similar to: Extracting means for given strata from dissimilarity object

I'm trying to plot four different sorghum types on a plot using a different colour/symbol combination for each sorghum type (TYPBOTA in the script below). What am I doing wrong?: plot(xx$LATITUDE,xx$SFD1, points(xx$SFD1,xx$LATITUDE, col=1:4[codes(xx$TYPBOTA)],pch=c(4,3,1,2)[codes(xx$TYPBOTA)]) grid() I get the following error message Error in 1:4[codes(xx$TYPBOTA)] : NA/NaN argument

I'm trying to plot observations against observation dates and getting julian dates along the x-axis: library(date) Week<-as.date(c("05/02/03","05/09/03","05/16/03","05/23/03","05/30/03","06/0 7/03","06/14/03")) Leafminers<-c(0,2,5,10,4,6,5) Diglyphus<-c(0,0,4,5,7,3,1) LeafDig<-cbind(Week,Leafminers,Diglyphus)

Is there a way of removing all rows with missing values from a data frame? I usually use subset(x, var1!="NA") and repeat for each variable. It would be nice to be able to do it in one fell swoop. Also, surprisingly, it doesn't always work. Sometimes I'm left with an empty set even though not all rows have missing values for the variable. Cheers, mikkel Mikkel Grum,

Can anyone tell me what's wrong with this command?? xx<-subset(x,LOCAL.NAME==c("Chifumbata","Chikota"),select=c(13,16,19,23,26,2 9,30,33:48)) Warning message: longer object length is not a multiple of shorter object length in: LOCAL.NAME == c("Chifumbata", "Chikota") both of the following commands work fine

I have two problems where I've come up with some code that will do the analysis that I want, but it looks pretty clumsy. In the first case, I calculate the variance on five different columns for each of 14 clusters and get them into one matrix. I get the job done, but I would have thought that it could be done in one or two lines, not six, and be generalized so that it didn't matter how

First question: I have an Excel file with both character and numeric variables that I want to import to a data.frame, so I've saved the data to a tab-delimited text file. read.table : * Won't identify the mode of my character variables, as some of them contain only numbers and none of them are surrounded by quotes, * Won't allow me to specify the mode of my variables, * Doesn't

This message is in MIME format. Since your mail reader does not understand this format, some or all of this message may not be legible. ------_=_NextPart_000_01C35A53.75780090 Content-Type: text/plain; charset="iso-8859-1" Anyone have a clue why hclust() and agnes() produce different results in the example below when both use method="average"?? I'm not able to reproduce

Any idea why clusters five and six fall off the scale in the following? library(cluster) library(maptree) data(flower) dfl2<-daisy(flower,type=list(asymm=c(1,3),ordratio=7)) hdfl2<-hclust(dfl2) prune.dfl2<-prune.clust(hdfl2,k=6) plot(prune.dfl2) Of course the following will display all six clusters, but without a scale: draw.tree(prune.dfl2) Best wishes, Mikkel Mikkel Grum

Is there any function in R like is.not.found(x, y) meaning if you can't find object x, then use object y?? Mikkel Grum

Hi Can anyone explain why a date becomes numeric when you loop over a series of dates? > dt <- Sys.Date() > dt [1] "2017-11-14" > class(dt) [1] "Date" > dts <- dt - 1:0 > class(dts) [1] "Date" > > for (i in dts) { + print(i) + print(class(i)) + print(as.Date(i, "1970-01-01")) + print(class(as.Date(i,

I want to do something like df[df$b %in% df2[i, 2], ] where df$b is a numeric vector and df2[i, 2] is a factor with levels like "7:9, 12:14". For example: a <- c(paste("A", 1:10, sep = ""), paste("B", 1:10, sep = "")) b <- 1:20 df <- as.data.frame(cbind(a, b)) df$b <- as.numeric(levels(df$b))[as.integer(df$b)] f <-

What am I doing wrong, or is the \r that I'm getting in the example below a bug? > a <- (1:10) > b <- (LETTERS[1:10]) > df <- as.data.frame(cbind(a, b)) > > df a b 1 1 A 2 2 B 3 3 C 4 4 D 5 5 E 6 6 F 7 7 G 8 8 H 9 9 I 10 10 J > library(RSQLite) > drv <- dbDriver("SQLite") > con <- dbConnect(drv, dbname = "Test")

What am I doing wrong, or is the \r that I'm getting in the example below a bug? > a <- (1:10) > b <- (LETTERS[1:10]) > df <- as.data.frame(cbind(a, b)) > > df a b 1 1 A 2 2 B 3 3 C 4 4 D 5 5 E 6 6 F 7 7 G 8 8 H 9 9 I 10 10 J > library(RSQLite) > drv <- dbDriver("SQLite") > con <- dbConnect(drv, dbname = "Test")

When I use the function cutree(), the numbers of the clusters are not in the same order as the plotted dendrogram. Is there any way of sorting them so that they match the tree? Is it possible to plot a dendrogram horizontally, preferably with the branches to the right? This would enable some practical composite plots, e.g. labels that were an entire table with several columns of information, or

I run a batch file with the following command in Windows XP: C:\R\R-2.12.1\bin\Rterm.exe --no-save --no-restore <C:\users\me\file.R> C:\users\me\file.out 2>&1 Is there any way to get only the output of R in file.out, without getting all the code from file.R too? Any help greatly appreciated, Mikkel

I have a situation where I'm filling out a dataframe from a database. Sometimes the database query doesn't get anything, so I end up trying to place NULL in the dataframe like below. > temp <- NULL > xmat <- as.data.frame(matrix(NA, 2, 3)) > xmat[1, 2:3] <- temp Error in if (m < n * p && (n * p)%%m) stop(gettextf("replacement has %d items, need %d",

Dear useRs, I'm writing regular survey reports using Sweave. Each report has several sections along the lines of: \section*{Disease X} <<MapX,fig=TRUE,echo=FALSE>>= image(vectorx,vectory,matrixz) @ Notes with or without Sexpr{a}. \vfill \pagebreak \section*{Disease Y} <<MapY,fig=TRUE,echo=FALSE>>= ...etc. Often one or more of the diseases is not observed (all

Is the following expected behaviour for a date used in an ifelse function? > date <- Sys.Date() > date [1] "2007-12-30" > ifelse(TRUE, date-1, date) [1] 13876 > ifelse(FALSE, date-1, date) [1] 13877 > ifelse(TRUE, as.character(date-1), date) [1] "2007-12-29" > if (TRUE) {date} [1] "2007-12-30" It would seem more natural to me if a date produced

How do I get output with "\color{blue}", i.e. with only one backslash??? > "\color{blue}" [1] "color{blue}" Warning messages: 1: '\c' is an unrecognized escape in a character string 2: unrecognized escape removed from "\color{blue}" > "\\color{blue}" [1] "\\color{blue}" > Any help greatly appreciated. Best regards,

Apparently any (?) call of the form cut(date,"weeks") where the date *begins the week*, gives the error Error in 1:(1 + max(which(breaks < maxx))) : result would be too long a vector In addition: Warning message: In max(which(breaks < maxx)) : no non-missing arguments to max; returning -Inf To my surprise, this was first reported as a problem in 2006 (!) (version 2.3.1