to the
one that results from applying predict() on a loess(). I am guessing they
are using different defaults. Correct?
On Thu, 23 Mar 2023 at 20:20, John Fox <jfox at mcmaster.ca> wrote:
> Dear Anupam Tyagi,
>
> You didn't include your data, so it's not possible to see exactly what
>
2012 Apr 03
2
How does predict.loess work?
Dear R community,
I am trying to understand how the predict function, specifically, the
predict.loess function works.
I understand that the loess function calculates regression parameters at
each data point in 'data'.
lo <- loess ( y~x, data)
p <- predict (lo, newdata)
I understand that the predict function predicts values for 'newdata'
according to the loess regression
2010 May 05
0
A question regarding the loess function
Hello,
I was hoping that someone familiar with the implementation details of the
loess algorithm might be able to help me resolve some difficulties I am
having. I am attempting to reproduce some of the functionality of the
loess() function in C++. My primary motivation is that I would like to
understand the algorithm in detail.
So far I have managed to create a working port in C++ for the
2011 Mar 05
0
loess function takes long to estimate
Hi,
I have 2 questions regarding using loess function in stats package.
1. I have about 1 million points. I did loess with alpha=0.5 and
degree=1 and 2 regressors. It has run for more than 5 hrs on 64bit
16CPU and 64GB server (with no other process running). I am wondering
if this is usual? And if there is anyway to make it run faster?
2. I noticed a difference in RAM consumption when specifying
2012 Mar 24
0
Loess CI
I am trying to (semi) calculate the confidence intervals for a loess smoother
(function: loess()), but have been thus far unsuccessful.
The CI for the loess predicted values, yhat, are apparently
yhat +- t*s * sqrt(w^2), where s is the residual sum of squares and w is the
weight function
Correct me of I'm wrong, but R uses the tricubic function (1-abs(z)^3)^3,
where z = (x-xi)/h, where h
2010 May 17
1
Loess fit
Hi,
I wonder why my attempt to extend an existing loess fit to a new data set is
producing error. I was trying the following:
dat = read.csv(choose.files())
x = dat[,2]; y = dat[,1]
x.sort = sort(x)
y.loess = loess(y~x, span=0.75)
# For testing the above fit with a new dataset:
test = read.csv(choose.files()) # test data
new_x = test [,1]; new_y = test[,2]
new_x.sort = sort(new_x)
predicted
2011 Feb 07
1
tri-cube and gaussian weights in loess
>From what I understand, loess in R uses the standard tri-cube function.
SAS/INSIGHT offers loess with Gaussian weights. Is there a function in R
that does the same?
Also, can anyone offer any references comparing properties between tri-cube
and Gaussian weights in LOESS?
Thanks. - Andr?
--
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2010 Oct 05
2
loess and NA
Hi everyone.
I'm trying to do a loess with missing value on independant variable.
doc = c(2.27904, 2.59536, 7.44696, NA, 6.24264, 4.58400, 5.79192, 5.39502,
7.41216, 4.09440, 4.22868, 4.24620, 5.43804, 1.95528);
distance = c(26.5,56.5, 90.3, 123.0, 147.5, 176.0, 215.7, 229.3, 252.0,
325.3, 362.0, 419.3, 454.6, 470.0);
myloess = loess(doc ~ distance, na.action = na.omit);
plot(distance,
2011 Mar 18
1
Difficulty with 'loess' function
Hi,
I am trying to create a loess smooth from hydrologic data. My goal is to
create a smooth line that describes discharge at a certain point in time. I
have done this using the 'lowess' function and had no problem, but I'm
having some difficulty with loess. I am inputting the date ('date') and
discharge ('q') values using the 'scan' function, then inputting