similar to: expanding out date and time

Dear R-users! I am using R 1.7.0, under Windows XP. Having some hospital discharge data (admission date and discharge date for each patient), I want to get the number of patients in the hospital on a given date. My data look like (simple example): > x <- data.frame(patid=c("pat1", "pat2"), adm.date = c("15.03.2002", "16.03.2002"),

My data contains a variable "observation_date" and it contains values as: 1985-09-02 1985-09-15 1985-07-31 1985-09-02 I need to process data annually rather than daily, therefore I'm trying to 1) either extract the first 4 digits from this field and use them as a new variable "year" or 2) keep the variable as it is and process the analysis using the first 4 digits of

Hello all! Please forgive me if I am asking stupid questions, I am new to implementing VoIP as PBX. I am currently employed at a Tifton, GA-based peanut shelling facility and I am looking for a VoIP system to tie our 2 locations together. The plant and the main office were originally separate, so each has their own (different) phone system. Each side has 4 incoming analog lines and about a dozen

Dear all, Suppose I have a date variable: c = "99/05/12" I want to extract the parts of this date like month number, year and day. I can do it in SPSS. Is it possible to do this in R as well? Rgd, --------------------------------- Here’s a new way to find what you're looking for - Yahoo! Answers [[alternative HTML version deleted]]

How does one convert to a date format when survey respondents have used two different date formats whilst entering their data. There were clearly told to use mm/dd/yyyy but humans being humans some entered mm/dd/yy. There was even validity checks on the forms but I allowed them to be overridden since the data is more holy than the format. The data was downloaded as a csv and read.csv was used to

Greetings, I have written a patch for rsync-2.6.1pre-2 which adds a --time-limit=T option. When this option is used rsync will stop after T minutes and exit. I think this option is useful when rsyncing a large amount of data during the night (non-busy hours), and then stopping when it is time for people to start using the network, during the day (busy hours). If this patch is accepted it may

hi, this is a very basic question -- sorry for posing it: how can i force R to print 0.0001 instead of 1e-04??? .--------------------. | > 0.0001 | | [1] 1e-04 | `--------------------' i tried the functions format, formatC, ... and changed options()$digits with no success! thanks for advice, tomy -- no signature

Dear List, I am having a problem using gsub to remove dates from a date/time string. For example: x<-c("5/31/2009 12:34:00","6/1/2009 1:14:00") I would like to remove the date and have just the time. I have tried: gsub("[0-9+]/[0-9+]/[0-9+]","",x) and various versions. I think my problem is that the / is a special character and is telling it

I have and XTS time series object that has date and time. I started with 1 minute data and used apply.daily(x, sum) to sum the data to one cumulative value. This function works just fine however it leaves a time for the last summed value which looks like this 2006-07-19 14:58:00. I need to just have the date and to remove the time value of 14:58:00 just leaving the date value of 2006-07-19 .

Hello! I've time stamp ('time') field in dataset ('dt') with values like "18:10", "19:43", .... I need to split time field into hour and minutes and add both as new columns to dataset. We are able to do it in bash+awk, but curious to stay within R codebase as much as possible. For now we are using such solution: tstamp <- strsplit(dt$time,

Dear R Users, given that: > AggDateTime[960:962] [1] "2011-08-25 23:59:00 BST" "2011-08-26 00:00:00 BST" [3] "2011-08-26 00:01:00 BST" > unlist(strsplit(as.character(AggDateTime[960])," ", fixed=TRUE)) [1] "2011-08-25" "23:59:00" > unlist(strsplit(as.character(AggDateTime[962])," ", fixed=TRUE)) [1]

Hola a todos: Tengo un problema con las fechas, básicamente necesito una diferencia en días y siempre se sale en segundos. Salvo un ejemplo copiado de un libro, pero yo necesito procesar los datos propios. Les paso el código en R (copiar y pegar, son solo dos días que se comparan) y al final como me salen los resultados porque es medio complicada mi redacción. ¿Alguna idea? fechas1

Ei-ji Nakama has pointed out (from another Japanese user, I believe) that postscript() and pdf() have not been handling kerning correctly, and this is a request for opinions about how we should correct it. Kerning is the adjustment of the spacing between letters from their natural width, so that for example 'Yo' is usually typeset with the o closer to the Y than 'Yl' would be.

I know R has a steep learning curve, but from where I stand the slope looks like a sheer cliff. I'm pawing through the available docs and have come across examples which come close to what I want but are proving difficult for me to modify for my use. Calculating simple group means is fairly straight forward: data(PlantGrowth) attach(PlantGrowth) stack(mean(unstack(PlantGrowth)))

Dear R-users, actually i try to parse some state protocols for my work. i an easy stetting the code below works fine, if states are reached only once. in harder settings it could be possible that one state gets visited more times. in this case for me its interesting to see how much waiting time lies between to states on the whole. by the way i didn't use R as a parsing tool so far, so

hi everybody, i try to extract a part of name to a date : like : "VGT1_VGT2_CONTR_B020030401.H0V0.MIR" to "20030401" but the beginning of the files changes i have a list of files: [,1] [1,] "VGT1_CONTR_B020020301.H0V0.MIR" [2,] "VGT1_VGT2_CONTR_B020020611.H0V0.MIR" [3,]

Hi All, Is there a means to extract the "10" from "23:10:34" in one pass using strsplit (or something else)? tst <- "23:10:34" For example my attempt strsplit(as.character(tst),"^[0-9]*:") gives [[1]] [1] "" "" "34" Obviously it is matching the first two instances of [0-9]. Note that there may be only one digit

Hi R experts, For example I have a dataset looks like this: Number TimeStamp Value 1 1/1/2013 0:00 1 2 1/1/2013 0:01 2 3 1/1/2013 0:03 3 How can I split the "TimeStamp" Column into two and return a new table like this: Number Date Time Value 1 1/1/2013 0:00 1 2 1/1/2013 0:01 2 3 1/1/2013 0:03 3 Thank! [[alternative HTML version

Daniel, en vez de mean utilicé table. Entonces me genera una lista y quiero que quede una matriz. Unlist no me sirve porque me pasa todos los valores a un vector y me pierdo de saber a que caso corresponde. Saludos, Sebastián. El 26 de septiembre de 2013 16:50, daniel <daniel319@gmail.com> escribió: > Sebastián, tengo dificultades para entender si sigues con el ejemplo > anterior

Hi. I am having trouble thinking of an easy way to grab rows out of a data frame. I want to select the rows with a median value when the rows are similar. A simple example is this table, which I could read into a data frame. I would like to find a new data frame with only the rows with a median value for the "c" column given a certain "a" value. For example, the c values