similar to: Anova

Displaying 20 results from an estimated 400 matches similar to: "Anova"

2002 Oct 15
1
R memory
Hello I was doing PCA (principal component analysis) with a DNA expression matrix (7000 rows/38 columns; from golubEsets) but I had the following problem "Error:cannot allocate vector of size 397051 Kb In addition: Warning message: Reached total allocation of 119Mb: see help(memory.size)" I've already done some filtering (reduced to 3051 rows) but the problem remains, only the
2008 Feb 17
1
app_voicemail - Failed to open file ../tmp/xxxxx.WAV
Hi, Would anyone have a clue on this issue? I'm running asterisk 1.4.13. Trying to get a WAV voicemail file attachment sent to my email address. Voicemail is working fine. Email notification of a new message works fine. However, when I set up voicemail.conf to have an attachment of the file sent to email I get an error message like this on the console: [Feb 17 13:33:37]
2014 Nov 10
2
Webinar Gratuíto, Como evitar fraudes em telefonia
A SipPulse acaba de liberar o TFPS (www.tfps.co), solu??o para combate a fraudes de fomento de tr?fego internacional em telefonia. O sistema ? capaz de detectar 99.99% das tentaivas de fraude em tempo real. Durante o Webinar, abordaremos como proteger servidores Asterisk e Elastix/FreePBX de fraudes, medidas basicas como configura??o de firewall e remo??o de servi?os desnecess?rios e em seguida
2003 Jan 28
2
symbol
Dear R helpers I would like to make a plot where the symbols were the numbers of the corresponding classes, i.e, samples of class 1 would the symbol 1, samples of class 2 would have symbol 2,.... Is this possible? Thank you Luis -- Kit SAPO.ADSL.PT Apenas 50 ?. Adira j? em http://www.sapo.pt/kitadsl
2003 Feb 10
1
lda
Dear helpers There are some versions of lda. I would like to know which one is behind R's lda function. Luis -- Ofere?a a si uma prenda no Dia dos Namorados: SAPO.ADSL.PT, e receba ainda uma oferta especial para a sua cara-metade. Tudo s? por 50? http://adsl.sapo.pt/destaque_namorados.html
2003 Jan 25
1
plot/screen
Dear helpers I have this code to make 10 plots in the same device a<-1 split.screen(c(2:5)) for (i in 1:10){ nova.matriz<-a*sigma+(1-a)*S proj<-calculo.comp(treino,nova.matriz) print(proj[,1:2]) screen(i) plot(Re(proj[c(2,3,6,9:11,14,23),1:2]),xlim=range(c(- 15:15)),ylim=range(c(-5:5)),col="black") points(Re(proj[c(1,4:5,7:8,12:13,15:22,24:27),1:2]),col="red")
2004 Jul 01
1
Factors.
Hello, I'm new with R. I need some help; I have a matrix of data to wich i want to apply the function dudi.acm to perform multiple correspondence analysis. However to use it all variables must be factors, so how can i turn each column of the matrix into a factor? I've tried as.factor. It works isolated for each column, but when I form the matrix of all factors it doesnt work. Please
2013 Nov 14
3
How to use PVH mode in xen
Hi, I'm instresting with the PVH mode, is there any wiki available to boot up a PVH guest? I used the following source code to compile the xen and dom0. I have tried adding pvh=1 in xl.cfg file as pv mode, but guest still uses qemu device model. This patch series can also be pulled from this git tree: git://xenbits.xen.org/people/gdunlap/xen.git out/pvh-v15 The kernel code for PVH guests
2012 Oct 05
2
problem with convergence in mle2/optim function
Hello R Help, I am trying solve an MLE convergence problem: I would like to estimate four parameters, p1, p2, mu1, mu2, which relate to the probabilities, P1, P2, P3, of a multinomial (trinomial) distribution. I am using the mle2() function and feeding it a time series dataset composed of four columns: time point, number of successes in category 1, number of successes in category 2, and
2012 Sep 27
0
problems with mle2 convergence and with writing gradient function
Dear R help, I am trying solve an MLE convergence problem: I would like to estimate four parameters, p1, p2, mu1, mu2, which relate to the probabilities, P1, P2, P3, of a multinomial (trinomial) distribution. I am using the mle2() function and feeding it a time series dataset composed of four columns: time point, number of successes in category 1, number of successes in category 2, and
2012 Oct 11
2
model selection with spg and AIC (or, convert list to fitted model object)
Dear R Help, I have two nested negative log-likelihood functions that I am optimizing with the spg function [BB package]. I would like to perform model selection on these two objective functions using AIC (and possibly anova() too). However, the spg() function returns a list and I need a fitted model object for AIC(), ICtab() [bbmle package], or anova(). How can I perform AIC-based model
2008 Dec 24
0
merry christmas!
