similar to: snip.rpart with R 1.6.0

Displaying 20 results from an estimated 5000 matches similar to: "snip.rpart with R 1.6.0"

2002 Oct 30
1
snip.rpart with R 1.6.0, problem solved
Hi Thank you very much for your help. My problem is exactly this one: "I think he may mean that the visual deletion in snip.rpart.mouse is not working. It only works if the background colour is opaque, which is not the default on e.g. x11() in either system." But now I don't know how to set the background to OPAQUE? Because in R 1.5.1 I didn't have to do this...
2006 Oct 27
3
Suppress blanks/spaces in character
Hi all I'm have a character vector and would like to suppress the blanks if there are more than one after the other. Example: Character value is: "abc def ghi" The result should be: "abc def ghi" I know that it's possible to delete the leading blanks with the command "trim". But how can I delete blanks within a character? Thank you very much in
2004 May 05
4
Analysis of ordinal categorical data
Hi I would like to analyse an ordinal categorical variable. I know how I can analyse a nominal categorical variable (with multinom or if there are only two levels with glm). Does somebody know which command I need in R to analyse an ordinal categorical variable? I want to describe the variable y with the variables x1,x2,x3 and x4. So my model looks like: y ~ x1+x2+x3+x4. y: ordinal factor
2004 Apr 23
4
Tcl Tk table
Hi I've a problem with the following example: library(tcltk) .Tcl("array unset tclArray") myRarray <- matrix(1:1000, ncol=20) for (i in (0:49)) for (j in (0:19)) .Tcl(paste("set tclArray(",i,",",j,") ",myRarray[i+1,j+1],sep="")) tt<-tktoplevel() table1 <- tkwidget(tt,"table",variable="tclArray",
2006 Jun 29
1
RCOM Package
Hi list, I just installed the rcom package and tried to read/give out some values from/to Excel. Altogether it works great... but nevertheless I don't know how the syntax works or in other words: "Which command needs which parameters?" Is there somwhere a manual about this package with good examples? I've read the Package description... but there are not really good
2006 Sep 25
2
rpart
Dear r-help-list: If I use the rpart method like cfit<-rpart(y~.,data=data,...), what kind of tree is stored in cfit? Is it right that this tree is not pruned at all, that it is the full tree? If so, it's up to me to choose a subtree by using the printcp method. In the technical report from Atkinson and Therneau "An Introduction to recursive partitioning using the rpart
2008 Jul 22
2
rpart$where and predict.rpart
Hello there. I have fitted a rpart model. > rpartModel <- rpart(y~., data=data.frame(y=y,x=x),method="class", ....) and can use rpart$where to find out the terminal nodes that each observations belongs. Now, I have a set of new data and used predict.rpart which seems to give only the predicted value with no information similar to rpart$where. May I know how
2009 Jun 09
3
rpart - the xval argument in rpart.control and in xpred.rpart
Dear R users, I'm working with the rpart package and want to evaluate the performance of user defined split functions. I have some problems in understanding the meaning of the xval argument in the two functions rpart.control and xpred.rpart. In the former it is defined as the number of cross-validations while in the latter it is defined as the number of cross-validation groups. If I am
2018 Aug 14
2
Xenial rpart package on CRAN built with wrong R version?
Hello, I just upgraded my Ubuntu Xenial system to R 3.5.1 (from 3.4.?) by changing the sources.list entry and doing an "apt-get dist-upgrade". Everything works except loading the rpart package in R: > library(rpart) Error: package or namespace load failed for ?rpart?: package ?rpart? was installed by an R version with different internals; it needs to be reinstalled for use with
2004 May 13
2
R 1.9.0 and pred.rpart
I have just upgraded from R 1.7.3 to R 1.9.0 and have found that the predict function no longer works for rpart: > predict(hmmm,sim3[1:10,]) Error in predict.rpart(hmmm, sim3[1:10, ]) : couldn't find function "pred.rpart" I have re-installed the rpart package to no avail. Any ideas? Giles Hooker
2011 Sep 07
2
rpart/tree issue
I am trying to create a classification tree using either tree or rpart but when it comes to plotting the results the formatting I get is different than what I see in all the tutorials. What I would like to see is the XX/XX format but all I get is a weird decimal value. I was also wondering how you know which is yes and which is no in each leaf of the tree? Is yes always on the left?
