similar to: optim

Dear all, I have two vectors and connect the points by line segments: x <- c(1990,1994,1995,1997) y <- c(30,40,80,20) plot(x,y,type="l") I want to get the values of y's on these lines at missing x's, i.e., at 1991,1992,1993,and 1996. Is there a simple way to do this? Best regards, Remigijus mailto:remigijus.lapinskas at maf.vu.lt

Hello R-help, My vector aa has some NA's: > aa_c(NA,1) > aa=="NA" [1] NA FALSE > aa==NA [1] NA NA How can I detect NA's? In other words, I would like my answer to be TRUE FALSE. Best regards, Remigijus mailto:remigijus.lapinskas at maf.vu.lt -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help

Dear All, There is an example for the priceIts function (the its package) which does not work for me as expected. > ?priceIts > x1 <- priceIts(instrument = c("^ftse"), start = "1998-01-01", + quote = "Close") Error in validObject(.Object) : invalid class "its" object: Missing values in dates > x2 <-

Hi everybody, I am currently working on mixtures of two densities ( f(xi,teta)= (1-teta)*f1(xi) + teta*f2(xi) ), particularly on the behavior of the variance for teta=0 (so sample only comes from the first distribution). To determine the maximum likelihood estimator I use the Newton-Rapdon Iteration. But when computing the first derivative I get a none linear function (with several asymptotes)

Dear List, There has just been this question (as well as the answer to it) in the S list: > I would like to put some text in plots... but in french. How can I > write accented letters? > I suppose that there is a possibility similar as the one which > works in LaTeX, isn't it? What about R (for Windows and in East European languages)? Specifically, how can I give a title like

Dear all, I got this error message > library(dprep) > mardia(Savg) Error in cov(data) : 'x' is empty But with the same data, I got > library(mvnormtest) > mshapiro.test(Savg) Shapiro-Wilk normality test data: Z W = 0.9411, p-value = 0.6739 What does the error message "Error in cov(data) : 'x' is empty" mean? Thanks a lot! Jiao

The last two times I have originated message threads on R or Bioconductor I have received the message included below from someone named Patrick Connolly. Both times I was the originator of the message thread and used what I thought was a unique subject line that explained as best I could what my question was. Patrick seems to be implying that I am abusing the R and BioC help newsgroups in this

People, I'm researching some Bayesian statistic topics and in the midle of my study i found a very simple problem and i'm trying to find a simple package to solve this type of equations: Lets say that i need to compute beta values for the beta distribution and i now for example: E(teta)=a/(a+b) = 0,5 Var(teta)=ab/((a+b)^2(a+b+1))=0.05 So if i want to solve this to non-linear system to

Is it possible to fit a lagged regression, "y[t]=b0+b1*x[t-1]+e", using the function "lag"? If so, how? If not, of what use is the function "lag"? I get the same answer from y~x as y~lag(x), whether using lm or arima. I found it using y~c(NA, x[-length(x)])). Consider the following: > set.seed(1) > x <- rep(c(rep(0, 4), 9), len=9) > y <-

Hi all, I'm trying to implement a floating-point 'min' and 'max' operation using select. For 'min' I get the expected x86 assembly minss instruction, but for 'max' I get a branch instead of maxss. The corresponding C syntax code looks like this: float z = (x > y) ? x : y; Any clues? Could someone maybe explain to me the basics of

Dear All, R 1.9.1, Windows When copying and pasting a few lines from the 'predict.Arima' help, I get an error message: > data(lh) > predict(arima(lh, order = c(3,0,0)), n.ahead = 12) Error in eval(expr, envir, enclos) : Object "xreg" not found On the other hand, the following is OK: > data(lh) > predict(arima0(lh, order = c(3,0,0)), n.ahead = 12) $pred Time

Most mornings, I have over a screenful of messages mostly from R-help and it's very useful to have them threaded. However, the usefulness of threading is lost when posters reply to a message and then change the subject instead of creating a new message. People who don't have a mail client that can display email in threads are probably unaware that this sort of thing can happen in ones

Dear Contributors I would like to perform this operation using a loop, instead of repeating the same operation many times. The numbers from 1 to 4 related to different groups that are in the database and for which I have the same data. x<-c(1,3,7) datiP1 <- datiP[datiP$city ==1,x]; datiP2 <- datiP[datiP$city ==2,x]; datiP3 <- datiP[datiP$city ==3,x] datiP4 <-

>From the <samba>/var/log/<client>.log file: doing parameter domain controller = AZPHXNT01 Unknown parameter encountered: "domain controller" Ignoring unknown parameter "domain controller" >From the smb.conf file: # Domain Master specifies Samba to be the Domain Master Browser. This # allows Samba to collate browse lists between subnets. Don't use

All, I am using a sum of squared differences in the objective function of an optimization problem I am doing and I have managed to speed it up using the outer function versus the nested for loops, but my suspicion is that the calculation could be done even quicker. Please see the code below for a simple example. If anyone can point out a faster way I would appreciate it greatly. Thanks, Roger

Hi, guys, I need to simulate Pareto distribution. But I found 'rpareto' didn't exist in R. And it seems that Pareto distribution don't have mathematical relationships with other distributions. What can I do? Thanks a lot. Ni --------------------------------- [[alternative HTML version deleted]]

Hi, my name is Guilherme and I'm trying to solve an optimization problem in R, regarding reliability and survival time of equipments. I Have to write the function in the image attached to this email, please take a look, where the f(t) is weibull's distribution density function, Ca=1000 and Cb=100 are costs of two equipments and i'm using shape=2.5 and scale=20. However, a few problems

Hi, I am having some trouble trying to plot a histogram in more than one colour. What I want to do is, plot two vectors in the same histogram, but with different colours, for instance: > x <- rnorm(1000,20,4); > y <- rnorm(1000,10,2); Then I'd like to have x and y ploted on the same hist (I can do that already doing w <- c(x,y) then hist(w)) but the bars

Hello asterisk users! Does asterisk (or any of its plugin) support MRCP to interface with 3rd party professional TTS engine? I've found very little information about this, for example: http://www.zen-turkey.com/blog/default.aspx?id=12&t=Asterisk-MRCP-Integr ation Thanks in advance! Regards, Claudio Internet Email Confidentiality Footer

Hi all, I am new to the mailing list , and i need your help. i want to compress audio raw data (PCM) after i have captured them in (sensor) and get them as 16-bit integr samples. that is, when i capture voice for,say, 1 second, i get an array of 8 kilo sample, and I NEED TO COMPRESS THIS SO THAT I GET A SMALLER SIZE BEFORE I TRANSMIT THEM WIRELESSLY. Does Speex allow me to such compression ? Any