similar to: Markov chain simulation

Hello, I would like to write in a variable the following string : Hello "World" If I do cat("Hello ","\"World\""), I have the good result on the screen but it can not be affected to a variable. If I do the same thing with paste paste("Hello ","\"World\"") it does not work since \" seems to be not recognized. So what

Dear R developers, I had some problem when building package: for exemple when building the package e1071 available from CRAN, I get the following message error: * checking for file 'e1071/DESCRIPTION' ... OK * preparing 'e1071': * cleaning src * running cleanup * creating vignettes ... ERROR /usr/lib/R/bin/texi2dvi: pdflatex exited with bad status, quitting.

I am trying to use the function aggregate with the median function but I get the following error: Error in FUN(X[[1]], ...) : Argument "INDEX" When I replace median by mean, it works perfectly Can someone tell me where the problem comes from? Thx I am running R 2.0.0 on SunOS 5.9 -- Philippe Hup?? UMR 144 - Service Bioinformatique Institut Curie Laboratoire de Transfert (4??me

Hello, I have a MANOVA model and I want to test the following hypothesis: LBM = 0 where B is the parameter estimates. Is there any function to do this in R? Cheers, Philippe -- Philippe Hup? Institut Curie, CNRS UMR 144, INSERM U900 26 rue d'Ulm 75005 Paris - France Email : Philippe.Hupe at curie.fr T?l : +33 (0)1 56 24 69 91 Fax: +33 (0)1 56 24 69 11 website :

> Well, that is in all good texts on R, together with the > solution: drop=FALSE. See ?"[" for the on-line details. OK. Thank you a lot. Now patched cclust and clustIndex work fine for 1D case. BTW, why not to apply the "drop=F" to these functions? I guess other users need 1D case as well. kind regards, Valery A.Khamenya

Hello, my data is an ordered list of observations where each observation is either of condition "efficient" (coded as 1) or "non-efficient" (0) as e.g. No. Obs Condition 1 1.1 0 2 1.2 1 3 1.4 1 4 1.5 0 5 2.5 1 etc. My goal is to plot a single line with lty='o' but different symbols for either condition whenever condition is 1 or 0, i.e. on the x-axis the

Hi, I just installed Ubuntu 12.04.4. I installed R by following instructions from CRAN after modification into my /etc/apt/sources.list file sudo apt-get update sudo apt-get install r-base sudo apt-get install r-base-dev When I try to load library(gdata) ou library(gplots), I have error message : library(gdata) gdata: read.xls support for 'XLS' (Excel 97-2004) files

Hi, I would like to get from a plot the size of the symbols plotted. Imagine I have the following plot function : plot(1:2,1:2, pch=15, cex=4) I would like the get the values SIZE1 and SIZE2 so that if I plot the following rectangle : rect(1.5,1.5, 1.5+SIZE1, 1.5+SIZE2) then the size of this square is exactely the same as the one of the symbols that have been plotted. Thanks for any idea. --

Hi, I would like to plot a graph on the jpeg device for example and to write a table associated to this plot where I have the pixel coordonates of each plotted point so that I could include the jpeg image onto a html page and get all the information about each point when the mouse button is pressed. The indentify() can do it but on the window device... Thanks for any idea. Philippe --

I am running R 2.0.0, GOstats 1.1.1 and GO 1.7.0, and when I use the function GOHyperG, I have the following error: w1<-as.list(hgu95av2LOCUSID) w2<-unique(unlist(w1)) set.seed(123) myLL<-sample(w2,100) xx <- GOHyperG(myLL) Error in mget(x, env = GOTERM, ifnotfound = NA) : recursive default argument reference In fact first I tried this function with my locusId ' list (with

Hi, I need to computed the GSVD of two matrices. For doing so I used in my C code the lapack routine dggsvd. But when I source my file gsvd.R I have the following error: Error in eval.with.vis(expr, envir, enclos) : BLAS/LAPACK routine 'DGGSVD' gave error code -1 Is there a problem with the parameters passed through the gsvd.R script? Is there a problem within the C script?

Hi, I have the following error when building a package * creating vignettes ... ERROR Error: chunk 3 Error in pmatch(x, table, duplicates.ok) : argument is not of mode character Error in buildVignettes(dir = ".") : Error: chunk 3 Error in pmatch(x, table, duplicates.ok) : argument is not of mode character Execution halted I use R-2.0.1 under debian linux 2.6.9

Hi. I have a problem with the default behavior of seq(), which gives the argument "from" when the argument length.out = 1. This behavior is annoying when the number of value determine in length.out is not predictable. Would it be possible to add an argument that propose the median/mean, i.e. (from + to) / 2 when length.out = 1 ? Examples: > seq(from = 1, to = 11, length.out=1) #

Hi. I have a problem with the default behavior of sample(), which performs sample(1:x) when x is a single value. This behavior is well explained in ?sample. However, this behavior is annoying when the number of value is not predictable. Would it be possible to add an argument that desactivates this and perform the sampling on a single value ? Examples: > sample(10, size = 1, replace = FALSE)

Thanks for your answer. The rational behind my proposal is why taking "from" when length.out=1, more than "to" or "NA", or " integer(0) " ? This question seems basic. But is is not in certain situations, like when length.out = unpredictable positive integer. And I haven't found in ?seq() the particular behavior of this function when length.out = 1.

Dear developers, I have noticed difference in computation time for the data.frame function between R2.9.0 and R2.8.1. The older release is more efficient: typically, R2.9.0 spends three more time in the data.frame function. Therefore, when many calls of this kind is done inside a function, the additional time spent with R2.9.0 may be several minutes. Looking at the profiling results (see file

Millot, On Mon, Jun 15, 2015 at 9:19 AM, Hadley Wickham <h.wickham at gmail.com> wrote: > Regardless of the value of the other arguments, the first element in > the output of seq() is _always_ `from`. > Indeed, as Hadley says, the output of seq must always start with* from*. It is a sequence starting at *from* and ending wherever the other arguments cause it to end. A sequence

On 6/16/2015 1:32 PM, Peter Meissner wrote: > Am .06.2015, 14:55 Uhr, schrieb Millot Gael <Gael.Millot at curie.fr>: > >> Hi. >> >> I have a problem with the default behavior of sample(), which performs >> sample(1:x) when x is a single value. >> This behavior is well explained in ?sample. >> However, this behavior is annoying when the number of

Hello, My name is Maria, MBA student in Sanfransisco, USA. In my credit scoring class, I have hard time making "transition matrix", which explains probability especially in relation to "Markov chain model". It is regarding people's monthly credit payment behavior. Does R have function to caculate it? I am actually a novice in using 'R'. Please help me!!! Maria

Hi, I have a set of data like the following: [,1] [,2] [1,] 10 2 [2,] 7 0 [3,] 1 0 [4,] 1 0 [5,] 15 0 [6,] 17 4 [7,] 4 0 [8,] 19 8 [9,] 10 2 [10,] 19 5 I'd like to aggregate it in order to obtain the frequency (the number of occurences) for each couple of values (e.g.: (10,2) appears twice, (7,0) appears once). Something cool