similar to: On nlm

oops!, I pressed the 'send' key too soon, ... see ?replace replace(x, is.na(x), median(x, na.rm=T)) take also a look at the function itself > replace function (x, list, values) { x[list] <- values x } <environment: namespace:base> Stefano >-----Messaggio originale----- >Da: r-help-bounces at stat.math.ethz.ch >[mailto:r-help-bounces at

Hello, usually work with S-plus and/or with R, which I do prefer, on a Window paltform. Now I downloaded R for the Mac (I run it on a G4 at home) but I found that many, too many functions are not available (svd, lm, glm and so on... but still the lapply is missing...!). I have ProFortran a C++ routine of my own but I can't pass them to that version of R. Is there anybody going to give a little

Buenas para tod en s, tengo una consulta para poder optimizar tiempos. Ejemplo tengo el siguiente dataframe: distrito<-c("A","A","A","B","B","B","C","C","C","A","A","B","B","C")

Encontré mi error, ahora funciona perfecto, Animal <- c('A','A','A','B','B','C','D','D') Edad <- c(2,3,4,3,4,2,4,5) datos <- data.frame(Animal, Edad) m_m <- with(datos, tapply(Edad, Animal, function(x){ minimo <- min(x) valor <- length(x) rep(minimo, valor) })) datos$repetido <- do.call(c, m_m) datos

Hi, I'm trying to install xen+Debian Etch on a Geode LX system. Xen boots fine, but although the package "libc6-xen" is installed I have a large number of such errors: 4gb seg fixup, process syslogd (pid 1878), cs:ip 73:b7f24610 All processes triggers it, and from what I've found on the web it's a sign that libc6-xen is not recognized. Indeed:

It would be really nice if nlm took a set of "..." optional arguments that were passed through to the objective function. This level of hacking is probably slightly beyond me: is there a reason it would be technically difficult/inefficient? (I have a vague memory that it used to work this way either in S-PLUS or in some previous version of R, but I could easily be wrong.) Here's

Buenas, Estoy intentando caracterizar una curva de 180 puntos y sacar su vector de caracteristica: Punto de inicio, Máximo Minimo .... Para ello tengo un dataframe con las distintas curvas, de la forma siguiente: segundos valor curva 1 170 1 2 175 1 ...................................... 180 125 1 1

Hello! I''d like to gather some points about running a rails application on a PDA. As a condition I''d like to use Palm and Windows Mobile based PDA to target a huge user audience (this could be become difficult I know, only Windows Mobile for the start is although okay). I googled the last weeks and found out that there were only a few web browsers out there. E.g. Mozilla

Boa tarde, Ap?s alguma experi?ncia com o Asterisk, e com muito ainda para aprender, gostaria de saber se h? algu?m nesta mailing list que pretenda criar um Asterisk Users Group para Portugal. Visto que acaba sempre por ser uma enorme aprendizagem ( valor acrescentado) a partilha de experi?ncias/problemas e solu??es nas implementa??es Asterisk. H? spre detalhes que variam entre os Telco's de

Hola, Carlos. Primero, muchas gracias por el código. No es exactamente lo que quería, porque la parte "Detección de presencia de "cual_1" y "cual_2"... no excluye aquellas combinaciones en las que está presente también el objeto c, pero me ha servido de base e inspiración para elaborar otro código. He copiado la primera parte de tu función, para crear todas las

Hello, The following piece of code works fine in R.2.10 (ubuntu): switch(distr,         normal    = {if (is.infinite(param["desv"]))                      n <- c(n,"La desv. estándar no puede ser Inf.")                    if (param["desv"]<0)                      n <- c(n,"La desv. estándar no puede ser <0.")                    },        

Dear R community: it is possible to replace NA?s in a data frame with zeroes? what should I do? Thanks in advance Juan Pablo _________________________________________________________________ MSN Photos es la manera m?s sencilla de compartir e imprimir sus fotos: http://photos.latam.msn.com/Support/WorldWide.aspx -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-

Without trying to understand your code in detail let me just assume you are trying to create a matrix, ret, whose i,j-th entry is some function, f, of row i of X and row j of X. In that case this should do it: apply(X,1,function(x)apply(X,1,function(y)f(x,y))) Date: Wed, 30 Jun 2004 15:28:47 -0300 (ART) From: <daniel at sintesys.com.ar> To: <r-help at stat.math.ethz.ch>

Hi everyone. I have a problem that I have been unable to determine either the best way to proceed and why the methods I'm trying to use sometimes fail. I'm using the pf() function in an optimization function to find a noncentrality parameter that leads to a specific value at a specified quantile. My goal is to have a general function that returns the noncentrality parameter that

I've been working on a new package and I have a few questions regarding the behaviour of the nlm function. I've been (for better or worse) using the nlm function to fit a linear model without suppling the hessian or gradient attributes in the objective function. I'm curious as to why the nlm requires 31 iterations (for the linear model), and then it doesn't work when I try to add

En el correo anterior se me olvidó mencionar que trabajo con Rstudio El 28 de mayo de 2015, 15:18, MªLuz Morales <mlzmrls en gmail.com> escribió: > Hola, > soy nueva en esta lista y también en R. Yo he realizado un script en R > que carga dos archivos csv, uno de ellos con casi 2 millones de filas. El > programa carga esos archivos a data frame, y se trata simplemente de >

Is there a command as "mat.or.vec(nr,nc)" to create an array that I must calculate with more cicle? [[alternative HTML version deleted]]

Buenas, ¿Cómo calculariais el punto de inflexion de esta curva marcado en rojo? [X] He probado de la siguiente manera: 1- Haciendo la segunda derivada:No me sirve, porque m edetecta muchas veces esos casos 2- Mirando si el siguiente valor es mayor que el anterior. No me vale, ya que si hay ruido, no lo va a detectar. 3. Mirando que el punto siguiente crezca respecto al anterior. No me

In the course of revising a paper I have had occasion to attempt to maximize a rather complicated log likelihood using the function nlm(). This is at the demand of a referee who claims that this will work better than my proposed use of a home- grown implementation of the Levenberg-Marquardt algorithm. I have run into serious hiccups in attempting to apply nlm(). If I provide gradient and