similar to: APC Modelling and the GLM function

Displaying 20 results from an estimated 5000 matches similar to: "APC Modelling and the GLM function"

2003 Jul 21
1
Analysis of Complex Survey Data
Hi all I would like to perform a logistic regression analysis on some complex survey data with R, but am not sure if there are functions within R that will enable me to do so. Also, are there any extensions of the "cor" function that would enable me to incorporate survey weights when calculating correlation coefficients for bivariate data. Any help on this matter will be greatly
2010 Jun 10
1
glm poisson function
Hi, I'm totally new to R so I apologise for the basic request. I am looking at the incidence of a disease over two time periods 1990-1995 and 2003-2008. I have counts for each year, subdivided into three disease categories and by males/females. I understand that I need to analyse the data using poisson regression and have managed to use the pois.daly function to get age-sex adjusted rates and
2006 Apr 17
7
help
Hi, I am trying to runn a age-period-cohort model, but here is what I am having problem with, hope you can help me! This is what I am trying to do: sumzero_a<-((A-min(A))/5+1) - mean((A-min(A))/5+1) where A is my age variable (numeric, the mid-point of a five-year age group), but I got the following error: Error in min(..., na.rm = na.rm) : invalid 'mode' of argument I am pretty
2009 May 27
2
Factor level with no cases shows up in a plot
Consider this data structure (df1) ... Group Year PctProf FullYr 1 Never RF 2004 87 88 2 Cohort 1 2004 83 84 3 Cohort 2 2004 84 86 4 Cohort 3 2004 87 87 5 Cohort 4 2004 73 74 6 Never RF 2005 85 86 7 Cohort 1 2005 81 82 8 Cohort 2 2005 81 81 9 Cohort 3 2005 78 79 10 Cohort 4 2005 72 74 11
2012 May 07
1
Can't find the error in a Binomial GLM I am doing, please help
Hi all, I can't find the error in the binomial GLM I have done. I want to use that because there are more than one explanatory variables (all categorical) and a binary response variable. This is how my data set looks like: > str(data) 'data.frame': 1004 obs. of 5 variables: $ site : int 0 0 0 0 0 0 0 0 0 0 ... $ sex : Factor w/ 2 levels "0","1": NA NA NA
2011 Aug 06
1
help with predict for cr model using rms package
Dear list, I'm currently trying to use the rms package to get predicted ordinal responses from a conditional ratio model. As you will see below, my model seems to fit well to the data, however, I'm having trouble getting predicted mean (or fitted) ordinal response values using the predict function. I have a feeling I'm missing something simple, however I haven't been able to
2012 Jun 04
1
Chi square value of anova(binomialglmnull, binomglmmod, test="Chisq")
Hi all, I have done a backward stepwise selection on a full binomial GLM where the response variable is gender. At the end of the selection I have found one model with only one explanatory variable (cohort, factor variable with 10 levels). I want to test the significance of the variable "cohort" that, I believe, is the same as the significance of this selected model: >
2007 Aug 02
1
Xyplot - adding model lines to plotted points
Hello, I have written code to plot an xyplot as follows: library(lattice) xyplot(len~ageJan1|as.factor(cohort),groups=sex,as.table=T,strip=strip.c ustom(bg='white',fg='white'),data=dat, xlab="Age (January 1st)",ylab="Length (cm)",main="Linear models for male and female cod, by cohort",type='p',
2008 Jun 16
1
回复: cch() and coxph() for case-cohort
I tried to compare if cch() and coxph() can generate same result for same case cohort data Use the standard data in cch(): nwtco Since in cch contains the cohort size=4028, while ccoh.data size =1154 after selection, but coxph does not contain info of cohort size=4028. The rough estimate between coxph() and cch() is same, but the lower and upper CI and P-value are a little different. Can we
2011 Jun 28
2
coxph() - unexpected result using Crawley's seedlings data (The R Book)
Hi, I ran the example on pp. 799-800 from Machael Crawley's "The R Book" using package survival v. 2.36-5, R 2.13.0 and RStudio 0.94.83. The model is a Cox's Proportional Hazards model. The result was quite different compared to the R Book. I have compared my code to the code in the book but can not find any differences in the function call. My results are attached as well as a
2008 Jun 12
1
cch function and time dependent covariates
----- begin included message In case cohort study, we can fit proportional hazard regression model to case-cohort data. In R, the function is cch() in Survival package Now I am working on case cohort analysis with time dependent covariates using cch() of "Survival" R package. I wonder if cch() provide this utility or not? The cch() manual does not say if time dependent covariate is
2012 May 04
2
Binomial GLM, chisq.test, or?
