similar to: shelling out to R for one command

I know I should probably RTFM for this question, but could someone tell me if R supports the idea of "viewing source" on any particular function you want to use? If I want to "view source" on the rpois() function, for example, can I do somethink like: source(rpois) To see how the function is implemented? Regards, Paul Meagher Datavore Productions 50 Wood Grove Drive

I would like to ''exec'' an installation script ''onlyif'' an installation directory is empty. I tried using following bash one-liner however it didn''t work: <code> exec{$one_install_script: require => File[$one_install_script], onlyif => "[ \"$(/bin/ls -A $one_location)\" ] && exit 1 || exit 0" }

I am trying to deduce the one liner for an rpm I am packaging to edit a php configuration file from within my spec. The line I am editing looks like: $conf['nagios_base'] = "/nagios/cgi-bin"; What are the escape requirements Perl needs from within the shell to search for this? As I have seen, the syntax is a mess, any pointers would be appreciated! thanks, jlc

every time I read the R release notes for the next release, I see many functions that I had forgotten about and many functions that I never knew existed to begin with. (who knew there were bibtex facilities in R? obviously, everyone except me.) I wonder whether there is a complete list of all R commands (incl the standard packages) somewhere, preferably each with its one-liner AND

----- Original Message ----- From: "Richard A. O'Keefe" <ok at cs.otago.ac.nz> To: <paul at datavore.com> Sent: Thursday, September 04, 2003 2:56 AM Subject: Re: [R] Overlaying graphs > I do not know how to overlay the curve graphic on top of hist graphic. > > Do you know about the "add=TRUE" option for plot()? > > I am hoping to show visually

QuickTime 6 for Windows breaks the VP3 codec quite severely--if you turn on "Safe Mode" (which forces QuickTime to draw through GDI), you'll see a white or black screen instead of video. This is logged as bug #2111990 in Apple's QuickTime feedback system. The fix is a classic one-liner, although it took me a long time to figure it out. :-/ Also attached is a patch to bump the

Hello everyone, I have a dataframe with 1 column and I'd like to replace that column with a moving average. Example: > library('zoo') > mydat <- seq_len(10) > mydat [1] 1 2 3 4 5 6 7 8 9 10 > df <- data.frame("V1" = mydat) > df V1 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10 10 > df[df$V1 <- rollapply(df$V1, 3, mean)]

> On May 18, 2016, at 2:54 AM, Frank Cox <theatre at melvilletheatre.com> wrote: > > Given a list of rpms on one system (rpm -qa > list.txt), is there a one-shot command that I can run on another system to remove all of the rpms not listed and add any that are on the list and not present on the second system? It wouldn?t be a one liner except in the most general sense that you

Peter, thanks, very nice, this will work for me... could you also help with setting up the code to run the on liner "approx(sort(x), seq(0,1,,length(x)), q)$y" on the rows of a data frame using my example above? So if I cbind z and res,? df<-cbind(z,res) the "x" in your one liner would be the first 4 column values of each row and "q" is the last (5fth) column

Given a list of rpms on one system (rpm -qa > list.txt), is there a one-shot command that I can run on another system to remove all of the rpms not listed and add any that are on the list and not present on the second system? -- MELVILLE THEATRE ~ Real D 3D Digital Cinema ~ www.melvilletheatre.com

input: http://pastebin.com/raw.php?i=MqPXZwc3 output: http://pastebin.com/raw.php?i=8QCkp4yv it will be a long day.. :D could someone please help with it? i have to make a "one liner" that get's the input, and gives the mentioned output.

Trying to avoid a perl script which wouldn't be hard, but I am looking for an awk one liner that does a replacement, but only after it sees a key word on some line. Anyone know of that's easy to do? Thanks! jlc

Peter, thanks, very nice, this will work for me... could you also help with setting up the code to run the on liner "approx(sort(x), seq(0,1,,length(x)), q)$y" on the rows of a data frame using my example above? So if I cbind z and res, df<-cbind(z,res) the "x" in your one liner would be the first 4 column values of each row and "q" is the last (5fth) column

Hi Tena, I recommend rapache for building websites with R. See http://biostat.mc.vanderbilt.edu/rapache/ -Ista > ---------- Forwarded message ---------- > From: "Tena Sakai" <tsakai at gallo.ucsf.edu> > To: <ted.harding at manchester.ac.uk>, <r-help at r-project.org> > Date: Tue, 28 Apr 2009 15:04:53 -0700 > Subject: Re: [R] Newbie R question PART2 >

?s 21:05 de 11/06/2023, javad bayat escreveu: > Dear R users; > I am trying to fill a column based on a specific value in another column of > a dataframe, but it seems there is a problem with the codes! > The "Layer" and the "LU" are two different columns of the dataframe. > How can I fix this? > Sincerely > > > for (i in 1:nrow(data2$Layer)){ >

Maybe this is common knowledge, I don''t know. I figured I''d post it, hopefully it can help some people. If anyone has a better way, please share. http://jrhicks.net/120 (not my blog, I''m Mike in the comments I couldn''t get it to literally run the test in the identical way as rails does when you type rake. However, I could get it to run an individual

Hello, I am looking for an elegant one-liner for the following operation: x <- rnorm(10) y <- runif(10) c(mean(x)-mean(y), mean(x)+mean(y)) I thought about apply(data.frame(x, y), 2, mean) but I don't know how to apply the +- operation on the result of apply. Thanks, *S* -- Sascha Vieweg, saschaview at gmail.com

Dear Rui; Many thanks for your email. I used one of your codes, "data2$LU[which(data2$Layer == "Level 12")] <- "Park"", and it works correctly for me. Actually I need to expand the codes so as to consider all "Levels" in the "Layer" column. There are more than hundred levels in the Layer column. If I use your provided code, I have to write it

Dear All, Probably a one liner, but I am banging my head against the floor. Consider the following DF <- data.frame( x=1:10, y=10:1, z=rep(5,10), a=11:20 ) mn<-names(DF) but then I cannot retrieve a column by doing e.g, DF$mn[2] I tried to play with the quotes and so on, but so far with no avail. Any suggestion is welcome. Cheers Lorenzo

Hey guys, Looking through my book and the web and I am not having any success returning data from a search. I need to have awk search for a string and print the first field which is no problem but now its returning two options as the input data has changed. The change is reliable, I only want the first field if it ends in a regex that I have, and I only want what that regex matches to be printed.