Hallo, "BUON ANNO" "JOYEUX NOEL" "VESELE VANOCE" "MELE KALIKIMAKA" "NODLAG SONA DHUIT" "BLWYDDYN NEWYDD
2011 Jan 27
1
Errors in Integrate
Hello, I have written the function I would like to integrate in two ways: denfxn <- function(yy,vv,a2,b2,mu2) { pp <- 1-pnorm(yy/sqrt(vv)) part1 <- pp^(a2-1) part2 <- (1-pp)^(b2-1) part3 <- dnorm(yy,mu2,sqrt(vv)) return(part1*part2*part3) } denfxnorg <- function(yy,vv,a2,b2,mu2) { pp <- 1-pnorm(yy/sqrt(vv)) pp <- if (pp < .001) .001 else
2007 Oct 23
1
How to avoid the NaN errors in dnbinom?
Hi, The code below is giving me this error message: Error in while (err > eps) { : missing value where TRUE/FALSE needed In addition: Warning messages: 1: In dnbinom(x, size, prob, log) : NaNs produced 2: In dnbinom(x, size, prob, log) : NaNs produced I know from the help files that for dnbinom "Invalid size or prob will result in return value NaN, with a warning", but I am not able
2006 May 21
2
nls & fitting
Dear All, I may look ridiculous, but I am puzzled at the behavior of the nls with a fitting I am currently dealing with. My data are: x N 1 346.4102 145.428256 2 447.2136 169.530634 3 570.0877 144.081627 4 721.1103 106.363316 5 894.4272 130.390552 6 1264.9111 36.727069 7 1788.8544 52.848587 8 2449.4897 25.128742 9 3464.1016 7.531766 10 4472.1360 8.827367 11
2009 Jul 17
6
Solving two nonlinear equations with two knowns
Dear R users, I have two nonlinear equations, f1(x1,x2)=0 and f2(x1,x2)=0. I try to use optim command by minimize f1^2+f2^2 to find x1 and x2. I found the optimal solution changes when I change initial values. How to solve this? BTW, I also try to use grid searching. But I have no information on ranges of x1 and x2, respectively. Any suggestion to solve this question? Thanks, Kate
2003 Dec 20
0
Fw: Re: CAMPANHA NATAL SEM BAIXARIA - PARTICIPE!
----- Mensagem Original -----=20 Eu boicotaria estas empresas s=F3 pelo fato de financiarem os enjoativos e = rancentos Cassetas, mas me surpreendi ao descobrir que tantos produtos que = eu costumo comprar s=E3o transg=EAnicos. Fui conferir no site do greenpeace= e =E9 verdade!!!!!!!!!!!!! Boicote neles! ----- Original Message -----=20 C A M P A N H A=20 N A T A L S E M B A I X A R I A
2005 Nov 09
2
About: Error in FUN(X[[1]], ...) : symbol print-name too long
Hi, I??m trying to use the Win2BUGS package from R and I have a similar problem that reurns with the message: Error in FUN(X[[1]], ...) : symbol print-name too long But, there is no stray ` character in the file ( Sugestions given by: Duncan Temple Lang <duncan> Date: Mon, 26 Sep 2005 07:31:08 -0700 ) The progam in R is: library(R2WinBUGS) library(rbugs) dat <-
2013 Feb 01
2
How does this function print, why is n1 which equals 1 printed as 2?
Windows 7, R 2.12.1 Colleagues, I am trying to understand the n.for.2means function. The code below is a copy of the function (renamed to n.for.2means.js). I have inserted a single line of code towards the bottom of the function which uses the cat function to print the value of n1. You will note the value (preceded by stars) is printed as 1. The function (1) prints a lot of output without any
2007 Mar 06
2
Estimating parameters of 2 phase Coxian using optim
Hi, My name is Laura. I'm a PhD student at Queen's University Belfast and have just started learning R. I was wondering if somebody could help me to see where I am going wrong in my code for estimating the parameters [mu1, mu2, lambda1] of a 2-phase Coxian Distribution. cox2.lik<-function(theta, y){ mu1<-theta[1] mu2<-theta[2] lambda1<-theta[3]