2011 Aug 25
2
rpart: plot without scientific notation
While I'm very pleased with the results I get with rpart and rpart.plot, I would like to change the scientific notation of the dependent variable in the plots into integers. Right now all my 5 or more digit numbers are displayed using scientific notation. I managed to find this: http://tolstoy.newcastle.edu.au/R/e8/help/09/12/8423.html but I do not fully understand what to change, and to
2014 Aug 13
1
Request to review a patch for rpart
Dear list For my work, it would be helpful if rpart worked seamlessly with an empty model: library(rpart); rpart(formula=y~0, data=data.frame(y=factor(1:10))) Currently, an unrelated error (originating from na.rpart) is thrown. At some point in the near future, I'd like to release a package to CRAN which uses rpart and relies on that functionality. I have prepared a patch (minor
2007 Feb 15
2
Does rpart package have some requirements on the original data set?
Hi, I am currently studying Decision Trees by using rpart package in R. I artificially created a data set which includes the dependant variable (y) and a few independent variables (x1, x2...). The dependant variable y only comprises 0 and 1. 90% of y are 1 and 10% of y are 0. When I apply rpart to it, there is no splitting at all. I am wondering whether this is because of the
2006 Aug 09
2
How to draw the decision boundaries for LDA and Rpart object
Hello useR, Could you please tell me how to draw the decision boundaries in a scatterplot of the original data for a LDA or Rpart object. For example: > library(rpart) >fit.rpart <- rpart(as.factor(group.id)~., data=data.frame(Data) ) How can I draw the cutting lines on the orignial Data? Or is there any built in functions that can read the rpart object 'fit.rpart' to do
2001 Aug 12
2
rpart 3.1.0 bug?
I just updated rpart to the latest version (3.1.0). There are a number of changes between this and previous versions, and some of the code I've been using with earlier versions (e.g. 3.0.2) no longer work. Here is a simple illustration of a problem I'm having with xpred.rpart. iris.test.rpart<-rpart(iris$Species~., data=iris[,1:4], parms=list(prior=c(0.5,0.25, 0.25))) + ) >
2003 Aug 15
3
How to reinstall rpart?
After entering ?library(rpart)?, I tried to plot an existing rpart tree, and got this error message: Error: couldn't find function "plot.rpart". However, ??plot.rpart? does bring up the help for the function. The same things occur for text.rpart, although print(my.tree) does work. So, I tried to re-install rpart using Packages | Install from CRAN, but then I get this
2011 Apr 08
4
Rpart decision tree
Dear useRs: I try to plot an rpart object but cannot get a nice tree structure plot. I am using plot.rpart and text.rpart (please see below) but the branches that connect the nodes overlap the text in the ellipses and rectangles. Is there a way to get a clean nice tree plot (as in the Rpart Mayo report)? I work under Windows and use R2.11.1 with rpart version 3.1-46. Thank you. Tudor ...
2012 Jul 06
2
Plotting rpart trees with long list of class members
I have a class with 732 members, so using rpart.plot is giving me a tiny plot in the middle of the window. Is there a good way to modify the plot, or replace the long list with something like "group1"? -- View this message in context: http://r.789695.n4.nabble.com/Plotting-rpart-trees-with-long-list-of-class-members-tp4635671.html Sent from the R help mailing list archive at
2010 Dec 13
2
rpart.object help
Hi, Suppose i have generated an object using the following : fit <- rpart(Kyphosis ~ Age + Number + Start, data=kyphosis) And when i print fit, i get the following : n= 81 node), split, n, loss, yval, (yprob) * denotes terminal node 1) root 81 17 absent (0.7901235 0.2098765) 2) Start>=8.5 62 6 absent (0.9032258 0.0967742) 4) Start>=14.5 29 0 absent (1.0000000