similar to: Specifying search position for attached package

Hi, The following seems to be a bug introduced with version 1.8.0 (it worked without error on my installation of version 1.7.0): > test <- data.frame(time = I(c("2003-08-19:22:55:57"))) > test[["time"]] <- strptime(test[["time"]], format = "%Y-%m-%d:%H:%M:%S") Error in "[[<-.data.frame"(`*tmp*`, "time", value =

Let me first admit: I am experiencing this bug on a precompiled binary of R for windows, and I know these are not supported. I am not asking for support, but I thought the R developers would want to know about this. # Define: foo.page <- function(x) x # Then, foo.page("a") # actually invokes the pager (!) on object named "a" (if one is defined). # same thing happens

Hello, Could someone please tell me why the following doesn't work: I have a file C:\Program Files\R\rw1051\etc\Renviron.site, which contains the line: R_LIBS= "C:/Jim/LocalR-Libraries/FromCran"; "C:/Jim/LocalR-Libraries/Cantata" >From the documentation, I gather that I have put this file in the default location, but to be safe I also explicitly set the R_ENVIRON

Hello, Could someone please tell me what I am thinking about incorrectly: f <- function(y) { g <- function(x) x + y g } In the following, I get what I expect based on my understanding of lexical scoping: (f(1))(3) # 4 (f(2))(3) # 5 But now, fs <- lapply(c(1, 2), f) fs[[1]](3) # 5 (Why not 4 ?) fs[[2]](3) # 5 Checking the environments of these functions, I see that

Hello, Has anyone out there encountered a problem like this: xyplot(Plasma ~ Serum | Analyte, data = sp.df, aspect = 1, layout = c(1, 1, 200), scales = list(relation = "free") ) Gives the error: Error in pretty(x[is.finite(x)], ...) : x must be numeric On the other hand, this works (but I don't want the default of having everything on the same

How can I perform a Student-Newman-Keuls-Test for multiple comparision of means in R? (I did not manage to find any specific function in the libraries) Jörg Peter Baresel Technische Universität München Institut für Ackerbau und INformatik im Pflanzenbau D-85354 Freising Lange Point 51 [[alternative HTML version deleted]]

J'aimerais savoir si la fonction merge() est la seule disponible pour concatener des tableaux de donn?es? Est-ce normal que l'ex?cution soit lente?

Hi there, I want to generate a large amount of functions, say f=function(x,t) exp(-t[1]-t[2]*g_1(x)-t[3]*g_2(1+x)) where g_1(x) and g_2(x) are from a long list of moments, such as x, x^2, log(x), log(1+x) .. and so on. Any suggestions on how to do this efficiently? thanks a lot. x.w

Hi Listers, Surely, I just have a mental block and there is a more elegant way of creating a summary count (other than extracing it from ftable). I''d like to create a new data.frame containing counts of spell by loc ie have three columns showing spell,loc,count. Below the data.frame... Any help appreciated Thanks Herry spell loc 101 Parts 1 102 Overall 2 105 Parts 1 106

Dear sir, I would ask if there are in R some code to generate a random sample from a mvariate student distribution like that one wich generate the multivariate normal one i mean( rmvnorm(n, mu, sigma) Second question : if R can plot density 3Dcurve I don't mean de histogram but de hole density function(normal for example). I use a windows version of The R software Thank you in advance wiyh

ligges@statistik.uni-dortmund.de wrote: > > Was on R-help: > > Subject: Re: [R] .Renviron and Renviron.site (on Windows XP) > Date: Thu, 11 Sep 2002 > From: "James Rogers" <jrogers@cantatapharm.com> > > At least on the windows version of R the file > ...../etc/Renviron.site > won't be interpreted as mentioned in, e.g., ?.Renviron. >

Hello, I have Samba 2.2.3 running on a Solaris 7 server. I have many Windows 98 and a handful of Windows 2000 computers authenticating against it for logging in and filesharing. One of the users (Jeff) had his Windows 98 workstation replaced with a Windows 2000 workstation. I have other Windows 2000 computers and their users can log in fine, and they all have the same network settings for the

Hello to all, I'm a biologist trying to tackle a "fish" (Poisson Regression) which is just too big for my modest understanding of stats!!! Here goes... I want to find good literature or proper mathematical procedure to calculate a confidence interval for an inverse prediction of a Poisson regression using R. I'm currently trying to analyse a "dose-response"

Moi! I was helping to teach a course on mixed models this week, and we came across a problem with coding more than one random effect in lme when they aren't nested. As an example, suppose we have an experiment where we sample moths from several populations, and place the moths on different trees, and measure a trait (in this case survival of offspring, but that's less important). We

Hello, In the Unix environment, I open a window by x11(). May I specify the position of this window by specifying the position of the top left of the window as in Windows environment? Or some other parameters can be used to do that? Thank you, Shengzhe

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Any doubts about R's big-league status should be put to rest, now that we have a Sudoku Puzzle Solver. Take that, SAS! See package "sudoku" on CRAN. The package could really use a puzzle generator -- contributors are welcome! -- David Brahm (brahm at alum.mit.edu) [[alternative HTML version deleted]] _______________________________________________ R-packages mailing list

Any doubts about R's big-league status should be put to rest, now that we have a Sudoku Puzzle Solver. Take that, SAS! See package "sudoku" on CRAN. The package could really use a puzzle generator -- contributors are welcome! -- David Brahm (brahm at alum.mit.edu) [[alternative HTML version deleted]] _______________________________________________ R-packages mailing list

I'd like to play with ARIMA models of stock prices, but I am a complete novice. Could some kind soul explain the relationship among packages "ts", "tseries", "dse", "dse2", and "fracdiff"? Are they 'competing' products or does one depend on another? Where would be the best place for a novice to begin? Thanks for any advice. PS. I

as.character.factor contains this line (where cx=levels(x)[x]): if ("NA" %in% levels(x)) cx[is.na(x)] <- "<NA>" Is it possible that this is no longer the desired behavior? These two results don't seem very consistent: > as.character(as.factor(c("AB", "CD", NA))) [1] "AB" "CD" NA > is.na(.Last.value)[3] [1] TRUE