Hi, I have a data set with 999 observations, for each of them I have data on four variables: site, colony, gender (quite a few NA values), and cohort. This is how the data set looks like: > str(dispersal) 'data.frame': 999 obs. of 4 variables: $ site : Factor w/ 2 levels "1","2": 1 1 1 1 1 1 1 1 2 2 ... $ gender: Factor w/ 2 levels "0","1":
2010 Feb 12
1
using mle2 for multinomial model optimization
Hi there I'm trying to find the mle fo a multinomial model ->*L(N,h,S?x)*. There is only *N* I want to estimate, which is used in the number of successes for the last cell probability. These successes are given by: p^(N-x1-x2-...xi) All the other parameters (i.e. h and S) I know from somewhere else. Here is what I've tried to do so far for a imaginary data set:
2003 Dec 05
3
Odds ratios for categorical variable
Dear R-users: How does one calculate in R the odds ratios for a CATEGORICAL predictor variable that has 4 levels. I see r-help inquiries regarding odds ratios for what looked like a continuous predictor variable. I was wondering how to get the pairwise odds ratios for comparisons of levels of a categorical predictor variable. I can't seem to get the correct output using: >
2012 Oct 06
2
Expected number of events, Andersen-Gill model fit via coxph in package survival
Hello, I am interested in producing the expected number of events, in a recurring events setting. I am using the Andersen-Gill model, as fit by the function "coxph" in the package "survival." I need to produce expected numbers of events for a cohort, cumulatively, at several fixed times. My ultimate goal is: To fit an AG model to a reference sample, then use that fitted model
2004 Oct 11
3
split and rlm
Hello, I'm trying to do a little rlm of some data that looks like this: UNIT COHORT perdo adjodds 1010 96 0.39890 1.06894 1010 97 0.48113 1.57500 1010 98 0.36328 1.21498 1010 99 0.44391 1.38608 It works fine like this: rlm(perdo ~ COHORT, psi=psisquare) But the problem is that I have about 100 UNITs, and I want to do a
2013 Aug 23
1
A couple of questions regarding the survival:::cch function
Dear all, I have a couple of questions regarding the survival:::cch function. 1) I notice that Prentice and Self-Prentice functions are giving identical standard errors (not by chance but by programming design) while their estimates are different. My guess is they are both using the standard error form from Self and Prentice (1986). I see that standard errors for both methods are
2011 May 17
1
epi.2by2
This is a really simple question, I'm sure,but I can't make EpiR work! I keep getting the following: > epi.2by2(47, 263483, 282, 935028, method="cohort.time", conf.level=0.95) Error in epi.2by2(47, 263483, 282, 935028, method = "cohort.time", conf.level = 0.95) : unused argument(s) (935028) and I really don't know why!. Any ideas very very welcome thank
2007 Jul 30
1
help with ROC curve
Hi I'm new to stats and R, so can you please help me or guide me building ROC curve in an elaborate way with codes I loaded ROCR package, but I'm not sure how to use it. Requirement To build ROC curve using only PSA(variable) alone of the original cohort against the ROC of the Model of the original cohort. It would be really great if you could help me with this. Thanks
2009 Jun 20
1
Plotting Cumulative Hazard Functions with Strata
Hello: So i've fit a hazard function to a set of data using kmfit<-survfit(Surv(int, event)~factor(cohort)) this factor variable, "cohort" has four levels so naturally the strata variable has 4 values. I can use this data to estimate the hazard rate haz<-n.event/n.risk and calculate the cumulative hazard function by H<--log(haz) Now, I would like to plot this