similar to: How to change the label position in axis() ?

Hello I've created a function to make a plot with multiple pannels from columns of data that are created in a previous function. In the example below the number of columns is 8, giving 4 pannels, but in general it takes data with any number of columns and figures out a nice layout. The panels all have the same axes, and so I wonder what functions are avialable to create axes only on the

Dear List, Several times I use this package I get the error message shown below. When I work out simple examples, it turns out to be fine, but when working with real and moderate size data sets I always get the same error. Do you know what could be the cause of the problem? Error in apply(mod.matrix[, components], 1, prod) : subscript out of bounds Error in

Hi all, how do I change the magnification of xaxis annotation? I need a smaller axis text size in some of my plots. I tried cex.axix=0.5 in plot(), but this doesn't work. Thanks, Sven -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or

Dear all, I would like to draw a dendrogram and mark some parts/branches (by using "segments") including their labels. If I draw it without specifying the length of x axix, I am able to do that (as in My dendrogram 1 of the following codes). However, if I want to specify the x axix, I am not able to draw marking line (by using "segments") including labels (as in My dendrogram

I have the following list of observations of calendar time: [1] 03-Nov-1997 09-Oct-1991 27-Aug-1992 01-Jul-1994 19-Jan-1990 12-Nov-1993 [7] 08-Oct-1993 10-Nov-1982 08-Dec-1986 23-Dec-1987 02-Aug-1995 20-Oct-1998 [13] 29-Apr-1991 16-Mar-1994 20-May-1991 28-Dec-1987 14-Jul-1999 27-Nov-1998 [19] 09-Sep-1999 26-Aug-1999 20-Jun-1997 05-May-1995 26-Mar-1998 15-Aug-1994 [25] 24-Jun-1996 02-Oct-1996

Dear R helpers Suppose I am plotting a simple scatter plot where no of paired observations (x,y) are say 100. month          length 1                   10 2                   12 3                   17 4                   21 5                   13 .......................... .......................... .......................... 100              16 when i run the command plot(month, length)

I have a sample of observations: > yy [1] 0.00000000 2.39722222 4.35000000 -4.19722222 0.63611111 [6] 1.08055556 5.90555556 -1.87222222 2.13333333 -1.18055556 [11] 3.61666667 0.87777778 8.33888889 3.84166667 1.11111111 [16] -3.76111111 -11.67777778 -2.03055556 6.94444444 -11.76666667 [21] 4.81111111 -7.25833333 1.42222222 5.37222222 4.68055556

In the function boxplot: Is it possible to have the numbers on the vertical axix written horizontally (so that tilting of the head is unneccessary)? [[alternative HTML version deleted]]

I am generating an array of similar plots using the par(mfrow=c(3,3)) method. Everything works fine except the plot only puts y-axis tick marks on cells in column one and x-axis tick marks on cells in row three. I would like tick marks on both the x and y axix of all 9 plots in my array. I am generating plots using the following two functions three.by.three.plot <- function(ss) {

Hi, I was trying to make a density plot with 13 samples. To distinguish each sample, it would be good if each color is as different as possible from the other colors. I could use the built in function, but that does not do more than 8 colors and then goes back to recycling the cols. If I use a palette, then it is really difficult to distinguish between the colors. So, is there a way that I can

Just as as.vector() takes a vector, matrix or array and returns a vector in row-major order, I'd like to write a function to take such an object and return the dimension names, pasted with some separator, as a similar vector. Here is something ugly cobbled together to demonstrate what I want: a function to work for any number of dimensions. vecnames <- function(x, sep=':') {

(Embedded image moved Geert Jansen <g_jansen@geert.co.uk> to file: 06/06/2002 01:55 PM pic04528.pcx) (Embedded image moved Geert Jansen

(Embedded image moved Geert Jansen <g_jansen@geert.co.uk> to file: 06/06/2002 01:55 PM pic18844.pcx) (Embedded image moved "Geert Jansen"

Hello, I am trying to run a PCA in R and I cannot get the PC scores for each of the values. Using pcX <- princomp(X) then loadings(pcX) I can get a listing of the eigenvectors but not the actual PC scores for each value in the dataset. I greatly appreciate any help anyone can offer Thanks Ken

(Embedded image moved to file: pic10389.pcx) NVC for Domino Virus Warning This is an automatically generated message. A possible virus, 'Yaha.E@mm', was detected in attachment 'Neu_Textdokument.zip_.scr' in document '[Samba] Neu Textdokument'. Database: 'KAWILK01 Mailbox'. Document was apparently created on '26.01.2003 17:45:16' by

Hi, I am trying to run a conditional logistic model on a nested case-control study using cph() and then estimate survival based on the model. The data came from Prof Bryan Langholz website where he also has the SAS code to this, so I am trying to replicate the SAS results. The data attached. Basically, the variables are: rstime: risk set age rsentry: fake entry time, just before rstime setno:

(Embedded image moved "Geert Jansen" <g_jansen@geert.co.uk> to file: 06/06/2002 01:55 PM pic20654.pcx) People be carefull, the people behind this

I am reading some documentation about Cross Spectrum Analysis as a technique to compare spectra. My understanding is that it estimates the correlation strength between quasi-periodic structures embedded in two signals. I believe it may be useful for my signals analysis. I was referred to the R functions that implement this type of analysis. I tried all the examples which generated a series of

Hi, Im new to R so this question is quite fundamental. Im trying to compare some autocorrelations generated by the acf function to some theoretical correlations. How can I have acces to just the autocorrelations, for computation? This is some of my code: > acf.data<-c(acf(x)) > acf.data This is the R output: $acf , , 1 [,1] [1,] 1.000000000 [2,]

I've experienced something like this, as well. Though I don't know if this will help, I would make sure that your NT username(s) are appropriately mapped to unix users. You may not be able to view the properties because the permissions/mapped user are mixed up. You can check this by doing a smbstatus - the user names listed as connected are the unix usernames that have been mapped to.